Chemistry 105 - Finnegan
Chemistry 105 - Finnegan Chemistry 105
Popular in Chem 105: Principles of Chemistry
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This 9 page Class Notes was uploaded by Emma Silverman on Friday February 13, 2015. The Class Notes belongs to Chemistry 105 at Washington State University taught by Finnegan in Spring2015. Since its upload, it has received 174 views. For similar materials see Chem 105: Principles of Chemistry in Chemistry at Washington State University.
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Date Created: 02/13/15
2615 Friday Identify the element reduced in the following reaction KMnO4aqFeSO4aqHZSO4aq gt IVIn04 aq Fezso43 aq H200 K2304 aq AMn BFe CO DH ES FK Identify the oxidizing agent in the following reaction ZnsHClaqgt ZnCl2aqH2g AZn BHC CZnCl2 DH2 Zn is oxidized O gt 2 H is reduced 1 gt O Oxidizing agent is the one that contains the reduced Identify the reducing agent in the following reaction CH20aq H2804 aq gt H28aqCOZg H200 022 2 68 gt22 4 4 22 Since carbon goes from O to 2 its the oxidizing agent Therefore the compound on the left containing carbon is the answer ACH20 BHZSO4 CHZS DCO2 EHZO Sulfur is 6 Only choose a reactant Don t chose a product In balancing redox reactions the atoms need to be balanced as well as the amount of electrons Need to take the same amount away as we give Redox reactions must be balanced for number of electrons transferred as well as the number and types of atoms CUS2Agaq gt CU2 aq 2Ags Silvers gaining one coppers giving up two Twice as many silver as copper Balance charge on each side two charges on each side Just check that when you balance the equation 2Als3Br2l gt 2AlBr3 s Each aluminum loses 3 Each bromine gains 1 Zns2HClaq gt ZnCl2aq H2g zinc loses 2 hydrogen gains 1 888 12029 gt 33039 Sulfurs going from O gt 6 and there are 8 so 48 So Oxygen needs 48 Oxygen goes from O gt 2 24 248 2KMnO4aq1OFeSO4aq8HZSO4aq gt 2 MnSO4 aq 7 2 2 5F92SO43aq8H20I1K2804aq 3 Mn is reduced by 5 e Fe is oxidized by 1 e Ratio is 15 ironmn We don t want 5 because its an odd number make it 210 Then put in the 2 and the 5 on the reactant side Then balance the rest H2804aqCH20aq gt H28aqCOZgH20I 268 0 2 2 2 2 44 22 C is oxidized O gt 4 loses 4 e S is reduced 6 gt 2 gains 8 e 2 carbons for every sulfur 1HZSO4aq2CHZOaq gt 1H28aq2COZg4HZOI balance the carbons and sulfurs first then balance H20 C12H22O11SKC03I 3029 H2Og KCIS 0 22 22 1 5 6 4 4 2 2 1 1 Carbon is oxidizing O gt 4 loses 4e Chlorine is reduced 5 gt 1 gains 6 e Sucrose is the reducing agent Potassium chloride is the oxidizing agent Common multiple is 12 each C12H22011 loses 4 x 12 48 e need 486 8 Cl atoms c12szo11 8KC03 gt 12COZ11H208KCI 3C H3OH aq2K2CrZO7aq8HZSO4aq gt3CH202 aq2Cr2SO43aq11HZOI 2 4 2 2 12 14 2 6 8 2 2 4 2K2804ltaqgt Cr is reduced 6 gt 3 gains 3 e Each K2Cr207gains 6 e Carbon gets oxidized 2 gt 2 loses 4 e CH30H loses Common multiple 12 2915 Monday Review Tuesday 21015 7PM Fulmer 226 Covers Chapters 14 reading Assignments 110 Lab Worksheet 1 and Experiments 1 and 3 There is one gas law the Ideal Gas Law All other gas laws are special cases of this one PVnRT or PVnTR 623637 LtorrmolK R00820575 LatmmolK The Kelvin scale K The coldest possible temperature is 27315 degrees C This is called absolute zero and is the basis of the Kelvin temperature scale Absolute zero is 000K X degrees C X27315K Learning Catalytics 1 A sample of argon occupies 7532 mL at 367 C and 6338 torr How many moles of argon are present a PVRTn b 63387532623637309850247 2 6258g of oxygen gas is sealed in a rigid container with a volume of 1765L The temperature is 35000 What is the pressure of the gas in atm a nRTVP b 6258321955625 mol of 02 gt n c 19556250820575352731517652802 atm 3 What is the density of sulfur dioxide gas at 555C and 1602 kPa Answer in units of gL DO NOT put the units in your answer a Gas constant of kPa 83144621 b Molar mass of sulfur dioxide 64066 c Density MPRT 64071581051082057532865 3756 gL 4 What is the density of neon gas at STP Express your answer in gL DO NOT include the units in your answer a 27315K 1atm DMPRT 201810820575273159003 906 5 A sample of a pure compound in the gas phase has a mass of 8273 mg and occupies a volume of 3666mL at 83511C and 09105 atm What is the molecular weight of the compound Express your answer in units of gmol DO NOT include the units in your answer a 9105366608205758351127315x b 8273x 63525 210882852 21115 Learning Catalytics 1 2KC03s gt 2KC s 302g If 9264 g of potassium chlorate are heated and the reaction goes to completion what volume of oxygen gas at 220C and 1055 atm is produced 391 gmol 3545 gmol 316 gmol 12255gmol 92641225532 mols of 02 n nRTPV 1 1339045290082057527315221 055 2603 2 4NH3g 502 g gt 4NOg 6H20 I If 408 L of ammonia gas and 550 L of oxygen gas both at 250 C and 1100 atm react according to this equation what volume in L of NO at 250 C and 1100 atm will be produced