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PHYS 207: Exam #1 Study Guide

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by: Eren Sakarcan

PHYS 207: Exam #1 Study Guide PHYS 2070-001

Marketplace > Clemson University > Physics 2 > PHYS 2070-001 > PHYS 207 Exam 1 Study Guide
Eren Sakarcan
GPA 3.25

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About this Document

Study guide reviewing the key points of the lecture notes in addition to a document containing all the word problems from lecture and their answers
General Physics I
Pooja Puneet
Study Guide
Physics, General Physics, Physics Without Calculus, Gen Phys, PHYS 207
50 ?




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This 24 page Study Guide was uploaded by Eren Sakarcan on Thursday January 28, 2016. The Study Guide belongs to PHYS 2070-001 at Clemson University taught by Pooja Puneet in Spring 2016. Since its upload, it has received 218 views. For similar materials see General Physics I in Physics 2 at Clemson University.


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Date Created: 01/28/16
Eren Sakarcan PHYS 2070—Exam #1 Study Guide Practice Problems Chapters 1-4 Chapter 1: Introduction to Physics (SI Units, Significant Figures, Drawing Vectors): 1. What is the number of significant figures in 0.0052? A. One B. Two C. Three D. Four E. Five
 2. What is the number of significant figures in 4.321 x 10 ? -10 A. One B. Two C. Three D. Four E. Five
 3. What is the number of significant figures in 0.0430? A. One B. Two C. Three D. Four E. Five
 4. A tortoise travels at 2.51 cm/s for 12.23 seconds. How far does the tortoise travel?
 5. Michael, an exchange student from France, is studying in the US. He wishes to buy a new pair of jeans, but all the sizes are in inches. He does remember that 1 m. = 3.28 ft., and that 1 ft. = 12 in. If his waist size is 82 cm., what is his waist size in inches?
 Chapter 2: One-Dimensional Kinematics: 1. Sophie is as position X = 23 m. She then undergoes a displacement ΔX = -50 m. from this point. What is her position? A. 27 m. B. -27 m. C. 73 m. D. -73 m. E. Cannot be determined 
 2 2. Equation of Motion: A drag racer starts from rest and accelerates 7.40 m/s . How far has the racer traveled in 2.00 seconds?
 3. Equations of Motion: A park ranger is driving on a road and sees a deer standing frozen in the middle of the road. The ranger, driving at 11.4 m/s, immediately applies the brakes and slows with an acceleration of 3.80 m/s . If the deer is 20.0 m. from the ranger’s vehicle when the brakes are applied, (A) how close does the ranger clem to hitting the deer? (B) How much time is needed to stop?
 4. Equations of2Motion: At the start of a race, a horse accelerates out of the gate at a rate of 3.00 m/s . How long does it take the horse to cover the first 25.0 m. of the race? A. 16.7 s. B. 4.08 s. C. 4.5 m. 12.2 s.
 5. Equations of Motion: A ball is thrown upwards in the air with a speed of 2 m/s at an initial height of 1 m. (A) how much time does it take the ball to reach its maximum height? (B) what is the maximum height the ball will reach? 
 6. Equations of Motion: A heavy rock (at rest) is dropped from the top of a cliff and it falls 100 m. before hitting the ground. How long does the rock take to fall to the ground? A. 44 m. B. 44 m/s C. 4.5 s. D. 20 s.
