Class Note for CHEM 112 at UMass(49)
Class Note for CHEM 112 at UMass(49)
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Date Created: 02/06/15
Courses amass e t k chem l2 39 DEER NWVg 3216 H 79m S l What is standard atmospheric pressure mm rs gA awaosThey xc erasure The air pressure at sea level 760 mm Hg 3 760 mm Hg 1 atm 5 01 atm 6 The air pressure in Amherst MA 7 The air pressure in Lander WY J 2 Which letter represents the normal boiling point of water JED 750 mm Hg Pressure mm Hg Diethyl ether has a vapor pressure of 760 mm Hg at 346 C and the enthalpy of vaporization of 281 kJmol What is the a vapor pressure of at 250 C K WWW a 120 mm Hg b 197 mm Hg c 346 mm Hg d 534 mm Hg w 4790 mm Hg J a 1L5 MM 7 L 4quot 3 fUc LL 1 ISOC 2V ZNHmh 1 1 2mm 7qu R g 9 Ed E Q J a 7 I Ty n 71 bu L gt 1quot lt3 1 7 EL 1 WW1 PL 7 T gww gnu ujzgpm 11L anti Hy j mfw R3594 JLw w L l 0 I a 1 L1 u L L My 392 C 1 T39 l 1Lo gt vdh MN My 1 an 3395 139LNL quot0564 97 Lu s c hvv 459 419591 w 3mm m MM Lzmwr gnawK AL L 1m m A 1 T2 I m lt EC 377 5 7339511w loaf VLW b 0555 1 qu Jhb a3 Png 29 WM 9 EL CIausiusClapeyron equation Ava lnPWc AH lnPZ J c z AH ilnPl 9 c RT AH AH P AHV 1 1 w jlngiH 29quot RTZ RTl P1 R T2 T1 Why did the lighter have a small ame in Hasbrouck vs a large ame at Thai Blue Ginger 7 A The elevation of Hasbrouck is higher so the pressure was higher B The elevation of Hasbrouck is higher so the pressure was lower The lighter was colder in Hasbrouck so the vapor pressure ofthe butane was lower D The lighter was warmer in Hasbrouck so the vapor pressure ofthe butane was lower E The lighter was warmer at Thai Blue Ginger so the a vapor pressure nfthn hlltnnn mine Inmler 4 9 Wei Phase Diagramg wf lZV sulii A135 MG 10 Why learn about phase diagrams Phase Equilibria Water a 0 Gasliquid GasSolid Pressure mm Hg 453 mm Tempeyam 0c At the three phases are in equilibrium all 13 Phase Diagrams Important Points for Water T C Normal boil point I 0 Normal freeze point 0 Triple point 039 l39 PmmHg 76 76 45 14 Critical T and P As P and T increase you finally reach the CRITIC L Tand P Political Note that line 1 goes strai m Above critical T g a no liquid exists 5 no matter how E Tcritical high the pressure High Temperature gt 15 Critical T and P COMPOUND TC C Pcatm 5 WHZO 374 m u p co2 3t 13 w H4 10 2 4 t Freon12 Ill 4 C CCIZFZ H 4 quot What do you predict Tc and Pc depend on IMF 15 CO2 Phase Diagram Pressure atm E 519 am 4 20 0 Temperature cc Critical point CO2 cri cal point a 8 E 74 W m m E u Temperature K httpl 303 plyCMRcriticalpicshtmi CO2 cri cal point 5 8 9 a m E a Temperature K CO2 cri cal point Pressure bar Temperature K 2O CO2 critical point 8 9 I 574 U m 9 Q Temperature K 21 For 002 what phase Changes occur between 100 C and 10001 aL I GLIII A Solid to liquid B Solid to liquid to gas C Solid to gas D Liquid to gas E liquid to supercritical 1 1 fluid l me am P1255 For CO2 what phase Changes occur between 391OOOC and 10001 at IL aLIII A Solid to liquid like ziisa 1 B Solid to liquid to gas A 1 i olid to gas i y quot D Liquid to gas as E liquid to supercritical fluid m 23 SolidLiquid Equilibria In any system if you increase P the DENSITY will go u Therefore as P goes up equilibrium favors phase with the larger density or SMALLER volumegram Liquid H20 Solid H20 Density 1 gcm3 0917 gcm3 cm3gram 1 Luv ICE 2 LIQUID H20 favored at favored at low P high P 24 SolidLiquid Equilibria ICE 2 LIQUID H20 favored at favored at low P high 1 Raising the pressure at constant T causes water iqgid to melt Send 2 Norm The NEGATIVE SLOPE of H20 freezmg the SL llne IS unique to pomt 760 HZO Almost everythlng mmHg else has positive slope 0 pc 25 l 39S tl39 573am Cn39tl39nalpnint a Liquid Pxessuve atm emu 750 720 u 20 511 Temperature at 26 SolidVapor Equilibria At P lt 458 mmHg and T lt 00098 c solid H20 can go directly to vapor nus process is called SUBLIMATION Can you think of any machine that uses sublimation 27 The vapor pressure of liquid ethane thiol C2H5SH is 100 mm Hg at 260 K A sample of C2H5SH is placed in a closed evacuated 521 mL container at a temperature of 260 K It is found that all of the C2H5SH is in the val or I hase and that the pressure is 570 mm Hg If the volume of the container is reduced to 390 mL at constant temperature which of the following statements are correct Choose all that apply The pressure in the container will be 760 mm Hg No condensation will occur Liquid ethane thiol will be present Only ethane thiol vapor will be present The pressure in the container will be 100 mm Hg WPPJNE P1V1T1P2V2T2 lt see page 554 for review 28 Answers The pressure in the container will be 760 mm Hg No condensation will occur Liquid ethane thiol will be present Only ethane thiol vapor will be present The pressure in the container will be 100 mm Hg LnAwNi A 29 Refer m the rollowlng phase alagram not my sealel for xenon 576 1 oo 1520 161 3 1550 2597 T Kelvin A sample orxenen at a Dressure prn37n atm and a temperature or 145 K ls epmpressea at cpnstant temperature to a pressure orsm atm wnlep or the rollowlng are true amass all that apply The sample ls lnltlallv a gas The sample ls lmtlallv a solm 7 No phase change will occur The Imul initially present will vapprlze Tile nal state prtpe supstanee ls a snim w Kerer tc tne FoHowmg pnase magram not to sca E rcr xermn 57 e 1 00 p aim 037 1520 1613 1550 2597 T Kelvin A Samme crxcnon at a pressure prn7n atm and a temperature or us K rs compressed at constant temperature to a pressure crsm atm wnrcn or tne mummg are lme arms autnatapplv The sample rs mmaHy a gas a mesuunesntrsm suns at us mass change w me Iinum Wth present wm vaponze 51 ms nu stats prtne substance s s son Tne temperature rs ccnstant sc as tne supstance Feed back At Ms K and n37n atm tne substance rs a sum At us K and 514 arm tne substance rs a so rs ccmpresseu tne Domt reuresentmg rts state maves vemcaHv up tne r 145 K une tc nrgner pressures nerer tc tne genersr pnase magram on tne nfnrmatmn page 31
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