### Create a StudySoup account

#### Be part of our community, it's free to join!

Already have a StudySoup account? Login here

# STAT 200-OL1-US1 SECTION FINAL EXAMS

LU

GPA 3.8

### View Full Document

## 66

## 0

## Popular in Course

## Popular in Department

This 0 page Study Guide was uploaded by kimwood Notetaker on Thursday November 5, 2015. The Study Guide belongs to a course at a university taught by a professor in Fall. Since its upload, it has received 66 views.

## Similar to Course at University

## Reviews for STAT 200-OL1-US1 SECTION FINAL EXAMS

### What is Karma?

#### Karma is the currency of StudySoup.

#### You can buy or earn more Karma at anytime and redeem it for class notes, study guides, flashcards, and more!

Date Created: 11/05/15

STAT 200 0L1 US1 Sections Final Exam Problem Number Solution 1 a TRUE b TRUE 0 FALSE 1 FALSE e FALSE Work a For normal distribution curve mean median and mode coincide Also every distribution is divided into two equal parts by its median ie symmetric about median Since for a normal distribution curve mean is same as median the distribution is symmetric about its mean b If all the observations in a data set are identical then its arithmetic mean is also has the same value of the observations Therefore it can be observed that all the mean deviations from the observations in the data set are zero so as its variance is also zero 0 Since A and AC are disjoint the probability of their intersection must be equal to zero not equal to 1 d If pvalue is less than the level of significance 1 it indicates that the test statistic fall in the rejection region so we have sufficient evidence to reject the null hypothesis e The volume of a milk jug represents a continuous data since it can take any of the values between the given limits 2 The shaded cells in the following table indicate the calculated values Checkout Time in minutes 10 19 20 29 30 39 40 59 Total Frequency f Relative Frequency Work Total frequency 25 28525 1525 25 1510 Frequency of the cell Relative frequency Total frequency gt Relative frequency for 10 19 2 25 008 gt Relative frequency for 20 29 825 032 gt Relative frequency for 30 39 1025 040 gt Relative frequency for 40 5 9 5 25 020 3 Answer 040 Work Obtain the percentage of the checkout times was less than 3 minutes 28 2810525 4 Answer The median must lie in the class 30 39 Work The following table shows the cumulative relative frequency distribution of the given data Checkout Cumulative Frequency Relative Time 1n Relative 139 Frequency minutes Frequency 10 19 2 008 20 29 8 032 30 39 10 040 40 59 5 020 Total 25 100 The median of the distribution covers 50 of the observations in the given dataset Here the cumulative relative frequency corresponding to 30 39 is just greater than 50 so median must lie in that interval 5 Answer Mean increases and median remains the same Work The mean increases as the observation recorded incorrectly increases the sum of the observations The median remains the same as it is a measure of location not in uenced much by the change in extreme observations 6 Answer The required sample standard deviation is 9975 2x 215151830 Q Mean 16 n 5 5 2 2 2 2 16 L 30 16 Standard deviation 5 M 4 997 n 1 5 1 4 7 Answer There are 24 16 outcomes in the sample space Work The required sample space is HHHH HHHT HHTH HTHHTHHH HHTT HTHT HTTHTHHT THTHTTHHTTTHTTHTTHTTHTTTTTTT gt n S 16 8 Answer The probability that the third toss is heads given that the first toss is heads is 05 Work The required sample space is HHHH HHHT HHTH HTHHTHHH HHTT HTHT HTTHTHHT THTHTTHHTTTHTTHTTHTT HTTTTTTT gt n S 16 Let A is the that the first toss is heads B HHHHHHHT HHTHHTHH HHTT HTHT HTTH HTTT gt n A 8 Let B is the that the third toss is heads A HHHH HHHT HTHHTHHH HTHTTHHTTTHHTTHT gt n B 8 A m B HHHH HHHTHHTHHTHT gt n A m B 4 PBAm nA 8 9 Answer Yes the events A and B are independent The required sample space is HHHH HHHT HHTH HTHHTHHH HHTT HTHT HTTHTHHT THTHTTHHTTTHTTHTTHTT HTTTTTTT gtnS 16 Let A is the that the first toss is heads B HHHHHHHT HHTHHTHH HHTT HTHT HTTHHTTT gt n A 8 Let B is the that the third toss is heads A HHHH HHHT HTHHTHHH HTHTTHHTTTHHTTHT gtnB8 nB 8 P B 115 16 A03 HHHHHHHTHHTHHTHT gtnAmB4 A B pBAm nA 8 Since P B A P B the events A and B are independent 10 Answer b Bigburg Work Since the range of the city Bigburg is high its variability is also high 11 Answer a Tinytown Work Since the Tinytown has a symmetric distribution and the Bigburg has a left skewed distribution for Tinytown its value is 50 and for Bigburg it is less than 50 12 Answer c Both cities have the same value requested Work Since