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by: amber weiss

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# Math 112b Chapter 7 Section 2 Math 112b Sec 004

amber weiss
SIUE
GPA 3.7
elementary mathmatics
cheryl eames

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## About this Document

Here is what we covered last week! Chapter 7 Section 2 Part 2 will be posted as well!
COURSE
elementary mathmatics
PROF.
cheryl eames
TYPE
Class Notes
PAGES
1
WORDS
CONCEPTS
Math 112b
KARMA
25 ?

## Popular in Mathmatics

This 1 page Class Notes was uploaded by amber weiss on Monday January 25, 2016. The Class Notes belongs to Math 112b Sec 004 at Southern Illinois University Edwardsville taught by cheryl eames in Spring 2016. Since its upload, it has received 13 views. For similar materials see elementary mathmatics in Mathmatics at Southern Illinois University Edwardsville.

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Date Created: 01/25/16
Math 112b Chapter 7 Section 2 Dr Eames oz Describe and analyze data Measure of Central Tendency Center gt Mean average add up all the numbers and divide by the number of numbers Exampe 456458657 45645865750 there are 9 numbers 509 the mean is 555 so 56 gt Median middle number you put the numbers from smallest to largest If it is an odd amount of numbers it is the middle number If it is an even amount of numbers add the two numbers in the middle and average them Exampe 456458657 put them from least to greatest 445556678 5 is the median gt Mode which number occurs the most often 445556678 the mode is 5 1 Find the Mean Median and Mode a 33455 Mean 33455 205 4 Median 33455 4 is in the middle Mode 3 and 5 both occur twice bimodal b 1355 Mean 1355 144 35 Median 35 82 4 two numbers in the middle add and divide by 2 Mode 5 c 123456 Mean 123456 216 35 Median 342 35 ModeNo Mode they all occur once 2 Which measures of central tendency must be in the original data set IF EXISTS MODE 3 Which measures of central tendency can be in the original data set MEAN MEDIAN AND MODE 4 A group of 20 students average an 85 on an exam Two more students take the exam and score a 95 and 100 What is the new average We know that there were 20 kids that took the test and their scores the average of 85 We add up the unknowns and the 95 and 100 to equal the known average 85 Xxxxxx x 95100 85 85201700 170095100 189522 8614

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