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# Class Note for STAT 427 at OSU 02

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This 4 page Class Notes was uploaded by an elite notetaker on Friday February 6, 2015. The Class Notes belongs to a course at Ohio State University taught by a professor in Fall. Since its upload, it has received 18 views.

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Date Created: 02/06/15
STAT 427 lVIidterm 11 Winter 2004 Prof Goel MWF 1030 1120 NOTES This is a closed book examination Please write your name on each sheet You can use your own calculator and a single sided 85 x 11 crib sheet There are four problems worth a total of 50 points You must explain each step in your answer to get partial credits Good Luck Problem 1 7 points The average thickness of plastic casings for magnetic disks is normally distributed with a mean of 15 mm and a standard deviation of 01 mm What is probability that the average thickness of a randomly selected plastic casing is between 135 mm and 17 mm P135 s X 317 Ps Z s P 15 3 Z s 20 ltIgt20 ltIgt 15 where I is the cdf of the standard normal distribution Using Normal Table the above expression is equal to 9772 0668 9104 Problem 2 9 points A trial has just resulted in a hung jury because eight members of the jury were in favor of a guilty verdict and the other four members were for acquittal The jurors leave the jury room in random order and each of the rst three leaving the room is interviewed Let X the number of jurors favoring acquittal among those interviewed i 6 points What is the probability distribution of the random variable X In a total of N 12 jurors M 4 are in favor of acquittal N M 8 are in favor of a guilty verdict and n 3 jurors are randomly selected for interview The pmf of X is 4 8 x 3 x PX x 39x 0123 1 2 3 This is a Hypergeometric Distribution Ifyou have time you can calculate the value of these expressions The pmf is given by x 0 1 2 3 pX 1455 2855 1255 155 ii 3 points Find the mean of the random variable X From the formula the mean of the Hypergeometric MNn 4123 1 1 of 4 pages Problem 3 16 points A manufacturer of ashlight batteries wishes to control quality of its product by rejecting any lot in which the proportion of batteries having an unacceptable voltage appears to be too high For this purpose out of each large lot 100000 batteries a certain number of batteries are selected at random and tested a 5 points If at least 5 of the 25 tested generate an unacceptable voltage the entire lot will be rejected What is the probability that a lot will be rejected if 20 of the batteries in the lot have unacceptable voltage Let X of batteries among 11 25 selected at random that generate unacceptable voltage Since the lot is very large one can assume that each draw is an independent Bernoulli trial with probability of Success 02 Hence X has a binomial distribution with n25 and p02 and ProbLot is rejected PX z 5 1 P X s 4 1 Bi4 25 2 1 0421 0579 b 5 points If at least 15 out of 1000 tested generate an unacceptable voltage the entire lot will be rejected What is the probability that a lot will not be rejected if 1 of the batteries in the lot have unacceptable voltage In this part X has a binomial distribution with n1000 and p001 However since 11 is large and p is small we can use Poisson approximation ie X has Poisson distribution with I np10000110 Using the Table for the cd we have ProbLot is not rejected PX S 14 F14 10 917 c 6 points If 20 of the batteries in the lot have unacceptable voltage and 900 batteries are tested nd the 67111 percentile for the number of batteries that have unacceptable voltage among those tested In this part X has a binomial distribution with n900 and p02 thus 11 is large but p is not small so we can approximate the Binomial by a NORMAL distribution with p up 90002 180 and variance npl p 18008 144 Thus the standard deviation 039 12 Now from the normal table the 67 11 percentile of a standard normal distribution is Z57 044 Hence the 67 h percentile of the X distribution is given by p O39 z57 180 1244 18528 2 of 4 pages Problem 4 18 points A small accounting firm does not own computing facilities It leases these facilities from Arthur Enron Inc AE1 on an hourly usage basis The firm must plan its computing budget carefully and hence has studied its weekly usage of AEI s systems Suppose the weekly usage X in hours has the following probability density function pdf Lx 0Sxlt10 100 1 x 20 x 10Sxlt20 f 100 0 otherwise a 5 points Find the probability that the firm s usage of AEI s computers next week will be at most 15 hours 15 10 x 1520x 2020x PXS15fxdxmdx 100 dx10 100 dx 005 0 0 10 15 1 area 0f the triangle to the right 1 125050875 15 20 b 5 points Find the probability that the firm s usage of AEI s computers next week will be between 8 and 12 hours 12 dxJ20 x 100 10 x dx 100 12 10 P8 SXS12 fxdx 8 8 Since the pdf is symmetric around 10 this area is equal to 10 x P8 s X s122 dx 036 8 100 c 8 points Suppose that AEI charges the firm 200 per hour for its system s use but the minimum amount billed in a week is 1000 irrespective of the time used Express the weekly bill amount for computer usage as a function of X Find the expected amount of weekly expenses for leasing computing facilities from AEI Note that whenX is less than or equal to 5 hours the amount billed to the firm is 1000 and when the X is greater than 5 the amount billed is 200 X Thus the amount billed is a function of x given by 1000 x S 5 1100 200x xgt 5 3 of 4 pages Now Expected amount billed EhX j hxfxdx I 1000 fxdx j 200xfxdx 2 10 x 20 0x 1000P XSS 200 dx 200 dx xiloo x100 2x3 10 2x3 20 3 10000125 3 8000 4000 125 3 3 20x2 5 10 145833 4 of 4 pages

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