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Notes for test 3 up to 4/14

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by: Mary-elizabeth Notetaker

Notes for test 3 up to 4/14 PHYS 221

Marketplace > University of Louisville > Physics 2 > PHYS 221 > Notes for test 3 up to 4 14
Mary-elizabeth Notetaker
U of L

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About this Document

These notes contain material for exam 3 up to 4/11.
Fundamentals of Physics I
Dr. Raymond Chastain
Class Notes
Phys 221, physics 1, Fundamentals of Physics, Physics, Physics I
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This 6 page Class Notes was uploaded by Mary-elizabeth Notetaker on Thursday April 14, 2016. The Class Notes belongs to PHYS 221 at University of Louisville taught by Dr. Raymond Chastain in Spring 2016. Since its upload, it has received 20 views. For similar materials see Fundamentals of Physics I in Physics 2 at University of Louisville.


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Date Created: 04/14/16
Some on test 2 notes GW1:block mass m1=10 at rest on rough horiz surface.Connected to hanging mass m2=15 by massless string across massless frictionless pulley.Speed of blocks after released and fallen d=1.5m if coeff btwn block 1 and surface is uk=0.5? Same question w angular speed of pulley Ex2) hoop w radius 0.5 and m=2.Rolls w/out slipping 1.5m down plane inclined at 30 deg above horiz.Speed of hoop at bottom? Angular speed at bottom? • KEtrans- if obj center of mass moving • KErot- if obj it rotating about its center of mass • Work done by constant force/torque. Usually cos180/0(+1,-1) • PEg-When height of center of mass moves (Peg=mgh) h in cm • Static eq- when all F=0(in x & y..Trans eq) andT=0 (torques) ⿞probs: ‣ 1) extended FBD ‣ 2) coordinate system & pivot ‣ 3) break f's into x & y components ‣ 4) set up ‣ 5) Calc mag & dir of torque about picot for each f acting on obj ‣ 6) set up ‣ 7) solve for unknowns • Ex1) fiver weighty 500N at end of dive board 4m and negligible mass.Board fixed or 2 pedestals separated by 1.5 m.Mag and dir of f on board by 2 pedestals? Gw1) same board,diver,pedestals...Board mass is 200n Ex2) ladder 12m and 15kg leans against frictionless wall at 30 deg angle w wall.Mag of f on ladder from wall and ground? (friction on ground or ladder would slide) PP1) a)78deg b)70deg Spring-and-mass system Gw1:mass attached to spring pulled away from eq released at t=0.Mass undergoes simple harmonic motion. long would you have to wait for the first 2 times for the following to occur: a)Max speed b)Mass to original position c)mass stops d)All E of mass in KE e)All E of mass is PE a)when mass at eq..t=0.25T & t=0.75T (1/4) (3/4) (5/4) (7/4) Etc [continue to add .25] b) t=1,2,3,4,5 Etc c)at amplitude(A)....every t=0.5T d)at eq(moving fastest...all KE,no PE)..same as (a) e)atA bc speed=0 so all E in PE,no KE..same as (c) Ex1) 0.5kg mass attached to spring and set in motion -how long for simple pendulum to have same period as s & m if spring has spring constant k=25N/m? Ex2) 0.5kg mass on horiz spring w k=200N/m.Block pulled 0.4m from eq & released so slides back & forth on frictionless surface. -max speed? -speed when block moved halfway back to eq? -KE,PE,& total E of block at halfway pt? PUT IN MISSED NOTES FROM PICS ON PHONE • specific heat(Cw) ⿞change temp ⿞phase stays same ⿞Q= • Latent heat ⿞phase change ⿞Temp stays same ‣ Q= mL • Lf- latent heat of fusion (l-->s or s-->l) ⿞at melting(+) or freezing pt(-..takes E) • Lb- latent heat of vaporization (l-->g) ⿞at boiling point (+) ⿞Vapor condensation (-) • Ex1) how much E a can be added to a 2-kg block of ice initially at -10C to turn it into steam at 100C? ⿞ice at -10C➡ get ice to 0C(melting pt)➡ ice as water at 0C➡ ice as water at 100C➡ ice as steam at ⿞ Specific heat Latent heat Specific Latent ⿞ Mi. Mi. Mi. Mi ⿞ Ci. Lf. Cw Lv K= C+273 Q= Ex2)how much water initially at 80C needs t be added to 1.5kg of ice initially at 0C so that all of it ends up at -E will be exchanged as heat inside until in thermal eq... E=0 in calorimeter ice at 0C➡ ice as water at 0C➡ ice as water at 20C + water at 20C ⬅ water at 80C Q1+Q2+Q3=0 Gw1) dump ice initially at -10C into bucket w 1kg water at 20C.Water in bucket ends at 18C,how much ice was added? Ice at -10C ➡ ice as ice at 0C➡ ice as water at 0C➡ ice as water at 18C + water at 18C⬅ water at 20C miCw T+miLf+miCw T+mwCw T=0 (mi)(4.186)(0- -10)+(mi)(334)+(1)(4.186)(18-0)+(1)(4.186)(18-20)=0 Ct1:neg Q for cup...Taking in E or giving it up? Giving up BC at higherT Entropy(S) always > or =0 for an isolated (closed system..Everything involved in E exchange) Ct2:a = if reversible + if irreversible Total change in E of a system=0 (sum of all Q= 0 as well) Total change in entropy of a system is greater than 0 latent heat: S= mL specific heat: S=mc Ex1) water initially at 80C added to 1.5kg of ice initially at 0C so that all water ends at 20C.entropy change of ice,water,and ice-water system? Ice at 0C➡ ice as water at 0C➡ ice as water at 20C + water as water at 20C ⬅ water as water at 80C Peak of curve on graph is largest change in entropy of system..Also =change inT will get from working problem whatever the substance E is,entropy fx is to tell E how to arrange itself ex) 1kg.Water at 20 and 3kg water at 80...To= 65C and C=338k Ex2) steam at 100C combined w ice at -60C in isolated container.When system reaches thermal eq,everything in container is water at 50C.Mass of ice is 150g.What is entropy change of system? Ice at -60➡ ice at 0C➡ ice as water at 0C➡ ice as water at 50C + steam as water at 50C ⬅ steam as water at 100C⬅ steam at 100C


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