New User Special Price Expires in

Let's log you in.

Sign in with Facebook


Don't have a StudySoup account? Create one here!


Create a StudySoup account

Be part of our community, it's free to join!

Sign up with Facebook


Create your account
By creating an account you agree to StudySoup's terms and conditions and privacy policy

Already have a StudySoup account? Login here

Physics 151 week three notes

by: Breanab

Physics 151 week three notes PHYC 151 001

Marketplace > University of New Mexico > Physics 2 > PHYC 151 001 > Physics 151 week three notes
GPA 4.1

Preview These Notes for FREE

Get a free preview of these Notes, just enter your email below.

Unlock Preview
Unlock Preview

Preview these materials now for free

Why put in your email? Get access to more of this material and other relevant free materials for your school

View Preview

About this Document

These notes cover everything on the exam
General Physics
Dr. Dave Cardimona
Class Notes
25 ?




Popular in General Physics

Popular in Physics 2

This 3 page Class Notes was uploaded by Breanab on Monday February 8, 2016. The Class Notes belongs to PHYC 151 001 at University of New Mexico taught by Dr. Dave Cardimona in Winter 2016. Since its upload, it has received 9 views. For similar materials see General Physics in Physics 2 at University of New Mexico.


Reviews for Physics 151 week three notes


Report this Material


What is Karma?


Karma is the currency of StudySoup.

You can buy or earn more Karma at anytime and redeem it for class notes, study guides, flashcards, and more!

Date Created: 02/08/16
Chapter 3: Vectors and Motion in Two Dimensions 3.1 Using Vectors recall discussion in Section 1.5 3.2 Using Vectors on Motion Diagrams For example: circular motion 3.3 Coordinate Systems and Vector Components Vector Components Looking for resultant vectA+ B = R Given A and B vectors. Then findR x A +xB xand Ry= A y B y “SOH – CAH – TOA” Find Ax, Ay, x ,y. Finally finR and θ using the above. R 3.4 Motion on a Ramp X 3.5 Relative MotionX 3.6 Motion in Two Dimensions: Projectile Motion A projectile is an object that moves in two dimensions under the influence of gravity and nothing else. Projectile motion is made up of two independent motions: uniform motion at constant velocity in the horizontal direction and free-fall motion in the vertical direction. 0 height The horizontal and vertical components of θ projectile motion are independent of each other. 0 BUT … They are connected by the time. range A projectile follows a parabolic trajectory because it "falls" a distance ½ g t below a straight-line trajectory. horizontal vertical x = v t y = v t − 12g t2 0x 0y a = 0 a = −g x y v x v 0x v = v − g t y 0y (time, t, connects the two directions) where v = v cosθ and v =v sinθ 0x 0 0 0y 0 0 € Two €pecial formulas: height and range At x = R , v x v 0xand vy= −v 0y Aty = h ,2v y2 (top of mot2on) Then: x = v0x ⇒ t = R v 0x Then: v yv 0y =2a y ⇒ −v 0y =2 ( )h and: vy= v 0ygt ⇒ −v 0y= v0y g R(v 0x) € € 2 2 2 2 v0y v0sin θ 0 € 2v0x €y v0sin2θ 0 OR: h = = € OR: R = = € 2g 2g g g € € For horizontally-projected objects (wherv = v and v = 0 ), take ‘down’ to be positive and use: 2 0x 0 0y € x = v0x y = 2g t € € € y If one ball is dropped and one € € is projected horizontally from the same height, which hits the ground first? x 3.7 Projectile Motion: Solving Problems EXAMPLE 3.11: Dock jumping If a dog runs at 8.5 m/s straight off the end of a dock that is 0.61 m above the water, how far will the dog go before splashing into the water? EXAMPLE 3.12: Checking the feasibility of a Hollywood stunt In the movieSpeed:A50 ft (15 m) section of a freeway overpass is missing.Abus must jump over the gap. The road leading up to the break has an angle of about 5°.Aview of the speedometer just before the jump shows that the bus is traveling at 67 mph (30 m/s). The movie bus makes the jump and survives. Is this realistic, or movie fiction? Range of a projectile: Trajectories of a projectile for different launch angles 3.8 Motion in Two Dimensions: Circular Motion Uniform Circular Motion: Constant speed, but constantly changing direction results in a non-zero acceleration – but NOT in the direction of motion. It is ‘center-seeking’ or ‘centripetal’. ! ! Δv = v −v! Δv −v 1 2 1 2 v a = a = v 2 c r r € € € “Period” =T = time for one revolution € “Frequency = f = number of revolutions per second =1/T Speed in uniform circular motion =v= distance/time =2 π r / T EXAMPLE 3.15: Acceleration in the turn Female world-class speed skaters can cover a 500 m track in 45 s. The most challenging aspect of the race are the turns. What is the magnitude of the centripetal acceleration experienced by the skaters if the tight turns have a radius of 11 m?


Buy Material

Are you sure you want to buy this material for

25 Karma

Buy Material

BOOM! Enjoy Your Free Notes!

We've added these Notes to your profile, click here to view them now.


You're already Subscribed!

Looks like you've already subscribed to StudySoup, you won't need to purchase another subscription to get this material. To access this material simply click 'View Full Document'

Why people love StudySoup

Bentley McCaw University of Florida

"I was shooting for a perfect 4.0 GPA this semester. Having StudySoup as a study aid was critical to helping me achieve my goal...and I nailed it!"

Anthony Lee UC Santa Barbara

"I bought an awesome study guide, which helped me get an A in my Math 34B class this quarter!"

Steve Martinelli UC Los Angeles

"There's no way I would have passed my Organic Chemistry class this semester without the notes and study guides I got from StudySoup."


"Their 'Elite Notetakers' are making over $1,200/month in sales by creating high quality content that helps their classmates in a time of need."

Become an Elite Notetaker and start selling your notes online!

Refund Policy


All subscriptions to StudySoup are paid in full at the time of subscribing. To change your credit card information or to cancel your subscription, go to "Edit Settings". All credit card information will be available there. If you should decide to cancel your subscription, it will continue to be valid until the next payment period, as all payments for the current period were made in advance. For special circumstances, please email


StudySoup has more than 1 million course-specific study resources to help students study smarter. If you’re having trouble finding what you’re looking for, our customer support team can help you find what you need! Feel free to contact them here:

Recurring Subscriptions: If you have canceled your recurring subscription on the day of renewal and have not downloaded any documents, you may request a refund by submitting an email to

Satisfaction Guarantee: If you’re not satisfied with your subscription, you can contact us for further help. Contact must be made within 3 business days of your subscription purchase and your refund request will be subject for review.

Please Note: Refunds can never be provided more than 30 days after the initial purchase date regardless of your activity on the site.