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# PSY 315 Week 3 û Chapter problems

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Date Created: 11/13/15

Chapter Problems Week 3 Page II Week 3 Chapter problems PSY 3 15 Katherine Sainz University of Phoenix Chapter Problems Week 3 Page 2 Week 3 Individual Assignment 0 Ch 2 Practice Problems 11 12 13 16 and 21 0 Ch 3 Practice Problems 14 15 22 and 25 Chapter 2 Question 11 Squared Value Mean Deviati Deviation on 1 0 2 2 4 2 0 2 2 4 3 0 2 2 4 4 0 2 2 4 5 0 2 2 4 6 1 2 1 1 7 1 2 1 1 8 1 2 1 1 2 1o 1 2 1 1 a T i 011121315113 2 21 11 I I I 1 2 2 2 O O 1 3 2 2 O O 14 3 2 1 1 15 3 2 1 1 1 6 4 2 2 4 1 7 4 2 2 4 18 4 2 2 4 1 9 4 2 2 4 20 4 2 2 4 21 5 2 3 9 42 I 39 I The mean is the mathematical average In this series of scores the mean is two A11 21 scores are added up and then divided by the total number of scores Chapter Problems Week 3 Page 3 The Median is the 39middle value39 in your list When the totals of the list are odd the median is the middle entry in the list after sorting the list into increasing order In this dataset 2 is the Median as 10 data points fall above and below this data point The eleventh score in ranked order holds the value of 2 Therefore the median of this dataset is 2 The sum of the squared deviation is 56 The square of any number is positive By squaring the deviations individually and summing them positive number results which can be used reliably in additional statistical analysis The variance which is 2666667 Among 21 scores there is a divergence from the median of scores which is the variance The standard deviation of 1632993 is the square root of the variance Chapter 2 Question 12 Squared Value Mean Deviation Deviation 1151111 1 1112 13124 2004 4016016 3939 2 1245 13124 674 454276 W 3 1361 13124 486 236196 4 1372 13124 596 355216 13 quot 39 39 39 39 5 1472 13124 1596 2547216 51 quot 39 39 39 39 d n 13124 E 1233606 393 1521784 1 E 3 l 5 E39 1233606 I The mean is 13124 The median is 1361 The sum of the squared standard deviations 760892 The variance is 1521784 The standard deviation is 1233606096 Chapter 2 Question 13 Squared 4 Value Mean Deviation Deviation 35 1 26 3166667 056667 0321111 3 39 2 3 3166667 016667 0027778 3539 39 2 Chapter Problems Week 3 Page4 32 3166667 0033333 0001111 33 3166667 0133333 0017778 34 3166667 0233333 0054444 35 3166667 0333333 0111111 3166667 0298142 0088889 0298142 The mean is 3166666667 The median is 325 The sum of the squared standard deviations 0533333333 The variance is 0088888889 The standard deviation is 0298142397 Chapter 2 Question 16 Governor39s Mean Deviation Squared Value Deviation Of ce 1 36 43 7 49 Of ce 2 40 43 3 9 Of ce 3 44 43 1 Of ce 4 52 43 9 81 Mean I I i Strddev I Variance 35 checkStrdDev 591608 CEO39s Mean Deviation Squared Value Deviation Of ce 1 32 44 12 144 Of ce 2 36 44 8 64 W Of ce 3 48 44 4 16 3 Of ce 4 60 44 16 256 g Mean I I i 3393 Strddev I 1 Variance 120 1 a 3 checkStrd Dev 1 095445 If I would have to give Frank advice regarding the appropriate size for his desk I would show him how to calculate the statistics for his decision First I plotted the desk measurements of four of the state governors that I knew I then plotted the sizes of desks of four CEO s that I knew I averaged the size of all the govemor s desks I then found the average size of the CEO s desks Chapter Problems Week 3 Page I5 I found the average size of the governor s desks to be 43 square feet I then did the same with the CEO s desks I found the average square footage which was 44 square feet With further analysis involving the variance of desk sizes within each range I was able to determine the deviation from the central tendency for each set of observations The standard deviations for the governor s desk sizes were 591608 square feet The standard deviations for the CEO s desk sizes were 1095445 square feet As the average between the two groups results of difference of only one square foot I advised Frank that an appropriate desk size range for his new position of CEO would be 44 square feet plus or minus one standard deviation This provided Frank with a size range from 33 square feet up to 55 square feet Frank was very grateful The average size of the governor s desks is 43 square feet The average size of the CEO39s desks is 44 square feet The standard deviations for the governor s desk sizes were 591608 square feet The standard deviations for the CEO s desk sizes were 1095445 square feet Chapter 2 Question 21 In this study a test group of individuals were shown a face and an item The items were either a gun or a tool The face was either back or white The first test provided the respondent as much time as needed to decide if the face went with a gun or a tool The second test required making a snap decision The results showing the Means and Standard Deviations were charted as follows Chapter Problems Week 3 Page I6 Tahll 25 91991 HE ClillTil l lEE in frlillisauznrja l in IrJEntj rin Guns 9I19T99 in E p l iml lt 1 and 2 an I999 White T l t M 99 M 99 Experim 9m 1 99m 929 91 air11 29 TDDI 2191 52 air 19 99 Exp 9 rirn ant 2 99m 299 29 295 91 