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by: Grace Gibson

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# Physics Test Four study Guide 2070

Marketplace > Clemson University > Physics 2 > 2070 > Physics Test Four study Guide
Grace Gibson
Clemson
GPA 3.88

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This is from lecture but honestly you need to work problems to get an A on the test, not study a study guide.
COURSE
General Physics 1
PROF.
Dr. Puneet
TYPE
Study Guide
PAGES
1
WORDS
KARMA
50 ?

## Popular in Physics 2

This 1 page Study Guide was uploaded by Grace Gibson on Thursday April 7, 2016. The Study Guide belongs to 2070 at Clemson University taught by Dr. Puneet in Fall 2016. Since its upload, it has received 22 views. For similar materials see General Physics 1 in Physics 2 at Clemson University.

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Date Created: 04/07/16
Physics Test Four    Chapter Eleven  ● Static Equilibrium   ○ The resultant external force is zero  ○ The external torque around any axis is zero  ● First condition implies that a = 0  ● Second condition implies that alpha = 0  ● We can choose our axis of rotation to be wherever we want  ● When you have a fulcrum you have to consider the position of the fulcrum  ● Angular momentum = L = Iw = rmv = rp  ● Torque is the change in angular momentum    Chapter Twelve  ● G = Gravitational constant = 6.67 x 10^­11  ● Law of universal gravitation says F = force acting between any two objects = Gm1m2/r^2  ○ R is the distance between the two centers of mass  ● Gravitational force is a vector and a force exists between any two massive particles  ● Inverse square law = force is inversely proportional to radius  ● So as the distance between two particles increase, the gravitational force will decrease  ● Since G is really small, the objects have to be really massive for the gravitational force to  not be negligible   ● Principle of superposition: net force is the vector sum of the individual forces  ● Force between any object on the surface of the earth = F = mg = m (GMearth/(r of  earth)^2  ● Kepler’s three laws of planetary motion  ○ Each planet moves in an elliptical orbit with the sun at one focus  ○ The line from the sun to any planet sweeps out equal areas at equal time  intervals  ○ For each planet, the square of the period is proportional to the cube of the  average radius   ● K = 2.9 x 10^­19   ○ This is for all planets  ○ This does not involve the orbiting object  ● Anything moving in a circle in constant velocity has centripetal force  ● Geosynchronous satellite: orbit around the earth is 24 hours  ● GPS satellites are 12 hours, twice the speed of geosynchronous satellites

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