Review Sheet for CHEM 122 at UMass(1)
Review Sheet for CHEM 122 at UMass(1)
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Date Created: 02/06/15
Atomic Structure 22 An atom of Fe has two 49 electrons and six 3d electrons How many unpaired electrons would there be in the Fe ion A one B two C three D four 23 Which of these species isare paramagnetic Ti FCZ Znquot A Fe2 only B Znquot only C Ti4 and Fe only D Fe and Zn only 24 Which of these electron diagrams could represent the ground state of the p valence electrons of carbon A E B T J C T D T T 25 The existence of discrete quantized energy levels in an atom may be inferred from A experiments on the photoelectric effect B diffraction of electrons by crystals C X ray diffraction by crystals D atomic line spectra 26 Which emission line in the hydrogen spectrum occurs at the highest frequency39 A 1123 9112 B n4 gtn2 C n7 gtn5 D nlO gtn8 27 Which set of quantum numbers is correct and consistent with n 439 A 3 m 3 mA2y2 B 4 m2 m 12 C I 2 m 3 m D l 3 m 3 m3 l 28 When an atom of an electropositive atom becomes an ion it A gains electrons B becomes larger C emits an alpha particle D does none of these 29 The orbitals of 2p electrons are often represented as being A elliptical B tetrahedral C dumbbell shaped D spherical 30 Helium He has two electrons in the 15 orbital When it becomes singly ionized forming He A its spectrum resembles that of the hydrogen spectrum B the remaining electron is easier to remove C the nuclear charge has decreased by one D it has lost one atomic mass unit Descriptive Chemistry Periodicity 20 2 22 23 24 25 26 27 28 The radii of the ions in this series decrease because lon Ionic Radii NM 0095 ntn Mg 0065 mm Al H050 nm r A the elements are In the same p riotl B the effective nuclear charge is increasing C the atomic radius of Na decreases from Na to A D the first ionization energies increase from Na to Al The species 7 Ne and Naquot all have the same number of electrons Which is the predicted order when they are arranged in order ol decreasing SIZL largest first A F gt Ne gt Na B Ne gt Na gt F C Na gtF gtNe D F gtNa39 gtNe Which isoelectronic ion is he rmaI esl39 A At B Na39 C F D t 03 What happens when a bromine atom becomes a bromide ion A A positive ion is formed B The bromine nucleus acquires a negative charge C The bromide ion is larger than the bromine atom D The atomic number of bromine is decreased by me Which ion has the largest radiusl A er B Fquot C K D Cu2 Which of these elements has the highest electronegativity A oxygen B iodine C cesium D lithium Which element ts more electronegative than arsenic and less eleetronegative than sulfur A chlorine B phosphorus C tin D oxygen List the eiements Ca Si and K in order of increasing electronegativity A Ca ltK ltSi B K ltSi lt Ca C Si lt Ca lt K D K lt Ca ltSi Which pair of elements is listed in order 01 decreasing first ionization energy7 A Na M B Mg Al C Al Si D Si P 100 Molecular Structure and Bonding 21 22 23 24 25 26 The fact that PtNHt3Clg exists in IWo different isomeric forms offers evidence thttt the geometry is A octahedral B square planar C tetrahedral D trigonztl planar Which species has both covalent and ionic bonds A NHgBFx B H10 C NaKS D MgtCNl When the carbon carbon bonds in ethane CHt ethene CZHJ and benzene 2H are arranged in order of increasing length shortest bonds first i what is the correct order A CZH lt QH4 lt CH B C ChH6 lt CIH4 lt CJHA D CgHJ lt on lt chum CJHJ lt Zita lt cznh These two electron dot formulas for carbon dioxide both satisfy the octet rule but one is preferred over the other Which of the statements identifies the preferred structure and also the reason it is preferred Eizcnzo oc39d Structure 1 Structure 2 A Structure 1 is preferred because the triple bond is stronger thtm the double bond B Structure 1 is preferred because the formal charge on cztrbon is negative C Structure 2 is preferred because the formal charge on each atom is zero D Structure 2 is preferred because the bonds are equal Which element is most likely to form it triple bond A Pb B F C N D S 3 3 Which is an isomer of H g O C gdl H H H A If If I B If 51 Hlf gg OH H Cf O f H H H H H C t t 5 D If it H g li OClI H H C1 O lf H H H H H 18 Smichiometry l1 1 quot l4 17 20 A 3 4 1 ll g umplc ul u unmnund lmmn l0 cmtlutn 4 t7 110 molc tulcx 39l lu unnmnund H Al 390 B CH C Avmzam39n s tturnhcr cquul tltc number nl Al tumm m mte nulls tll39atums tlll Cl murhlcs tn mu mnlc 0139 quot1311 le m NHx ID Hp umluuulc ut llllf mrllt39 ml 0 all nt the ahm39c Tllt number nl tuums n L70 g ol39ttlummum H thc mmc as the numhur ul Mmm m LA N l g ml nutgnesnnu lBl C I I g ut magnesium DI A angle molecule ul ll comm cumplluml hm a mum of 34 lt ll T the musk er mole m um t39ttmpmmt l A in gumr th um gaunt I0 mm must of Kctol wm product 430 g m tmgcn 0 1139 thv dowmpmttmn V1 KCIO in t txmplctcy 9 t 51 ul39 mugncstum m1 or luagnEStum q 150 gtnn ID t Whtsh value mum s closest ll gongmotquot A hng Bl 745g 10 What hi the mnxtmum mass ol tlttmtnum chlnt 1th that could be xhtutncd lt39nm LOU nwl t ll39httt39tum chlnndt And CAUC alumutum sullate Thu 1 the halancctl cqtmlioll far In rcztcnmt l lSOt BnCl A 3618041 IAICL lAl USU Bl 80 C 3911 Formula olar ta KUO l225 gvmol 132 5 Dl 2450 g Formula Mnlar Mass BAG 2083 g39mnlquot AlCl 1133 gmnl 39 534 l D H43 A cllxlmtuined lueztthmg tppamlult nst mmmm mpcmidc KO m t39nmcn he ctuhnn dioxtde and ucr tn exhaled tu intn Mygcu a huwn by lhh cquattnn 4K0 l am m ZHVO at H 4KHCOm tow me ntun moleculm ol tvxygen gm will he pmduccd from the 004 g ml turhon dmxldc that IS eKltuchl In A lyptcal hrcuth39 A 4 x x It In 64 xttfquot 10 35 xtuiquot D 19 XlO A mlxltuc L Unlmnlttg l mrtl Mr F and 4 nml ut 5 xx allowed U tcutt 39I39lm equntmn tcpments the ream mt llutt tutu plat RF 5 v SF Haw lllull mult or F mum after 3 mnl twa hum rcacled 1A 4 lBl 3 CI l D l thn 115 of a mmulllt mut ls reduced mm excecc Idmgcn l 054 g ml the ntutal n pmdttcrdl What w M metalGC nude AI Ago Bl CuVO Cl KJ Dl T120 How many nmlcx of ll39Ul39l l L Ct wuh 175 mm of oxyguu uttx The equulton lnr tltc t39enctmn l 10tw1Fe4r 3 A ll mol 1 l 75 nul Cl 28 30 u 213 quotml DI 535 mtyl States of MatterSolutions 11 The graph shows how he vapm39 pmsure m a 11un L00 changes ilh lcmpemlurc Select he chnIL c that hm 9w mahcam the degree of correctness at Ins statement Rm quotTm rmrrrml boiling ml11 nfrw liqmd 78 r 7m mo sun 4m mu ml MU l l l Vapor l rcssurc mm Hg O l 0 ID 20 El 40 50 U 70 80 QUIUU T C A The Slalemcnl 15 we Bl The slammem is pmhabh Irue uddumnal lulu would be nccdud fora final dtmsion CI The women 1x pmhably false additional data would be necdcd Bra le decision D The slntemanl l5 false 12 Wlul l the molar mu m an ideal gm ll a n 622 g mmple m39lhls gm VCL UIJIC u wlume M300 mL at 35 39C and 789 mm Hg A 443 gmulquot B 489 gmnl Cl 505 g mol DI ul 4i gmal 13 Whlch 52 ml enwcmlure and plcwlre candmuns will came a game exhlhn