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## Physics 2- PHYS 1302 Week One Notes Chapter 19

by: Alexis Clowtis

103

2

5

# Physics 2- PHYS 1302 Week One Notes Chapter 19 PHYS 1302

Marketplace > University of Houston > Physics 2 > PHYS 1302 > Physics 2 PHYS 1302 Week One Notes Chapter 19
Alexis Clowtis
UH
GPA 4.0

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These notes cover the first day of class which is half of Chapter 19: Electric Charges, Forces, and Fields. This set of notes covers through electric field lines.
COURSE
introduction to physics
PROF.
Mini Das
TYPE
Class Notes
PAGES
5
WORDS
CONCEPTS
Physics, electric field, forces, Charge
KARMA
Free

## Popular in Physics 2

This 5 page Class Notes was uploaded by Alexis Clowtis on Wednesday February 3, 2016. The Class Notes belongs to PHYS 1302 at University of Houston taught by Mini Das in Spring 2016. Since its upload, it has received 103 views. For similar materials see introduction to physics in Physics 2 at University of Houston.

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Date Created: 02/03/16
Physics 1302- 1pm MW SR1 116 Professor Mini Das Chapter 19 1/20/2016 19-1 Static Electricty Normally things have a neutral charge when charged=force Like charges repel, opposites attract Magnitude of electron’s charge is the same as proton’s Induced charge- charged rod picking up attached pieces of tissue (tissue is neutral) Total electric charge of the universe is constant Conductor- induce charge into metal, it flows through metal Insulator- plastic rod charged in one place, doesn’t move Stay away from each other farthest spread at surface = induction Charge stays on surface of conductor because same charge so repel each other Coulomb’s Law ???? = ???? |????1|????2| Units: Newtons (N) ???? 9  K= constant=8.99 X 10 N  q= charge Units: Coulombs (C)  r=distance Example: Force on q1 by q2 is in the positive x direction Q1= 1C Q2= -10 C F=10K 19-3 Coulomb’s Law If multiple point charges, forces add by superposition Forces of charges as vector sum, figure out overall direction and magnitude of force From professor’s slides Physics 1302- 1pm MW SR1 116 Professor Mini Das 19-4 Electric Field Electric field has a direction ⃗ ???? ???? = ????0 Units: Newton/Coulomb (N/C) If only 1 charge in a neutral area, no force. 2ndcharge introduced and it’s a field qois a positive “test charge”- serves to allow electric force to be measured ???? ????| ???? = ????2 ???? = ????????⃗ Direction of force depends on sign of charge 19.5 Electric Field Lines “If I put a test positive charge here, which way will it move?” -Direction which positive test charge would move (AWAY from positive charge in 3D) What happens to the test positive charge is the direction of the electric field lines *Always start in a positive charge and end in a negative charge* Field lines are straight in capacitors Example -Both are positive -Density of field lines tell magnitude of force -Density of field lines are greater closer to the charge -Force due to charge gets smaller as you move away because r 2 increases, F decreases Physics 1302- 1pm MW SR1 116 Professor Mini Das Conceptual Checkpoint 19-2 F=ma  smaller mass accelerates more, meet closer to proton because the electron moves faster  B is the answer Conceptual checkpoint 19-3 FnetA<F netB F 1xd F can2xl but F +F =R1yres2ytayt) R=0 at A Conceptual checkpoint 19-4 Enet at point P is upward Magnitude of q =1agnitude of q so 2oth of them identified as just q The difference in the two is the sign The electric field tells what a positive test charge would do if you put it at P (no charge at P) Answer: B q1 is negative, q2 is positive because that is the only way a positive test charge would go straight up at P Physics 1302- 1pm MW SR1 116 Professor Mini Das DIY Example 19-5 Need to find E1 and E2 first 9 −6 ???? = ???????? = (8.99????10 )(2.9????10 ) = 52142 = 5.21????10 ????/???? 1 (√2????) 2 2(.5 ) 9 −6 ???????? (8.99????10 )(2.9????10 ) 5 ????2= (????)2= (.5 ) = 104284 = 1.04????10 ????/???? Then to find the resultant of the two, find the components of each and add them using the rules of vector addition. E2 is only in the x direction, so there is no y component. ???? = ???? cos45 = 36840 1???? 1 ????1???? = ????1sin45 = 36840 ???? 2????= ????2 5 5 ???? ???? 36840 + 1.04????10 = 1.41????10 ???????? ????ℎ???? ???? ???????????????????????????????????? ????????= 36840 ???????? ????ℎ???? ???? ???????????????????????????????????? 1.46????10 ???? ???? = √( 1.41????105)2+ 36840 = 145578.7 = ???????????? ???? ???????? 36840 ???? = tan1 = tan−1( ) = 14.67° ???????? 140840 Physics 1302- 1pm MW SR1 116 Professor Mini Das Professor’s Example Find the net force on q3. q1= -5.4 µC q2= -2.2 µC q3= +1.6 µC ???????? ???? (8.99????10 )(1.6????10 ????)(5.4????10 ????)−6 ????1= 1 3 = = −0.14???? ????̂ ????2 0.752 ????????2 3 (8.99????10 )(1.6????10 ????)(2.2????10 ????) −6 ????2= 2 = 2 = 0.51???? ????̂ ???? 0.25 Fnet +1 =0251N-0.14N= +0.37N in the positive x direction Key Values: -31 Mass of an electron= 9.11x10 kg Mass of a proton= 1.673x10 -2kg Mass of a neutron= 1.675x10 -27kg -19 Magnitude of an Electron’s charge= 1.60x10 C

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