Math test two Study guide
Math test two Study guide MATH 1101
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This 2 page Study Guide was uploaded by Rukeem Collins on Sunday February 21, 2016. The Study Guide belongs to MATH 1101 at Georgia State University taught by Changyong Zhong in Winter 2016. Since its upload, it has received 80 views. For similar materials see INTRO TO MATHEMATICAL MODELING in Geography at Georgia State University.
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Date Created: 02/21/16
Quadratic functions 2 Quadratic functions are functions that are expressed as F(x) =ax +bx +c EX: 2x +3x+1 A cannot be zero, and a, b, and c have to be real numbers. The domain is all real numbers, and the range is dependent on the leading coefficient. If the leading coefficient is positive, then the range is everything more than the minimum, if the coefficient is negative then the range is everything below the maximum. The graph of a quadratic function is a U shape, called a parabola. If the leading coefficient is positive, the graph opens, or concaves up. If it is negative it opens, or concaves down. To find the vertex of a quadratic function, you use the equation – ???? to find the x value of the 2???? 4????????−???? 2 vertex, which is also your axis of symmetry, and the equation 4???? (there is a four in both the numerator and denominator. Those are NOT 2 as) to find the y value of the equation, which is also the minimum, or maximum of the function. The larger the absolute value of a is, the wider the graph will be. Increasing/decreasing intervals are the values in which a function increases or decreases on a graph. Forms of quadratic functions 2 Standard: Ax +Bx+c Vertex form: A(X-H) H is the x value of the vertex, And y is the y value of the vertex. ????± ???? −4???????? To solve a quadratic equation, you use the formula 2???? Solving just √???? − 4???????? will give you the discriminant of the function. If the discriminant is positive, the function has two real solutions, and if it’s a perfect square those solutions are rational. If the discriminant is zero there is one solution If the discriminate is negative there are no real solutions. The number of solutions is also the number of X intercepts.
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