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CU / Chemistry / CHB 1133 / How to achieve the correct acid/base ratio?

How to achieve the correct acid/base ratio?

How to achieve the correct acid/base ratio?

Description

School: University of Colorado
Department: Chemistry
Course: General Chemistry II
Professor: Susan hendrickson
Term: Spring 2016
Tags: Gen. Chem 2
Cost: 25
Name: Week 4 - Gen. Chem 2
Description: These notes cover the last bit of material for Week 4 before Exam 1.
Uploaded: 02/06/2016
2 Pages 47 Views 2 Unlocks
Reviews


& Havmany grams of NaC H2O must be added to 100 me of .15MH (H2O2


How to achieve the correct acid/base ratio?



to get a pH 4.44 buffer? 1) Find moles of acid ... leler. 15 M) = .015 mol HC2H2O2 2) Pluginto H H equation ... 4.44= 4.74 + log x=.0075 mol 3) convert to grams..... 0075 ml NaC2H2O2 x 829 -1.0615 q NaleH302


How to use the direct method?



We also discuss several other topics like What is edvard munch's known painting?

mol

Base

How to achieve the correct Acid Ratio

n es in th O Direct Method -- add the exact amounts of acid and conjugate baserwis

2) Indirect Boxe Achi patnya beqin my weak acid add strong base until enough acid converted to conjugate base you can entity molos otectes cas. (.) ALEM) .015 mol


How to use the indirect method?



HA + OH - A Hoa 4.74+ logos- If you want to learn more check out Who comes to the shepherds to order them to travel to bethlehem?

2001

THEM)015 mol

2015

at 5. Bx

Plug inta # -# envention (x = mol strong bose needed 5.0 x 2.0075... os mora ndirect Acid Addition to begin of weak base + add strong acid until enough base converted to conjugate acid A+ Hyöt -HATH, O

Find moles of base... (.12)6.1510) 5015 mol nät 2 H2O2

(реры, рэв био је још як) и чрк » Н-н арылт боја () . Т. 9 х Don't forget about the age old question of What is the difference between a theory and a theorem?

X- | X-10

о

4.44-4.74 + laq (015-x

E.015xl o

f

studySoup

BUFFER EXAMPLES What is pH of butter prepared by adding 15 ml of oolM HCl to 40mL of . ISM NH3 solution? pk of NH3-4.74

NH3 + H+ NH4+ NHa) (40 m.) (.15 M) = 6.0mmol pha=14-4.74 16 mmol 1.5 mmolo Don't forget about the age old question of What are perpendicular lines?
We also discuss several other topics like What is a legally recognized union between two people in which they unite sexually?

(15 mL) (IM) = 1.5 mmol

Ka=9.26

-1.5 -1.5 +15. If you want to learn more check out What is the imposed by the sedition act?

never put the pkp in the equation!

El 4.5

14.

5mmal

O 1.5 pH=9.26 + log

it simply shows that NHy is a base

1 1.5 mmol

1 pH=9.74 J

nas

OUP

A+vse

1

* cannot use H-H

equation unless similar

quantities of acid/base...

Helt base is 0 90

What is pt of solution prepared by adding 70 mL of 1 HCl to 40 mL of 15 M NH 3 solution? pk = 4.74

What Niva (NH3) (60m2) ( 15 M) - 6.0 mmol VIDA Find pH this 6 .00 7.0

(H) (70 mc) ( . 1 M.) = 7.0 inmol Find [Ita ut Hequation

(-6.0 16.0 16.0

Immula torovaire ?

1.0 16.0

40+ TUML 110

you don't always subtract the aid! quantite you subtract the limiting reactant...

-log(.0091 M) = 12.04pH ]

in this case, it is not the strong acid additive!

AVALA

actant...

not a butter &

* only weak acids howe

Ka valves! *

-Titrant

strong acid/bascof

known concentration (needs to be strong to know it

goes to completion)

One must

be acid, one

base

TITRATIONS

Analyte

strong/ weak acid or base

* Titrant is added to analyte to determine the conuentration of the analyte solution.

of unknown concentration

(1) 50 ml of NaOH (analyte) was titrated if 15.26 mL of . I HRI (titrant). What is [NuOH]?

* Equivalence Point / Erd Paint

1) Carenake mood swans... (15.26 mb) (1M) = 1.526 mmol HCl

the number of males of titrant analyte

are the same!

slechinodry te entrale mmel of fayld..... HCI + NAOH → H20+ Nall 1.526 mnd HCI & limmal NaOH = 1.526 mmol Naolt Immo NAOH

* If stochiometry is 1:1,

3) Cala Molenciyle... 1.Szo mmol NaOH -1.03052 M NAOH

Hava = M, V+

somb TYPES of ACID-BASE TITRATIONS O Strong Acid to dissociates 100%.; pH--109[H204]

Strong Buse to dissociates 100% ; poft = -1og [OH-] Weak Aud to partial dissociation; USC CHA), ICE diagram and Ka weak Base + partial dissociation; us [n-J. 1E diagram, and Ky Buffer calculate equilibrium mmol/M of HA+A; use W-4 equation to calculate pH

ano

@StudySoup

dnosas

Ex) Zome of .25M HF (PKG = 317) with at M NaOH.

& Eguvalent volume of titrant... Vea = (20 mL HF) (.25 mmol HELImmol NaOH Im NaOH)

= 50mL NAOH

I mL HF

2 what is pH before any titant added?...

mmol HE olmmal NaOH !

Vitane OmL * HF is only a weak aridu

* HF is only a weak acid when by itself!

titant V total = 20 mL + Ome HF + H2O + H2ot ka=6.76610-4 HF

- log (60127) = 1.89

NOOH

LOIO

"ICE table just w analyte and wider.

0127MH + JPH = 1.89

2.5

Study Soup

3) pt at 25 mL of titranti (midpoint

titrant = 25 mL

when you mix solutions together, you have to consider moles/mmol.& AF) ZOMLX.25 M=5 mmol HF HF + OH - F + H2O

5 mmol 2.5 mmollo

NASH) 25 mLx. IM2 2.5mmal OH

- 2.5

+ 2.5

2.5

2.5 mm

45

V total = 20mL + 25 mL

HF NOCH

1

7.5

vse molanty when ICE table is

notabuter!!

-5

5mmal 70m2.0714

-

5.

*

**

pH - 3,17+10913) -H- 3.17 *pH=pka at the midpoint of tittation 4) pH at 50 mL of futuant lequivalence point) HF+OH +H20 F+H205#F+0# Rp 1.5 x10"

5510

Vritrant - 50 ml

-4714 ZIO 10

total= 20 mL & SomL 70 mL

Loos 1 0714 x

HF NOOR

(20 m2) (25) - 5 mmol F

•15+ ICE = arałyle+ tirant is buffer

(sumi)(-) NACH

- Zna ICE switch reactants/prodveta ble not a bute

No longer a butter. Only weak base solution So do artikel table.

= 1.5*10-11

x = 1.03 x 10-6

TpH=8.011

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