for Bigburg its value is about 50 and for Tinytown also it is about 50 13 Answer The required probability is 025 Work Let A and B be the events that a randomly selected junior is in STAT200 and PSYC300 courses The probability that a randomly selected junior is in at least one of the two courses P A U B P A P B P A m B By addition theorem of probability 200 100 50 1000 1000 1500 250 1000 m 14 Answer The required probability is 025 Work Let A and B be the events that a randomly selected junior is in STAT200 and PSYC300 courses The probability that a randomly selected junior is taking PSYC300 given that heshe is taking STAT200 A m B PBAn 50025 n A 200 15 Answer The number of ways can the delegate be selected is 45 Work The number of ways can the delegate be selected 10 10 10gtlt9gtlt810gtlt9 27 2210 2 2blt8 2x1 16 Answer 3 Expected winning in this game is 5 b The standard deviation is 3854 Work Prize Amount x Probability p Xp X2 p 100 010 10 1000 50 010 5 250 10 020 2 20 20 060 12 240 Total 100 5 1510 17 Answer a The number of trials is n 8 the probability of success p 020 The probability of failure q 08 b The required probability is 08322 c The expected number of serves to be returned is 16 Work a SinceX Bnp with n 8 andp 02 q1 p1 02 b PX 21 1 PX 0 1 2 02 1 028 0 1 088 1 01678 c np802 18 Answer The required probability is 06826 Work HereX Nu 10003915 P85sxs115 P85 s X 3115 039 039 039 85 100323115 10m 15 15 7 P 1sxs1 lt1gt1 c1gt 1 08413 01587 06826 19 Answer The 90th percentile is 1192 Work Here X N u 100039 15 Let the 90th percentile is Pgo Obtain its value by solving the following X PXlt1990090gtP gar 090gt 23M 090 gt1 039 039 7 15 From normal areas table we have P X lt 128 090 gt II P 1 gt 901 00 1645gt Pg0 10015128 100192 1192 20 Answer The standard deviation of the sample mean is 15 Work HereX Nu 10003915 Sample size n 100 The standard deviation of the sample mean 039 i i E J 100 10 21 Answer The 95 con dence interval for mean life time is 29347 30653 Here Sample size n 100 Sample mean 7c 3000 Population standard deviation 039 500 Construct a 95 confidence interval of the mean lifetime 039 f 50 Lzaz 3000zo05 g 3000i196 3333 3000i 653 29347 30653 22 Answer a The test statistic is z 03 b The pvalue is 06179 c There is no suf cient evidence to justify the rejection of H0 Work a Here Sample size n 225 Sample proportion 13 051 H0 p 05 H1 p lt 05 Test statistic z p 051 05 c Since pValue 06179 gt a 001 there is no sufficient evidence to justify the rejection of H 0 I3 p1 pn J051 05225 b pValue of the test statistic p P Z lt z P Z lt 03 ltIgt 03 06179 23 Answer a H0 1 0 and H1 1 gt 0 b The test statistic is t 1118 c The pvalue is 01631 1 There is no sufficient evidence to support the claim that the mean number of correct answers after the class exceeds the mean number of correct answers before the class Work Before After 1 After Before 12 14 2 15 18 3 9 11 2 12 10 2 12 12 0 Total 5 Mean 1 SD 2 b Here Sample size n 5 Sample mean of differences 27D 1 Sample standard deviation of differences SD 2 7 1 Test statistic t D 1118 sD NZ 2N3 c pvalue Pt4 gt1118 01631 d Since pvalue 01631 gt a 001 do not reject the null hypothesis Therefore at 001 level there is no sufficient evidence to support the claim that the mean number of correct answers after the class exceeds the mean number of correct answers before the class 24 Answer a The required regression line is y 102 x 171 b The required predicted value at x 4 is 579 Work x y x2 y2 W 0 3 0 9 0 1 2 1 4 2 3 3 9 9 9 5 8 25 64 40 Total 9 16 35 86 51 a From the given data in 92 y 16in2 352 yf 86 inyi 51 andn4 The least square line of the form y a bx to the given data be fitted as follows Slope nzxiyi in Zzyi 4X51 9X126 aniz in 1 1 Intercept a Zyi 492 Z16 102gtlt9 yl02xl7l b Obtain the predicted value of y if x 4 94 102gtlt4171 579 The required least square line is 25 Answer a The null and alternative hypotheses are Hozp1p2p3p4p5020 H a At least one proportion is different from reported value b The required test statistic is 12 09 c The required pvalue is 09246 1 There is suf cient evidence to support the claim that such injuries and illnesses occur with equal frequency on the different days of the week Work A b The expected frequencies E1 Npi E110002020 E210002020 E310002020 E410002020 E5 100 020 20 O E T tStt39t39 2 es a1s1cz E 2 2 2 22 20 22 20 20 20 19 20 20 20 20 20 17 202 20 c pValue P24 gt 0 d Since pValue 09246 gt a 005 do not reject the null hypothesis Therefore at 005 level there is sufficient evidence to support the claim that such injuries and illnesses occur With equal frequency on the different days of the week

