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## Week 3 Electronic Text MicroSoft Word Solutions Quiz (9.70+9.74+9.78+9.80) - All work shown + megastat output

by: smartwriter Notetaker

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# Week 3 Electronic Text MicroSoft Word Solutions Quiz (9.70+9.74+9.78+9.80) - All work shown + megastat output

Marketplace > Week 3 Electronic Text MicroSoft Word Solutions Quiz 9 70 9 74 9 78 9 80 All work shown megastat output
smartwriter Notetaker
CSU - Dominguez hills
GPA 3.0

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Week 3 Electronic Text MicroSoft Word Solutions Quiz (9.70+9.74+9.78+9.80) - All work shown + megastat output
COURSE
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TYPE
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PAGES
3
WORDS
KARMA
50 ?

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Date Created: 11/15/15
Week 3 Quiz for RES342 Research and Evaluation II Please complete the following exercises and post to the assignment section on or before February 14, 2011. Title sheets are required for all assignments. Thanks,  Exercises: 9.70, 9.74, 9.78, and 9.80 (Doane & Seward, 2007, pp. 391­392).  PROPORTIONS: SMALL SAMPLES H o p=0.02 H : p>0.02 a P(x>2 )=P (X=13 +P X=14 )+…P (X=36 =0.16177314494926742 Since that is greater than the significane level of 0.10, we can’t reject the null and we have  to say that the quality standards are correct.  (a) It shows that the test statistic is quite extreme since its less than the alpha level of  0.05, and the probability of rejecting the null hypothesis is 0.042, which usually  means it will be rejected, and there will be a “significant” difference. (b) If it had a p­value of 0.087, its not that extreme of a test statistic, meaning the null  hypothesis probably would not be rejected, and even so, then the difference would  not be so “significant”. 2 2 H 0σ =8  (The variance is 64) H :σ ≠8 2  (The variance is not 64) a Alpha=0.05 D. f .=25−1=24 Chi .0,24=12.401 2 Decision rules: Reject H 0f thetest statistic<12.401 RejectH if theteststatistic>12.401 a Test statistic: The SD of this sample is approx.  14.068  according to excel. s =samplevariance=64 2 σ =populationvariance=14.068 n=sample¿25 2 2 (n−1 )s 24∗14.068 Chisquare= 2 = 2 =≈1.1596 σ 64 We reject the null hypothesis since  1.1596<12.401 The variance is not 64 as our conclusion. (a) Type 1 error is rejecting she has a less value when in fact she does and a type 2 error is  failing to reject the null that is less than the normal value when in fact it is not. (b) With the type 1 error, she will be taking medicine when she should not take it, and the  patient will bear the cost. The Type 2 error means she should be taking medicine, but she  will not since it was failed to be rejected and both will bear the cost since it’s the doctors  fault and the patient will have problems. (c) It might differ since the patient might think she has no problem, but in reality does have,  and the doctor will think she does have. (d) It’s a business problem since statistics is used here, and mistakes can be costly. It’s a  societal problem also since it shows that a doctor is not trustworthy if a wrong mistake  (or rejection in this case) is made. It’s also an individual problem since the patient’s  problems depend on this rejection, and so does the doctor’s career.

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