lhc gmmesl dcvmuon 39nm mm gm helmva m we C am 4 mm Bl 00quotC39m1d 2 mm Q 400 39C and 4 mm 10 l C und 2 mm J4 A 500 ml gas samplc ls ollecmd uvcr water 2111 g prcmrc m 740 mml nd 139 T Wm 5 e muume or me dry gas at STP ST 1 aim w 1 39CJ 4 quotquotHE 739 2 V W SOOXM 98 B 500x 750 27 760 208 397 77 7 7 39 Ll SWX 3960 X H D 500x 60 95 740 24 298 740 24 1 1 Which dlngmm I eprcpcnls me most concenmted solul wn 7 Iulu rcpreVenN a Llme parllulc md a I Cpruscms a water molucule 08 08 in 66 3833 as t gyw 1 11 111 A1 I 13 n 10 1 ma IV Energetics 20 21 u 5quot N P 25 26 Use lhc gncn heats wt Iormauon to calculate lhc Compound Am kJ39mol391 cmhalpy change for this rcac on I S B2071 mockw a 25cm 3C0 53 4038 71935 A 694 H 1B 354 9 k C gt58 9 k I 73917 kl Using me givcn lhcmmchemlcal dam when w ompnund AHK kJm9r1 AH for his reaclinnquot 1 8 2CHOH1H 0191 HCIH OyEI 2HO 4 7386 A 583 k B 513 k C 4381 H D 7535 kl thu IS the exnhmpy change for Ihls rezclinn3 Compnund 311 kJmmquot Hgl1 ug mq a Hgi yuq ZAgn 1016 I7lI LA ASKS H B 40 kl j 401 k D 475 3 k For whlch m Illese processes Is the vuhuc nf AS expeued h be ncgumc I Sugar 1 dlssolved in Wulen JL Steam 1 mdcns cd III C uCOz is decompoced mm C30 and 3903 A Ian 1 lund III uni C II only D II and III nnl Fur which pmcc is the entropy change per mulc the lurgcsl a Conslanl lempuumru m HIOvir Irlom m H4 4 H30 C H20 Hpm m H10m a HIOxr In wlnch process is elllmpy damned My dnssohing sugar m water H c pandlng A gas C evapmuug a quuid L D rrcmng mler thn a mum cvaporates whxch is uuu ubuul he signs of the enthalpy and cnlropy changes A AH H pm iliw AS is posmve 3 AH is pOS1HVeASlN ncgulixu C Hsv1tguliu is posim e ID 3ng negame AS it nugamc A particular chemical rcucrion has n ncgmwe AH and A ncgdlhc AS Which Armament H Corrcclquot ml Thr renulwn n spontaneous at ull cmpcmlurcx B The reamion is nonspunluncous m all Iempemturca C The rcucn un hcmmcs spontaneuux m lampcmmro increases D The rcmmn hccomcs sponmneuus b cmpmuurc durum 52 Dynamics 21L A unulm murmurs hc ms 11 u Icucuon h A chungmg lhc mm lmnhm 111111 rmumn B mercasmg he actualwn energy 1111hcrc1c1mn 1C 1nvn 1mnglhc mnccnlmmm lt11 1I1L nrm1vrunl39lhu prudLILh 1D dcclczmng the AJHTL rcm39c m n luuw cm lg ol hr n udunh1111lpl111lurh ll Conmdur lhc rcuuwn Chum139 115 4 Sm v 211111114 1cm The raw equanon Ior KhIsreaunon 1 mm L C H 11151 Winch 111391hcsc 111CL1mn1smgt1gt mr 11m cunmtcm mm 11m mtg eqmuvn l CIHSgtH I 4CIAHS Mmm 139 HS gt H39 1 S 1111le II 115 H39 115 111151 cqu11hr1un11 CIHS 2C1quotH39 9 Mkml 1A lonlv B I on C Bmh I and 11 D1 Ncuhcr 1 ur II 22 A ucrlzun rmclmn h1AAl 5 H 1m 1m 1111111111111 cucugv 11139 411 LJ 7 mulymlmmd111al1ltmc1 th Aclhuuun cnc u1 1hc1mwrd rcacunn h 15 H Whul1sthcnruumnm cncrgy 011m rump rcaculm 1n 11w pr once of 1111s same Hualpl A 25 k B 60 k1 00 1D IOOkJ 231 Whm 1x the 1elanmvsh1p beween he ethhrmm consmm 1K3 m a rcacunn and 111 mm conunnm 101 111 mnmrd 1A and rc39e1sek klreaclwn 1A f Auk B k 4 C K 111 24 I1 11chal1y11c m 1 chcuon 151ndupcndcn1 m wnu39mmuun lhc mmmn um he I w order 11 ltecnml m39dm 111 mm mrlcv A I and II uni m I and 111 1111 1c Innly rm 11 onl 25 1mua1 m1 dam 1011110 rcacunn I Epcr1mcn1 H4 1011 Rm 111 1 1 2111x141 H 31mm 1 11011111 1 11mm 5 gtlt 10 inc gncn 111 hemhle mm mhe 2 0030 1 quot 3 M l 5 K W 39 rulelaw39imvhmreacum 3 won M 11002 M 1 3 x 10 4 HHISO M 10010 M 0 lt X10 L w 11112AL39H Bu nuczurw 31 r11lekiH1 1D1 131CMH3HCH 64 Equilibrium l3 Cumldcr Um mmmw mmcd mu m unmmm