 7. Equations of Motion: A police car stopped at a set of lights has a speeder pass it at a constant speed of 28 m/s. If the police car can accelerate at 3.6 m/s , (A) How long would it 2 take to catch the speeder? (B) How far would the police car have to go before it caught the speeder? (C) What would its speed be when it caught up with the speeder, and is this speed reasonable?
 8. Equations of Motion: A motor boat traveling 5 m/s east encounters a current moving 2.5 m/ s north. (A) what is the resultant velocity of the motor boat? If the width of the river is 80 meters wide, how much time does the boat take to travel to shore? (C) What distance downstream does the boat reach at the opposite shore? 
 9. Equations of Motion: If a Jeep brakes to a stop from 70 mph to 0 mph in 186 feet, what is its acceleration? 
 10. Equations of Motion: A ball is tossed straight up with a velocity of + 20 m/s. How high does the rock reach? 
 Chapter 3: Vectors 1. Find the x- and y-components of the given vector r that has a magnitude of 10 m. and is making a 30° angle with the horizontal (x-axis). 
 2. What are the x- and y-components of this vector? A. 3, -4 B. 4, 3 C. -3, 4 D. 4, -3 E. -3, -4
 3. You are following directions to the beach from your hotel listed as follows: 2.8 miles (4.5km) Northeast; 1.25 miles (2.0 km) 30° West of North. How far and in what direction have you traveled from the starting point? 
 4. Given the A = (4, 2) and B = (4, 3), find the magnitude of C = 2A+B A. 19 B. SQRT: 193 C. (12, 7) D. SQRT: 138
 Chapter 4: Two-Dimensional Kinematics 1. A golfer hits a ball with an initial speed of 30.00 m/s at an angle of 50° above the horizontal. What is the range of the ball?
 2. A golfer hits a ball with an initial speed of 30.00 m/s. What is the maximum range of the ball?
 3. A projectile is launched from the ground at an angle of 30°. At what point in its trajectory does this projectile have the least speed? A. Just after it is launched B. At the highest point in its flight C. Just before it hits the ground D. Halfway between the ground and the highest point E. Speed is always constant
 4. What is the x-component of velocity V at the indicated (x) position? A. V ios(θ) - gt B. V ios(θ) + gt C. V ios(θ) D. V iin(θ) E. V iin(θ) + gt 
 5. What is the x-component of velocity V at the indicated (y) position? A. V iin(θ) - gt B. V ios(θ) + gt C. V ios(θ) D. V iin(θ) E. V iin(θ) + gt 
 6. A basketball is thrown at an initial speed of 4.3 m/s at an angle of 15° above the horizontal for a bounce-pass. If the ball is released 0.80 m above the floor, (A) how high does the ball reach? (B) How long does it take for the ball to reach this height? 
 7. Suppose a stuntman drives a car off a 10-meter-high cliff at a speed of 20 m/s. How far does the car land from the base of the cliff?
 8. A golfer hits a ball with an initial speed of 30.00 m/s at an angle of 50° above the horizontal. The ball lands on a green that is 5.00 m above the level where the ball was struck. (A) How long was the ball in the air? (B) How far has the ball traveled in the horizontal direction when it lands? (C) What are the speed and direction of the ball just before it lands?
 9. An archerfish squirts water with an initial speed of 2.30 m/s at an angle of 19.5° above the horizontal. The stream of water hits a beetle on a leaf at a height h above the water’s surface, moving horizontally. (A) How much time does the beetle have to react before it is hit with the water? (B) What is the height, h of the beetle? (C) What is the horizontal distance between the fish and the beetle when the water is launched?
