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## mat 117 appendix E (brand new)

by: smartwriter Notetaker

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# mat 117 appendix E (brand new)

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smartwriter Notetaker
CSU - Dominguez hills
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mat 117 appendix E (brand new)
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This 0 page Study Guide was uploaded by smartwriter Notetaker on Monday November 16, 2015. The Study Guide belongs to a course at a university taught by a professor in Fall. Since its upload, it has received 10 views.

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Date Created: 11/16/15
Axia College Material Appendix E Radicals Application Practice Answer the following questions Use Equation Editor to write mathematical expressions and equations First save this file to your hard drive by selecting Save As from the File menu Click the white space below each question to maintain proper formatting Hint for this assignment Pay attention to the units of measure You may have to convert from feet to miles several times in this assignment You can use 1 mile 5280 feet for your conversions 1 Many people know that the weight of an object varies on different planets but did you know that the weight of an object on earth also varies according to the elevation of the w C rquot2 object In particular the weight of an object follows this equation where C is a constant and r is the distance that the object is from the center of the earth a Solve the equation wCr2 2 W r C LK r2 C 2 C r w MAT 117 b Suppose that an object is 100 pounds when it is at sea level Find the value of C that makes the equation true Sea level is 3963 miles from the center of the earth W C r 2 C W r2 C 100 x 39632 C 1570536900 c Use the value of C you found in the previous question to determine how much the object would weigh in i Death Valley 282 feet below sea level w C f2 282 feet 2 0053 miles 3963 0053 2 3962947 Death Valley is 3962947 miles 3 th e center of earth wCr 1570536900 39629472 W 1570536900 1570494892 w 100003 pounds ii The top of Mt McKinley 20320 feet above sea level MAT 117 5280 feet 2 1 mile 20320 5280 miles Therefore 20320 feet 2 20320 feet 2 3848 miles 3963 3848 2 3966848 wCr w 1570536900 396684 82 w 1570536900 39668482 W 1570536900 1573588306 w 299806 pounds D 12Z The equation gives the distance D in miles that a person can see to the horizon from a height h in feet D 12Z a Solve this equation for h D 12 M 12 12 20 12 squaring both side s MAT 117 2 D l 144 fee h b Long s Peak in the Rocky Mountain National Park is 14255 feet in elevation How far can you see to the horizon from the top of Long s Peak Can you see Cheyenne Wyoming about 89 miles away Explain your answer D1214255 D12 119394 D 143279 miles Yes we can see Cheyenne Wyoming 3 Long s PeakE the Rocky Mountain National Peak it is only 89 miles away 3 the top of the Peak see we can W3 miles a the horizon MAT 117

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