Final Exam Study Guide
Rules for dimensional analysis
1. Dimensional analysis when the dimensions of a quantity instead of the value are used to solve a problem; this is often used to check a problem 2. Dimensions can be treated as algebraic symbols for example: a. V=l*w*h each is a unit of length so volume is equal to L3
3. The quantities can only be added or subtracted if they have the same dimensions
4. Each side of the equation must have the same dimensions
5. Trigonometric functions only apply to dimensionless quantities 6. Logarithms and exponential functions only apply to dimensionless quantities
This is a good way to check your answer or work to an answer if you don’t have a clue what to do. Know what units compose a N [kgm/s2], J [Nm], W [J/s].
If you want to learn more check out Semantic memory in the form of what?
Rules for significant figures
1. When multiplying or dividing the answer will have the same amount of significant figures as the number in the equation with the least amount of significant figures
2. When adding or subtracting the answer has the same amount of decimal places as the number with the least amount of decimal places in the problem 3. Numbers such as e and π don’t place restrictions on results
4. Scientific notation can be used to help avoid confusion with significant figures 5. Keep extra significant figures when solving the equation and only bring to the proper amount after the equation has been solved
6. When the answer begins with a 1 it is okay to keep an extra significant figure
Chances are this won’t be a huge factor in the final but it’s still a handy thing to know.
Five Kinematic EquationsDon't forget about the age old question of What are the two important procedures that were initiated by the world trade organization?
Five Rotational Equations
These are very similar to the translational ones except d=θ, v=ω, and a=α. A very useful formula to use to work between the two formulas is: v=ωr
1. “Every body continues in its state of rest or of uniform motion in a straight line, unless it is compelled to change that state by forces impressed on it.” 2. F=ma
3. F[Bon A]=−F[AonB] Equal and opposite reaction.
Two and Three Dimensional Motion
∙ Position: r=xi+yj+zk
∙ Displacement: ∆ r=∆ xi+∆ yj+∆ zk
∙ Average Velocity: v=∆r
∙ Instantaneous Velocity: v=drdt If you want to learn more check out What is an example of an intangible service?
∆t Or a=dvdt
∙ Acceleration: a=∆ v
∙ Projectile motion:
(¿¿0 tcos(θ))i+(v0tsin (θ)−12g t2) j r=¿
∙ Range: Rmax=v02g
Drawing a picture is especially useful when given a problem that involves multiple forces. This will add a visual that will help with understanding the math you’ll be doing. If you want to learn more check out What are the development problems?
∙ Static friction
oμs - The coefficient of friction (dependent on what the surface is) oF N - Normal Force
∙ Kinetic Friction
∙Fk=μ k FN Don't forget about the age old question of What is the 1913 alien land act?
oμk -coefficient of kinetic friction (unitless)
o FT- The force of tension
∙ Rolling friction
oμr -coefficient of rolling friction
∙ Drag force
o b- the experimental constant. It is negative to show it’s moving opposite velocity (v).
∙ For the drag force on blunt objects (What we mostly will work with) drag force is shown by:
∙F D=12C Aρ v2
o C- The drag coefficient
o ρ- The density of the medium
A- The object’s perpendicular cross-sectional area
o v- The speed of the objects
Centripetal Force We also discuss several other topics like What argument does russell use to defend his claim that the “sense-data” we are immediately aware of in sensory experience are “signs” of external objects rather than the external objects themselves?
The magnitude of centripetal force is found by:
If the origin is in a polar coordinate system
a=r p+r A
1. rp- The perihelion distance
2. rA- The aphelion distance
3. This answer comes in Astronomical Units or AU
4. 1 AU=1.5E11 meters
o Were only going to consider the first and the third since they’re the ones formulas apply to.
o In Kepler’s third law it says that the square of a planet’s period T is proportional to the cube of its semi-major axis
2 =a[AU ]
oT[ yr ]
o Newton’s law of universal gravity shows:
o G- The gravitational constant= 6.673E-11 o The gravitational field of any source can be found from: Unit vector pointing away
o G-Gravitational constant o M- Mass
o r- Radius
o Kinetic Energy
o This answer is in Joules
o Potential Energy
o To find gravitational potential energy:
o UG (r)=−Gm1m2
o Elastic potential energy:
o K= the spring constant
o The sum of a systems Potential and Kinetic energy is its mechanical energy. This is shown by:
o The conservation of mechanical energy is shown by:
o∆ K+∆U =0
o Momentum moves in the same direction as velocity and is given by the equation:
o The initial momentum is always the same as the final momentum. In the problems that ask for recoil motion use the following formula often times in momentum problems they are paired with translational kinematic equations:
An open systems is a system that gains or loses mass. This is the formula to us for the rocket or a similar system:
Torque and Inertia
Torque can also be found by taking the cross product of two vectors. The magnitude of Torque is given by:
Inertia is the torque divided by the angular acceleration.
In translational motion the more massive particle has the most rotational inertia
Mass distribution with respect to the rotational axis also impacts rotational inertia; the farther away the mass is from the rotational axis the more rotational inertia will exist.
Rotational inertia can be found by:
M is the mass of the particle
r is the distance from the rotational axis
On a continuous object the rotational inertia is:
The parallel axis theorem where M is mass, h is the perpendicular distance between the new axis and the axis through the center of mass and ICM is the rotational inertia around the center of mass
I=I CM +M h2
The center of mass is found by:
For center of mass multiply the associated mass with the associated x coordinate.
Kinetic Energy for rotating object:
Conservation of energy holds true for rotational motion similar to translational motion
Ki+Kri+Ui+W=K f +Krf +U f +∆ Eth
Ki is the translational kinetic
Kri is rotational kinetic
Newtons second law is shown through torque and is the sum of all torque.
If the system is conserved torque initial is equal to torque final
Two conditions need to be met for an object to be at equilibrium: 1. Ftot=dpdt Ftot=0
These are all that is needed to solve and equilibrium problem. To determine the radius for the torque always set a reference point for the initial radius. I think this is easier if an endpoint is chosen.
You may need to know this for torque.
Cross Product: To do cross product the simplest way is to use matrices. If r=1i +1j and F=2i+3j the r x F=
i j k 1 1 0 2 3 0
3 0− j1 0
2 0+k1 1
The discriminate of each matrix is found. (ac-bd) So the answer to this problem is k.
The density of water is 1000 kg/m3
Most problems can be solved using the following two equations in some fashion: A1v1=A2v2
And Bernoulli’s Equation:
P1+12ρ v12+ρg y1=P2+12ρ v22+ρg y2
ρ= density of fluid
Think back to conservation of energy to use this one. It’s the same thing. This formula can also be used for flowing air.