 10. A person playing darts throws a dart towards the bulls eye located 8.00 ft (2.44 m) away. If the velocity of the dart leaving the person’s hands parallel to the floor is 5.00 m/s, how far below the bulls eye will it hit the target? 
 11. A car traveling at 100 mph leaves the deck of an aircraft carrier that is 100 m above the surface of the ocean. How long before the car plunges into the ocean?
 Answer Key
 Chapter 1: Introduction to Physics: 1. (B)—Two
 2. (D)—Four
 3. 4. Distance = (Velocity) x (Time) = (2.51 cm/s)(12.23 s) = 30.6973 = 30.7 (with significant figures)—Needs three significant figures because the number in the problem with the least amount of significant figures is 2.51, which has (3), meaning the solution must also have (3) significant figures. 
 5. Conversion Factor: 1 m. = 3.28 in. 
 Convert to Meters: (82 cm) x (1 m./100 cm) 
 Convert to Feet: (82 cm) x (1 m/100 cm) x (3.28 ft/1 m)
 Convert Feet to Inches: (82 cm) x (1 m/100 cm) x (3.28 ft/1 m) x (12 in/1 ft) 
 = 32 inches Chapter 2: One-Dimensional Kinematics: 1. (B)— -27 m
 2. Use the motion equation relating position and time in terms of acceleration: 
 a = 7.40 m/s 
 2 2
 X f X + i t + i.5at V i 0 m/s, V = Unkfown
 X f 0 + 0 + 0.5(7.40 m/s )(2) 
 2 2 T i 0 seconds, T = 2 secofds
 X f 0.5(7.40 m/s x 4)
 2 X i 0 m, X = Unkfown 
 X f 14.8 m. 
 2 2 3. ΔX = V fV i 
 Distance Between the Deer and Car: 
 2a 20.0 m -17.1 m = 2.9 m
 2 ΔX = −V i 
 Time Needed to Stop:
 2a 2 ΔX = (11.4m / s) 
 V f V + it (−3.80m / s )2 t = -V /i = (- 11.4 m/s)/(-3.80 m/s ) = 3.00 s. ΔX = 17.1 m
 V fV i 4. a = , solve for (t). 
 t Substitute remaining expression into position vs. time equation of motion 
 1 2 X f X +Vti+ at i 2 
 5. Y i 1 m
 V f V + it
 Y f Y +Vit + 0.5at 2
 0 = V - gt
 2 V i 2 m/s, V = 0 mfs
 i Y f 1 + (2 m/s x 0.2) - 0.5(9.8 m/s ) x g = 9.80 m/s 2 t = V/i
 (0.2) 2
 = (2 m/s)/(9.80 m/s )
 2 t = Unknown 
 Y f 1.20 m Y f Unknown 
 = 0.2 seconds 6. (C)—4.5 seconds
 Y f Y +it + 0.5at Yi = 0, Yf = -100 m
 -100 m = 0.5(-9.8 m/s )t 2 2
 Vi = 0 m/s
 2 t = SQRT:[(200 m)/(9.8 m/s )]
 a = -g
 t ≅ 4.5 s ΔY = -100 m
 t = Unknown
 7. V Speeder = 28 m/s, V Police-i= 0 m/s
 X S V t
 S a = 0 m/s , a = 3.6 m/s 2
 X P X + VPi 0.5aPi p 2
 Speeder Police 2 X Police = X Speeder , X Speeder-i = 0 = X Police-i
 X P 0 + 0 + 0.5a t p 
 t= (2V )/Sa ) =p(56 m/s)/(3.6 m/s )
 t = 15.6 s 
 V PfV + a Pi p X P0.5a t p 2
V Pf = 0 +(3.6 m/s )(15.6 s)
 X P0.5(3.6 m/s )(15.6 s) 2
 V Pf = 56.2 m/s
 X P28.08 m 
 8. V = SQRT: V + V 
 x2 y2 2
 2 2 X f X +Vit + 0.5a t x Y f Y +Vit + 0.5a t y V = SQRT: [(5 m/s) + (2.5 m/s) ]
 t = x/v = (80 m)/(5 m/s)
 d = vt = 2.5(16 s) 
 V = 5.59 m/s
 t = 16 s d = 40 m 9. Convert the V and Δi to SI Units: 
 V i (70 mph) x (1.61 km/h) x (1,000 m/km) x (h/3,600 s) = 31.3 m/s
 X f X = i186 ft) x (0.305 m/ft) = 56.7 m (ΔX)
 V f2 = V +i2aΔX
 2 0 = (31.2 m/s) + 2a(56.7 m)
 a = -(979.7 m /s )/(113.4 m)
 a = -8.64 m/s V = + 20 m/s V f V + 2aiY
 10. i 
 2 2 a = g = -9.8 m/s 2
 0 = (20 m/s) + 2(-9.8 m/s )(Y-0)
 f V = 0 at maximum height 
 Y f [(20 m/s) ]/(2 x -9.8 m/s )
 2 f Yi = 0, Y = fnknown
 Y f 1.02 m 
 Chapter 3: Vectors 1. 
 2. (A)—(3, -4) 3. 
 4. SQRT: (193) 
 Chapter 4: Two-Dimensional Kinematics: 1. 
 3. (B)—At it’s highest point in its flight 4. (C)— V Cos(θ) i 5. (A)—V Sin(θ) - gt i 6. 


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