Math117 Appendix F
Math117 Appendix F
CSU - Dominguez hills
Popular in Course
verified elite notetaker
Popular in Department
This 0 page Study Guide was uploaded by smartwriter Notetaker on Monday November 16, 2015. The Study Guide belongs to a course at a university taught by a professor in Fall. Since its upload, it has received 23 views.
Reviews for Math117 Appendix F
Report this Material
What is Karma?
Karma is the currency of StudySoup.
You can buy or earn more Karma at anytime and redeem it for class notes, study guides, flashcards, and more!
Date Created: 11/16/15
Axia College Material Appendix E Radicals Application Practice Answer the following questions Use Equation Editor to write mathematical expressions and equations First save this file to your hard drive by selecting Save As from the File menu Click the white space below each question to maintain proper formatting Hint for this assignment Pay attention to the units of measure You may have to convert from feet to miles several times in this assignment You can use 1 mile 5280 feet for your conversions 1 Many people know that the weight of an object varies on different planets but did you know that the weight of an object on earth also varies according to the elevation of the object In particular the weight of an object follows this equation w Cr 2 where C is a constant and r is the distance that the object is from the center of the earth a Solve the equation w Cr z for r w CrA2 W C I39A2 er2 C rA2 Cw r Cw b Suppose that an object is 100 pounds when it is at sea level Find the value of C that makes the equation true Sea level is 3963 miles from the center of the earth Here w 100 pounds r 3963 miles So 100 C3963 2 gt 100 C 15705369 gt C 100 15705369 gt C 1570536900 c Use the value of C you found in the previous question to determine how much the object would weigh in i Death Valley 282 feet below sea level ii The top of Mt McKinley 20320 feet above sea level i Here r 282 feet 3963 miles 2825280 3963 miles 39630534 miles C 1570536900 pound mileA2 MAT 117 So w 1570536900 39630534A2 pounds 999973 pounds ii Here r 20320 feet 3963 miles 203205280 3963 miles 396685 miles C 1570536900 pound mileA2 w 1570536900 396685A2 998061 pounds 2 The equation 1 12 gives the distance D in miles that a person can see to the horizon from a height h in feet a Solve this equation for h D 12h D12 h h D12 h D122 h 02144 b Long s Peak in the Rocky Mountain National Park is 14255 feet in elevation How far can you see to the horizon from the top of Long s Peak Can you see Cheyenne Wyoming about 89 miles away Explain your answer Here h 14255 So D 12h 12114255 12 1193943 14327 So from the top of Long s Peak we can see 14327 miles to the horizon Since Cheyenne Wyoming is about 89 miles away and within 14327 miles it can be seen from Long s Peak MAT 117
Are you sure you want to buy this material for
You're already Subscribed!
Looks like you've already subscribed to StudySoup, you won't need to purchase another subscription to get this material. To access this material simply click 'View Full Document'