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Chem 100

by: Martha Fernandez
Martha Fernandez
Long Beach State

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About this Document

This week we went over Stoichiometry and the Mole
Chem 100
Tom Gufrey
Study Guide
Chem100 CSULB
50 ?




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This 2 page Study Guide was uploaded by Martha Fernandez on Tuesday March 8, 2016. The Study Guide belongs to Chem 100 at California State University Long Beach taught by Tom Gufrey in Spring 2016. Since its upload, it has received 28 views. For similar materials see Chem 100 in Chemistry at California State University Long Beach.


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Date Created: 03/08/16
Chem 100 Notes I. Mol: 1 huge number a. 1 mol has to do with molar mass of the atoms i. 1 mol atomic mass # in grams 1. Ex1. Molar Mass= 4.0g He= 1 mol He 4 g He 2. Ex2. 1 Mol Au= 197g Au (Mass No= 197) Molar mass of Au= 197g Au 3. Ex3. 1 mol H 2O= 2 (H)= 2(1) = 2 1 (O) = 1 (16)= 16 18 g H2O = Molar Mass of H2O 1 mol H2O II. Stoichiometry: Chemical Arithmetic a. When you see a coefficient in Chemical Formula think of them as Moles i. Coefficient in box (or whole number before each compound in chemical equation) = Mol of that compound ii. Ex. 2 H2 + 1 O 2  2 H 2O 2 comes from 1. This is a balanced equation* the atomic b. How to Get Grams of A -- Grams of B mass of H. c. Step 1: Grams of A - Mol A i. Need Balanced Eqtn: N 2+ 3H 2  2 NH 3 ii. Will need to find molar mass of A iii. Ex: Molar Mass: (440g of 2) (1 mol) = 220 mol H 2 2 g H2 d.Step 2: Mol A  Mol B i.Balance Eqtn . (220 mol H2) (2 mol NH3) = (.66) (220) = 146.7 3 mol H 2 mol NH 3 e. Step 3: (146.7 mol NH 3)( 17 g NH3)  17 comes from the total atomic 1 mol NH 3 mass of compound = 2494g NH 3 I. So above we started with 440 g of H2 which was given, and were asked to find the amount, in Grams, of NH3.


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