T99 992 29 999 29 Source Prejudice and Perception page 185 When looking at the data analysis the outcomes may appear unbiased In Experiment 1 the difference between the means of whiteblack Gun were only 18 points a part The difference between the means of the whiteblackTool were only 8 points The difference between the Standard Deviations for the whiteblackGun were 9 Standard Deviation points When the Standard Deviations of the datasets are taken into consideration a slightly different view is presented If each dataset is measured under a normal bellshaped curve and the Standard Deviations for each dataset are carried out 3 standard deviations it is found that the error of presuming the BlackGun is a consistently grouped error of bias In experiment 2 the choice had to be made as quickly as possible The results of this timedchoice produced a slightly more biased view While the Means for data points appear close numerically the Standard Deviations become more telling The mean for BlackGun is 299 and the mean for the WhiteGun is 295 The Standard Deviations are 28 and 31 respectively The mean for BlackTool is 307 with a Standard Deviation of 29 The mean for WhiteTool is 304 with a Standard Deviation of 29 In this view associating a Toll with a face color tends to occur with approximately the same unbiased error On the other hand associating a face color with a Gun tends to slightly more closely with the presentation of Blackface under a timestressed choice I told Frank that while the Mean will provide insight to the central tendencies of a distribution the Standard Deviation will provide a sense of the range and frequency under that area of a normal curve Chapter Problems Week 3 Page I7 Chapter 3 Question 14 Raw Scores to Z scores for Standardized Hearing Ability Measure converted Mean Resu1t SD Your Z Score 340 300 40 20 2 3 10 300 10 20 05 260 300 40 20 2 Z score is the raw score minus the mean divided by the standard deviation A 1 M 5H E Z Scores to Raw Scores for Standardized Hearing Ability Measure Standard X Z Mean Your Deviation Score Raw Score 20 24 300 348 20 1 5 300 330 20 0 300 300 20 45 300 210 The raw score is the Z score multiplied by the standard deviation Plus the mean 13511 M Chapter 3 Question 15 As this is a standardized test the general mean and standard deviation for each domain tested is known A quick analysis of the raw scores produced the Z values for each domain As Z Scores relate to how far from the Mean a score is positive Z values indicate better than average assessments In this case the person scored over 1 Stande Deviation about the mean in both domains This person has moved 155 Standard Deviations above the mean in Verbal Ability and Chapter Problems Week 3 Page 8 128 Standard Deviations above the mean in Quantitative Ability which is good Of the two domains the person has demonstrated a slightly higher ability level in Verbal Ability Chapter 3 Question 22 The sampling method used here is random sampling Sampling methods are classified as either probability or nonprobability In probability samples each member of the population has a known nonzero probability of being selected The random sampling used in this survey consisted of the population of graduate students Because of the random sampling method a person can interview random people within the population of Psychology graduate students The limitations of this type of sampling method would be that there are not a certain number of students Another form of sampling would be to take the total population of graduate students and use stratified sampling First ask all females between the ages of 18 to 21 and then ask all males of that population Chapter 3 Question 25 When conducting a survey of 1000 respondents from a local college and categorizing these respondents into five equal groups the question is the probability of selecting one unique respondent contact record at random The probability of picking a respondent contact record unique on any one try is as follows Probability of event that Probability does not Category Number PA occurs PA39 a Student 800 08 02 b Faculty 50 005 095 c AdministrationStaff 150 015 085 d Faculty OR AdministrationStaff bc 200 02 08 e NOT AdministrationStaff ab 850 085 015 There are 1000 people to contact We know that there are 800 students at the college So 8001000 is 80 or 80 chance of picking out a student listing Chapter Problems Week 3 Page I9 There are 150 administrationstaff listings So 1501000 is 15 or 15 of a chance of picking out an administrationstaff listing There are 50 faculty listings So 501000 is 05 or 5 of a chance of picking out a faculty listing When considering combinations of categories the chance of picking out either a Faculty OR AdministrationStaff listing relates to the addition of the size of these two categories 200 diVided by the population 1000 Which is 20 or 20 When considering picking a listing that is NOT AdministrationStaff that ignores 150 records from the 1000 total records and leaves 850 So 8501000 is 85 or 85 chance of not being that of AdministrationStaff

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