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Georgia Tech - Mat 1554 - Class Notes - Week 1

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Georgia Tech - Mat 1554 - Class Notes - Week 1

School: Georgia Institute of Technology
Department: Math
Course: Linear Algebra
Professor: Belegradek
Term: Fall 2016
Tags: Math, Linear Algebra, and Matrices
Name: MATH 1554, Week 1 Notes
Description: These notes cover reduced row echelon form and systems of linear equations. Will be on exam.
Uploaded: 01/10/2018
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Join more than 18,000+ college students at Georgia Institute of Technology who use StudySoup to get ahead
School: Georgia Institute of Technology
Department: Math
Course: Linear Algebra
Professor: Belegradek
Term: Fall 2016
Tags: Math, Linear Algebra, and Matrices
Name: MATH 1554, Week 1 Notes
Description: These notes cover reduced row echelon form and systems of linear equations. Will be on exam.
Uploaded: 01/10/2018
8 Pages 13 Views 10 Unlocks
  • Better Grades Guarantee
  • 24/7 Homework help
  • Notes, Study Guides, Flashcards + More!

Unformatted text preview: Linear Algebra Systems of linear Equations LX.- X3=4 2. cquations, 3 variables No soluhon xxz = 2 Infinitely many solutions La Even though two equations are te same, they still counte two equations for doing matrices - Viqve solution (x,x = 2%, -6X= . Augmented mateixo olds o mult of a Raus operations ro ho ong ther on mah ces > multiplies a row by FO number interchanges two rows LES) >9 ? rudysoup Pivals reduced rou7004 alle numbers above onol blo Pivors are zeroThere are 3 Fleypes of rous operations: verilla, chocolate, sombery You can choose any combination to solve a matrix - Rules Add o multipk of one on to another 2) Interchange OCOLAS 35 Multiply a cows by a non-zero constant 2xiy= 3 0 -2%2457 (x - Hyel --34 3 4 These equations and lines. Do they have 2 point where they intecsect ? X-3 -1 -3 Cases * Cani solve X-yil Have more equa hions than variables D.Could have exho information only need one X+ 0 = 2 equahor telling X- > you about X Orig) Some number of pque tiens as acoblesAutis Reduced cow echelon form Find the general solu hoa X. - 38,- 5x, = 0 to [ab] = -3 -S A TO 3 AKA R2.3 R1 > pivots POS -37 LOO -1 - X, X, Pivot variables Xs free variable "We always solve he pivot voriables in terms of prevariables Ex. -3.Sys 8 3 U v = 2:) - La - 50 - EESNJE) 2. Find general solution to A = [IN] b ( 2 nonsense NO SOLUTION Find aeneral solu honno AD b: X, X, X= Alb] : [ort i] - gora diduced X = pivot Yz, X3 = free

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