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Get Full Access to Tulane - MATH 1140 - Study Guide - Final
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TULANE / Math / MATH 1140 / What is the formula in solving for critical value?

# What is the formula in solving for critical value? Description

##### Description: How to do the 100 practice exam problems
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NOTES:If you want to learn more check out What are the significance of each of the 7 boundary properties in the cell?

1. Z 0,04
• 0.5 - 0.04 = 0.46
• On table: 0.4599
• Z score is 1.75
1. t 0.05,7
• On table: 1.895

1. H o: u = 4                n = 12
H a: u < 4                level of significance = ⍺ = 0.05
• Less than means negative
• df = 11
• ⍺ = 0
• on t- table, t 0.05,11= 1.796

If you want to learn more check out What are the structural elements of music?

1. When u = mean value, RV x is normal

Don't forget about the age old question of Explain adolescents from early christian times through the middle ages.

Final Exam

x̄ = 0.8

σ = 0.05                 use:

• 5. p(0.725 ≤ x ≤ 0.85)
• → (0.725 - 0.8)/0.05 = -1.5 z = -0.04332
• → (0.085 - 0.8)/0.05 = 1 z = 0.3413
• Add 0.4332 + 0.3413 = 0.7745 probability
• 6. Find the upper 10% (=probability is 0.4 on RBA)
• → closest is 0.3997 = z score 1.28
• → 1.28 = (x- 0.8)/0,05, x = 0.864

We also discuss several other topics like Who is hammurabi babylon?

x̄ = 0.8We also discuss several other topics like What is the definition of rxn center?

σ = 0.05

• 7. 90% confidence interval
• → RBA of 0.45 (prob. 0.4495 or 0.4505) = 1.645 z
• x̄ ± z (σ)
• 0.8 ± 1.645(0.05)
• 0.08225
• 80 ± 8.225

Don't forget about the age old question of What are the strategies used by enzymes for catalysis?

Tulane

p = 0.3                q = 0.7

n = 20

• 8. E(x) = 0.3(20) = 6 students
• 9. 6 =
• =
• =
• 10. p (p ∧ ≥ 0.4)
• z = (p ∧ - p)/σ
• z = (0.4 - 0.3)/2.049
• z = .1 / 2.049
• z = 0.05
• p = 0.0199
• 0.5 - 0.0199 = probability 0.4801
• 11.
• Position
• P(M) = 7/11                randomly select = independent
• P(W) = 4/11                        (sampling without replacement)
• 12.
• p = 7/11 , q = 4/11
• p (3 men) = 7/11 * 6/10 * 5/9
• p (3) = 7/33
• 13. P (2 m and 1 w)
• P = P1 + P2 + P3
• (7/11 x 6/10 x 4/9) + (7/11 x 4/10 x 6/9) + (4/11 x 7/10 x 6/9)
• = 0.16969 + 0.16969 + 0.16969
• 0.509
• 14. Sampling without replacement
• E(x) = μ = =
• n = 3; r (successes) = 7; N = 11
• E(x) = 21/11
• 15. P(A) = 0.3                P (A|B) = 0.2
• P(B) = 0.4
• P (A or B) = P(A ∪ B)
• P(A ∪ B) = P(A) + P(B) - P(A ∩ B);         P(A ∩ B) = P(A|B) x P(B)= 0.2 x 0.4 = 0.08
• P(A ∪ B) = 0.3 + 0.4 - 0.08
• P(A ∪ B) = 0.62
• 16. n = 400                want to find p(p ∧ ≥ 300/400)
• p = 0.5
• Find σ =
• p (p ∧ ≥ 0.75)
• z = (p ∧ - p) / σ = (0.75 - 0.5) / 0.025 = 10
• Z score 10 = probability of 0
• 17. x̄: 190,000
• σ: 20,000
• n: 100                        use
• Find p(186,000 ≤ x ≤ 193,000)
• z = (180,000 - 190,000) / (20,000 /)
• z = -2
• prob= -0.4772
• z = (193,000 - 190,000) / (20,000) /)
• z = 1.5
• prob= 0.4332
• 0.4772 + 0.4332 = 0.9104

Nutritionist

⍺ = 0.05

n = 500

p ∧ = 220/500 = 0.44; p =0.4

q = 0.56

σ = = 0.02

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