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MSU / Engineering and Tech / Eng 202 / What is the difference between kinematics and kinetics?

# What is the difference between kinematics and kinetics? Description

##### Description: Velocity, acceleration, and frame of reference for particles Velocity and acceleration as a function of time, velocity, as a position, and as a constant Examples using equations
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## What is difference between kinematics and kinetics?

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EGEN 202-| Introduction

Dynamics statics : [ F = Õ EN= 0

1/15/16 dynamics EF = mã EM TO tructure of course: 2D 3D particles - mass concentrated at point rigid body - distributed mass, non deformable

## How do you design a course structure?

tudy SO

Kinematics - geometry of motion

position, velocity, acceleration kinetics - forces resulting in motion

force, mass, acceleration means of work, energy We also discuss several other topics like What is the basic structure and function of a neuron?

Solving problems impulse, momentum

PARTICLES O kinematics - geometry of motion

position, velocity, aceleration

## What is the formula for acceleration?

- path of motion Ft +At)

TH) : position vector

*F

1.1) velocity = derivative of position

dot notation - Vt)- O E = ŕ * der of r wi respect to t - as It becomes small, of is small, V(t) is tangent to path We also discuss several other topics like What is the difference between divergent and convergent boundaries?

1.2) acceleration = denvative of velocity

u dv lim act) = lott o

(t+at) - ulty

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frame of reference both velocity and

and coordinate system acceleration are based on frame of ref. If you want to learn more check out What is the movement of substances against the concentration gradient called?

Velocity of frisbee on airplane is

different from velocity from earth frame of reference is what we pick as baseline Coordinate Systent is a specific coordinate in reference frame Don't forget about the age old question of What is the theory of functionalism?

note a point has the same relocity and acceleration

relative to any point in a reference frame

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ID motion - rectilinear | straight line mohon

- ID we don't need vectors, just scalars

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2.1) velocity and acceleration

as S: scalar position

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p

v= 0 dt . que - ate

2,7) types of problems in rechlinear problems If you want to learn more check out Locational excellence refers to what?

acceleration as a function of time

acceleration is constant (ex free fall) 3 acceleration as a function of velocity (ex: wind resistance) © acceleration as a function of position (ex gravity, magnetism)

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dnia.1) acceperation function of time

relocity alt) – dt > Stact) = Sw.dv

> V(t) = V. + St, alt) at position v(t)- e Stivít) dt - Ss. as Don't forget about the age old question of What is the definition of compounds?

→ 5(t) = 50+ St. Vit) dt

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2.2.2) acceleration as a constant (gravity)

velocity alt) at

(t) = ao lt-to) + Va position (t) = at

>\$(t) = á alt-to)? + Vo (t-tolts. velocity as function of position

als) - a - e vents – Sé, als) ds = Srivoli

→ v2 = V * 29.(5-50)

2.2.3) acceleration funcHon of velocity (wind/drag)

a(v) = at St. at = Sv. avj av integrate, solve for V(t)

a(v) will be an actual equation to integrate.

position as function of time . - r(t) = as/at St. Vit) dt = Js. as

- integrate, solve for s(t) velocity as function of position

a(v) = dv - as t = vas

f. ds = Sv. atvj velv

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1/20/16 2.2.4) acceleration as function of position a(s) = ax = a b as a = v au

> Ss. ds = Svo v dv

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Examples

1 GIVEN Missie launched at 100g for 3 sec.

After 3 sec; acier is -49 (gravity and drag)

g= 9.81 m/s2 FIND: How long until it reaches 15 km SOLN aut 235 5.0 Vo=0 a= 100g to =0

S = at2 + vt + E S(3) = (100)(9.81)(3)2 = 4414.5m

v=a(t-to) V(3) = (10079.81)(3-0) - 2943 mis

tusses a = - 49 Vo so

s = that + Vot to 15km 15000 m 15000 = á (-479.01)(+) + 2943 (t) + 4414.5

calculator! t = 3.695 (Ub) or t=146.3 sec (down)

(tto -3sec) 1 t = 6.69 sec)

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@ GIVEN: muss released from rest

both springs unstretched als) = 32.2 -50 s (fls2)

gravity Spring constant FIND how far does the mass fall?

What is the max Velocity? SOLN: als) - ante e ventos

Soa(s) ds = Ivozo v dv 2 v2 = So als) ds = 32 as - 2552/

12 = 64.45 - 5052 maximum position when v=0

0 = 464.45 -5052

(5= 1,280 ft

maximum relocity when a co

915) = 32.-505 = 0

g= 0.644 ft V(s) = +64.45-5052

(1644) = 4 . 55 ft/s

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1120116

3 GIVEN Pocket sled wl water breaks that slow after time

acce @ a(t) = 30 +2t (m/s) until V=400 ms

decei @ alv)= -.003 v2 (m/s2) unti v= 100mls FIND : total distance Haveled SOLN: unhl breaks apply

alt) = 30 + 2+ = au ve

s 30 + at dt =s av vít) < 30+ + + +y2 400 = 30t + t = 10sec

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after breaks. apply s(t) = \$50+ Soovit) at s(t) = 15+? +Śt lie

5(10) = 1833 m

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