### BOOM! Enjoy Your Free Notes!

We've added these Notes to your profile, click here to view them now.

### You're already Subscribed!

Looks like you've already subscribed to StudySoup, you won't need to purchase another subscription to get this material. To access this material simply click 'View Full Document'

## Why people love StudySoup

#### "There's no way I would have passed my Organic Chemistry class this semester without the notes and study guides I got from StudySoup."

#### "I used the money I made selling my notes & study guides to pay for spring break in Olympia, Washington...which was Sweet!"

#### "There's no way I would have passed my Organic Chemistry class this semester without the notes and study guides I got from StudySoup."

#### "Their 'Elite Notetakers' are making over $1,200/month in sales by creating high quality content that helps their classmates in a time of need."

### Refund Policy

#### STUDYSOUP CANCELLATION POLICY

All subscriptions to StudySoup are paid in full at the time of subscribing. To change your credit card information or to cancel your subscription, go to "Edit Settings". All credit card information will be available there. If you should decide to cancel your subscription, it will continue to be valid until the next payment period, as all payments for the current period were made in advance. For special circumstances, please email support@studysoup.com

#### STUDYSOUP REFUND POLICY

StudySoup has more than 1 million course-specific study resources to help students study smarter. If you’re having trouble finding what you’re looking for, our customer support team can help you find what you need! Feel free to contact them here: support@studysoup.com

Recurring Subscriptions: If you have canceled your recurring subscription on the day of renewal and have not downloaded any documents, you may request a refund by submitting an email to support@studysoup.com

Satisfaction Guarantee: If you’re not satisfied with your subscription, you can contact us for further help. Contact must be made within 3 business days of your subscription purchase and your refund request will be subject for review.

Please Note: Refunds can never be provided more than 30 days after the initial purchase date regardless of your activity on the site.