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Purdue - CHE 20500 - Class Notes

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Purdue - CHE 20500 - Class Notes

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background image   ChE 205 Hour Exam #3 Solution  Question 1   (50 points)   a)  3 points   Benzene: B; Toluene: T           +1 point  for the evaporator  +1 point  for separate liquid and vapor streams at the outlet  +1 point  for using dots in molar flowrate symbols  b)  10 points   min (P 0 )=?  min (P 0 )=Bubble point at T 0 =90°C  (+2 points)   From Rault’s Law:  min 𝑃 0 = 𝑥 𝐵0 𝑃 𝐵 + (1 − 𝑥 𝐵0 )𝑃 𝑇   (+3 points)   From Antoine equation:    (+2 points)   𝑃 𝐵 (𝑎𝑎 𝑇 = 90°C) = 10 6.893− 1204 90+219.9 = 1018.3𝑚𝑚𝑚𝑚  (+1 point)   𝑃 𝑇 (𝑎𝑎 𝑇 = 90°C) = 10 6.958− 1347 90+219.7 = 406.1𝑚𝑚𝑚𝑚  (+1 point)   min 𝑃 0 = 0.541 ∗ 1018.3 + 0.459 ∗ 406.1 = 373.3𝑚𝑚𝑚𝑚  (+1 point)  
background image   c)  15 points   𝑃 𝐸𝐸𝐸𝐸 , 𝑦 𝐵1 , 𝑛̇ 1 , 𝑛̇ 2 = ?   Using Antoine equation,  (+2 points)   𝑃 𝐵 (𝑎𝑎 𝑇 = 75°C) = 10 6.893− 1204 75+219.9 = 646𝑚𝑚𝑚𝑚  𝑃 𝑇 (𝑎𝑎 𝑇 = 75°C) = 10 6.958− 1347 75+219.7 = 243.9𝑚𝑚𝑚𝑚  Rault’s Law for B: 𝑦 𝐵1 𝑃 𝐸𝐸𝐸𝐸 = 0.439 ∗ 646                               𝑃 𝐸𝐸𝐸𝐸 = 417mmHg      (+1 point)            Rault’s Law for T: (1 − 𝑦 𝐵1 )𝑃 𝐸𝐸𝐸𝐸 = 0.561 ∗ 243.9                𝑦 𝐵1 = 0.68molB/mol     (+1 point)   Overall mole balance around evaporator: 93 𝑚𝑚𝑚 𝑠 = 𝑛̇ 1 + 𝑛̇ 2                   𝑛̇ 1 = 39.3𝑚𝑚𝑚/𝑠      B balance around evaporator: 93 ∗ 0.541 = 𝑛̇ 2 ∗ 0.439 + 𝑛̇ 1 𝑦 𝐵1            𝑛̇ 2 = 53.7𝑚𝑚𝑚/𝑠  +3 points  for using Raoult’s Law for calculation of 𝑃 𝐸𝐸𝐸𝐸   +6 points  for the two mole balances  +1 point  for the numerical value of 𝑛̇ 1   +1 point  for the numerical value of 𝑛̇ 2   d) 1 5 points  References: Liquid B & T at 75°C  Substance  𝑛̇ 𝑖𝑖  (mol/s)  𝑚� 𝑖𝑖  (kj/mol)  𝑛̇ 𝑚𝑜𝑜  (mol/s)  𝑚� 𝑚𝑜𝑜  (kj/mol)  B(l)  𝑛 1 : 50.3  𝑚 1 : 1.905  𝑛 5 : 23.6  𝑚 5 : 0  B(v)  𝑛 2 : -  𝑚 2 : -  𝑛 6 : 26.7  𝑚 6 : 31  T(l)  𝑛 3 : 42.7  𝑚 3 : 2.235  𝑛 7 : 30.1  𝑚 7 : 0  T(v)  𝑛 4 : -  𝑚 4 : -  𝑛 8 : 12.6  𝑚 8 : 33.7    + 5 points  for the input-output enthalpy table: +1 point for each column (* 5 columns) 

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School: Purdue University
Department: Chemical Engineering
Course: Chemical Engineering Calculations
Professor: Bryan Stephen P Beaudoin
Term: Fall 2015
Tags:
Description: ChE 205 Hour Exam #3 Solution Question 1 (50 points) a) 3 points Benzene: B; Toluene: T +1 point for the evaporator +1 point for separate liquid and vapor streams at the outlet +1 point for using dots in molar flowrate symbols b) 10 points min (P 0)=? min (P 0)=Bubble point at T 090°C (+2 points) From Rault’s Law: ∗ ∗ min???? =0???? ???? ????0(1????−???? )???? ????0 ???? (+3 points) From Antoine eq
Uploaded: 05/09/2017
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