Organic Chemistry I
Organic Chemistry I CHM 2210
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This 2 page Study Guide was uploaded by Araceli Lubowitz on Wednesday September 23, 2015. The Study Guide belongs to CHM 2210 at University of South Florida taught by Staff in Fall. Since its upload, it has received 12 views. For similar materials see /class/212698/chm-2210-university-of-south-florida in Chemistry at University of South Florida.
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Date Created: 09/23/15
CHM2210 Answer Key Acid Base Chemistry 1 Does the reaction lie to the left or to the right Use Table 15 in Wade to solve this problem a Reaction lies far to the left difference of l 11 pKa units it J J1 9 J 90 CH3 HO HO CH3 0 pKA1 5 9 pKA48 b Reaction lies slightly to the right difference of only 1 pKa units 0 O H H e eOJLCH3 Ho o HOJJCH3 0amp0 pKA 38 pKA48 c Reaction lies very far to the right difference of more than 36 pKa units eNH2 HOl NH3 90 6 0 O pKA 38 DKAgt40 2 Calculate the equilibrium constant Keq and AG of the following reaction pKa of diethyl amine is 35 pKa of phenol is 10 9 OH O EtZN O EtzNH O The pKa for the first reaction is 35 and for the second reaction is 10 e Et2NH H20 EtzNO H3099 OH 0 H20 O Hg a O Reverse the rst reaction and keep the second reaction the same Then calculate the equilibrium constants from the pKa values The equilibrium constant for the rst reaction is K1 l1X103935 The equilibrium constant for the second reaction is K2 leO39lo e e EtzN H3O Et2NH H20 OH 0 H20 O H309 G The equilibrium constant Keq for following reaction is the product of the constants K1 and K2 Keq K1 K2 1x1025 6 OH o EtzN O Et2NH O AG can be calculated by the equation AG RTlnKeq 0002 300K 1n1025 345 kcalmol Since AG is negative the reaction is spontaneous O
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