Find limiting reactant gt PVRTn 408 L NH3 4L NO 4L NH3 408 L NO lt Limiting reactant Answer 550 L 02 4L NO5L 02 440 L NO 3 4NH3g 502 g gt 4NOg 6HZO I If 408 L of ammonia gas and 550 L of oxygen gas both at 250 C and 1100 atm react according to this equation what is the total volume in L or all gasses at 250 C and 1100 atm at the end of the reaction Not going to be any ammonia we ll end up with 408 L of NO and also 02 408 L NH3 5L 024L NH3 510L 02 used 550L 510 L 40 L 02 remains 40 02 408 L N0 448 L 4 Two 2070 L tanks of gas are at a temperature of 235 C One tank contains hydrogen gas at a pressure of 1587 atm The second tank contains oxygen at a pressure of 1069 atm lfthese reactants are used to produce water what is the maximum mass in kg of water that can be produced PVnRt 15872070 235273150820575 13495365 mol H2 13495365 mol H20 10692070296150820575 90 91 mol lt limiting 90912mol1 181809 moi H20 2H2g02g gt 2H20g 13495368 moi 180161mol 2431325 g H20 2431 kg Kinetic Molecular Theory 58 Know the five assumptions of KMT Know the KMT defines pressure and temperature Know how KMT explains the gas laws KMT tells us that gas particles behave independently of each other They occasionally collide and exchange energy but that is it This is useful as it means that we can deal with each gas in a mixture separately We assume gases behave the way they do because there are no forces operating between the molecules billiard balls we say there are no forces lfthere were no forces operating between them there would be no liquids or solids We can ignore the forces for gases because they have so much kinetic energy that we can ignore the forces in between them End of chapter 5 talks about the fact that there are forces and molecules that DO occupy volume Low temperatures actually have an effect of that Same with high pressures Every gas in a mixture of gases behaves independently as if the other gases weren t even there That means we don t have to consider the other gases when looking at one gas Concept of partial pressure Calculate the pressure in a 1000L container at 250 C if the container holds a 0364 mole of argon Pressure i PnRTV 0364mol 00820575 29815 K1000 atm 8905 atm b 0450 mole of chlorine Pressure i PnRTV 0450mol00820575 29815K1000atm 11009 atm c 0364 mole of argon and 450 mole of chlorine i 8905 11009 19914 atm 21315 Check your email andor the Blackboard announcements andor the Blackboard Experiment 9 forum for an important correction to the Expt 9 prelab The pressure contributed by one gas in a mixture of gases is called the partial pressure The total pressure in the sum of the partial pressures mole fraction X of the gas PAXAPtot XA is the mole fraction ofA PAVA100Ptot Learning Catalytics 1 A mixture of gases at STP is 420 nitrogen 265 oxygen and 315 carbon dioxide by volume a What is the partial pressure of oxygen in atm b Oxygen is 265 of 1 atm 265 atm 2 A mixture of gases at STP is 420 nitrogen 265 oxygen and 315 carbon dioxide by volume Rank these gasses in order of increasing average kinetic energy i N2 ii 02 iii CO2 b They all have the same temperature which means they all have the same kinetic energy N202CO2 3 A mixture of gases at STP is 420 nitrogen 265 oxygen and 315 carbon dioxide by volume Rank these gasses in order of increasing rms velocity average molecular speed i N2 ii 02 iii CO2 b Lighter molecules are faster heavy molecules are slower C02lt02ltN2 4 A mixture of gases at STP is 420 nitrogen 265 oxygen and 315 carbon dioxide by volume Rank these gases in order of increasing time required to diffuse across a room From KMP umS sqrt 3RTM where M stands for molar mass in kgmol R 83144725 JmolK The average speed rms velocity of a gas molecule is inversely proportional to the square root of the molecular weight and directly proportional to the square root of the temperature Thus the rate of effusion the process of moving through the pores in a solid and of diffusion the process of moving through another gas is determine by the rms velocity What is the relative rate of effusion for hydrogen gas compared to nitrogen gas rHZrN2 sqrt MmMHZ sqrt 28022016 3728 Bigger molar mass goes on the top of the fraction lf 025 mol of hydrogen effuse from a container in 4632 s how much time would be required for 025 mol of nitrogen gas to effuse from the same container under identical conditions tN2tH2 sqrt MNZIMHZ you need a bigger number because it s going to take N2 a longer amount of time than H2 3728 4632 1727 seconds Homework review All substances have a vapor pressure partial pressure above the solidliquid CaCO3s gt CaOsCOZg CaCO3 is heated and the CO2 is collected over water 3500mL of gas at 2500C and 6900 torr are collected What mass of CO2 is produced PH202378 torr from table 54 PCO2690O torr 2378 torr 66622 torr nPVRT 66622 torr3500mL1000LmL623637torrmoK29815K 055199 What is today s secret code
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