mnrcmunc md mhmxc 9 15 Mm lt Ihe clleul nmmm mg mmu 30 mm IEII mmth H Cthhnum A lhc cunwnnuuun ml 50 rcax cx mum than Hm wucsnlmlmn n O m H1 nllcrnlruuun m 50 Incx emcx mm mun Iw mnucmmnon nr 0 C W ovncummlwn Ul SO1ndI39mn1n lhq mm D Thu Luncentrunnn M 50 And 0 van squall Conth Im ruman rmm m2 1 mnmuu mnpcrulurc and ohlmc Paws m m ch Haw um rho pmmun m cthhnum 1m hlS I mumn be mad m Hm right39 A Ilddmm m 1 mm B mmm39u M 391 0 mldinnn m39 m mun gas a mnsmm mlumc 139 remmul m PH 39mmdcn lhu rcncunn hear 150m C m 505 39hll L hiu vhcn ulmllhrulm ilt rerextuhlixhcd ull an an increase III the rmmlc II39 50 B IN D CI Increaxsmg r39ne renmnn mmpcmun decrewng th ulumc ur lhc cumamer uddmg wmc mam Case rcmm mg mmc hi the CnOm in xhhh rquot nun would an mocha m prcwurc u u vnunnl mnpemhne hmc no cum on the remme ummmh nf he sulwtzmcm 1C5L m m the cquxhhnum mmurcl AH uhuunum are R D 1505 A l 390 0 2N01th hem N 0 2N0 C N 3H ZNHR hem 2C0 O 1C0 heat The numemu uhlc vl 1hr cthhrimn mmmm for any chemical lengc i ufch lcd by dmngmg he r D nulurc txl39 lhc mm IA 10 L39nnccmmlinn or the produus he prmxurr he cn39mcmluru Rom1 carbnn and mum Jrhon mmldu me when m A chimed mm and Alhmcd m mm m athhrmm ul 1 high cmpcmlun acnvrdmg m Ih S equalinn cow 2C0m H lhc pressure nu ma syltlcm l in rmhcd me 1hc lcmpcmmx39c tap mm4m I141 ull he the resuhquot hCJl LU By Hu m39nnunl n CO ull macaw anI Ihzn nl lquot uml CU nxll lccr c The unmum u CO xih drum v and mm on and 0 Will uer Thu mmunl or such u the f ubmm u will nurcnsc The amount at each of the Ihlcc suh imLLW will dunquot xx 76 Electrochemistry and Redox 10 11 12 l3 14 15 16 17 Balance this ionic equation for a redox reaction using only whole number coefficients MnOJUIq Fe211 HJOqu Mn2lq Fephlq HQOH What is the coefficient for Fe2 in the balanced equation A 1 B 3 C 4 D 5 When this oxidation reduction equation is balanced in acidic solution using only whole number coefficients what is the coefficient for Sm 03071 qu sthzq gt CT11q SH A 4 B 3 C 2 D l Which of these ions is the best Standard Reduction Potentials EO reducing agent F63uq e gt Fezvuq 077 V CU2m 67 CUWuq 015 V A Fe B Fe C Cu D Cu A quantity of a powdered mixture of Standard Reduction Potentials E zinc and iron is added to a solution 136qu ee pehmq 077 V containing Fe2 and Zn2 ions each at 2 unit activity What reaction will occur Few 4 26 Fem 03944 V Zn 1c 267 st 076 V A Zinc ions will oxidize Fe to Fez B Fe2 ions will be oxidized to Fe3 ions C Zinc ions will be reduced to Zinc metal D Zinc metal will reduce Fe ions Two metals are represented by the Standard Reduction Potentials E symbols L and Z Which is the best LBW 26 LU 076 V i V 7 oxtdizmg agent listed Zvuq 67 Zm 080 V A L B L C 2 D 2 Which combination of reactants will Standard Reduction Potentials E produce the greatest voltage based on Cum gt Cum 052 V 1 u these standard electrode potentials thmq 26 a thmq 0 I 5 V Cr3aq 6 7 gt CrZqu 4l V A Cu and Sn2 B Cu and Cr C Cu and Sn2 D Sn4 and Cr2 What is the standard electrode Standard Reduction Potentials E potential for a voltaic cell constructed Crhmqy 3679 Cm 3974 V in the appropriate way from these two C01mw 26 COM 4128 V halt cells A l 02 V B 046 V C 064 V D 102 V What is the standard cell potential E Standard Reduction Potentials E0 for this reaction anmiq 26 Mnm 11 8 v 3M0 2AUC147W1 gt AuCl uq 3e39 gt Auto 4Cl aq 100 V 3Mnuq 2Auv 8Cluq A 018 V B 218V C 28V D 554V 86
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