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# Note 10 for ECE 474A at UA

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This 5 page Class Notes was uploaded by an elite notetaker on Friday February 6, 2015. The Class Notes belongs to a course at University of Arizona taught by a professor in Fall. Since its upload, it has received 16 views.

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Date Created: 02/06/15

PRACTICE PROBLEMS 7 Lecture 10 10E 1 8 9 Implement Fa b c Zm2 4 5 Zd 5 a as a Boolean nspace cube b in compact cubical form show the onset FON the offset F0 and the don t care set F Calculate c H d for Using atruth table determine ifFa b c ab ac bc is unate Determine ifFa b c d a c d a c d a cd ac d ab c is unate hint use a Kmap to check the cover provided Given the prime cover of F Fc is the inction F unate FC ANOO N MONO ooom Given the prime cover of F Fc is the inction F unate Fc ANOO ON O N xmo oo xm Calculate the cofactor ofF FAB With respect to the cube c 1 0 2 2 AB Fc o x xo x oo xmm oN xN x o xm xm Calculate the cofactor ofF FE With respect to the cube c 1 0 2 2 AB o x xom oN xmm ON N xmom 10 IfFON1011 2111 0102 0112 andFDc 0012 1201what is F0 a F0 0022 1202 1220 b F0 ltltIgt c F0 lt22021 d F0 1220 0002 e none ofthe above 11 Given c 1 2 2 2 1 2 and d 0 2 2 2 0 0 2 1 1which ofthe following are equivalent to c F d a c F d 1 b c d2 2 2 c c d1 0 0211012 d c d1 0 0111211 e none ofthe above 12 Which of the following statements are true a If a nonprime cover is unate the function is unate b If a nonprime cover is NOT unate the function is NOT unate c If a prime cover is unate the function is unate d If a prime cover is NOT unate the inction is NOT unate e Only a truth table can indicate whether a inction is unate 13 Given the inction cover F shown in Figure 1 what is the cofactor with respect to B Figure 1 Function cover used in 3 Fa lt1 Problem 13 bFB11110 212 c FE 12110 212 d FE 0 0 2 2 2 010 N xoo o xmo N o xmm e none ofthe above 14 Is the function depicted in Figure 2 unate Hint Convert to aBoolean expression Figure 2 Truth table used in Problem 14 a Yes b No c I don thave enough information to tell 15 Ifthe constraint matrix is empty what does this tell us a Expansion ofthe cube will not intersect with the offset b A complete column covering ofB has been achieved c All variables have been assigned to either the lowering set L or the raising set RA d No irther cubes can or need to be covered e Everything that could have been added to the raising set RA is already there 16 Using the blocking matrix in Figure 3 which of the following are valid column coverings Figure 3 TmLh able used in Problem 15 a L 1 2 3 1 2 3 b L lt1 2 1 1 0 c L 1 3 0 1 1 d L 2 3 B 1 0 1 e L 3 0 0 1 17 Fa b c d ab b c c d ad calculateF using espresso s UNATE7COMPLEMENT algorithm Check your answer with a Kmap Be sure to show your work 18 Provided Fa b c d ab bc ad calculate F using espresso s UNATE7COMPLEMENT algorithm Check your answer with aKmap Be sure to show yourwork 19 Using Espresso s COMPLEMENT inction compute Z 0 2 1 0 2 0 1 0 z 2 0 2 1 1 2 2 1 1 2 0 1 2 1 1 1 z 1 1 2 1 0 2 2 1 21 Using espresso s COMPLEMENT algorithm ndF given Fa b c d e abe a ce a b d e a cd e 22 Using Espresso s EXPAND inction expand F 0002 F0121 1112 23 Using Espresso s EXPAND inction expand F n H oo oo ANNNO N O N 24 Using espresso s expand algorithm nd the prime implicaan ofF Ao x xo Now x x ooo x x N Om can 574A 0m 25 Is apnme cw xequxedta guarantee F xsunat mm am explanahan puagaphmax 25 Why dues EINATEjELECT ncan anly Canada 1quot a n ankles m xgmxes 2quot ankles Wm chnasng a splitting vmbm Punalum BINA rrngcn39sv mm a rmtr 5 mm mm he quotmm mmuu v mb c x for phumg The numhurulvnnab m s n Brain lur k V n Begln mm x w E m nu ow llm numbu M mm WHY I m Inc 1 quot mp rmunun rum I 12 s we m Cmml m number nl mm WM 3 I m m Nquot mmH pmlllon End n r max mmDuhDIUHU1relumlUv IruzJU u m Indian 1 w nm and n0 m awn m mum pm mm mm my A wargmax mm um 39 Sclcu m m m D maxmuurs M A 39 quotr nlp llllz m ruunl mum n mun hm vanahk m m 27 Espressa39s comm fuman weds m detemunzs r a mm is male x SD m UNATE700MPLEMNT fmchm is neat Wm pseuda cad um delemunes whe39hexthe funcuanxs male

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