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## Chapter 8 practice problems

by: Jacqueline Vilca

316

0

5

# Chapter 8 practice problems PSY 292 Forster- Introduction to Biobehavioral Statistics for Non-Majors

Jacqueline Vilca
UM
GPA 3.9
PSY 292 Forster- Introduction to Biobehavioral Statistics for Non-Majors
Forster

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Includes practice problems from chapter 8 of the textbook.
COURSE
PSY 292 Forster- Introduction to Biobehavioral Statistics for Non-Majors
PROF.
Forster
TYPE
Class Notes
PAGES
5
WORDS
KARMA
25 ?

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This 5 page Class Notes was uploaded by Jacqueline Vilca on Saturday February 28, 2015. The Class Notes belongs to PSY 292 Forster- Introduction to Biobehavioral Statistics for Non-Majors at University of Miami taught by Forster in Spring2015. Since its upload, it has received 316 views.

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Date Created: 02/28/15
Study Soup Stats Chapter 8 textbook 9 Which of the following are examples of independent events Independent is when the outcome of one event does not affect the outcome of the next event a Obtaining a 3 and a 4 in one roll of two fair dice Neither results relies on the other Rolling a 3 doesn39t affect your chances of rolling a 4 on your next turn b Obtaining an ace and a king in that order by drawing twice with replacement from a deck of cards With replacement the probability of drawing either remains the same Without replacement the probability changes for the next draw e A full moon and eating a hamburger 10 Which of the following are example of mutually exclusive events Mutually exclusive is when the events cannot occur together a Obtaining a 4 and a 7 in one draw from a deck of ordinary playing cards They cannot occur at the same time c Being male and becoming pregnant These cannot occur at the same time d obtaining a 1 and an even number in one roll of a fair die You would need to roll a 1 and an even number but that can t happen at the same time if you39re only rolling one die e Getting married and becoming a bachelor These two events cannot occur at the same time 11 Which of the following are examples of exhaustive events Exhaustive events are when the set of events includes all of the possible events that could occur a Flipping a coin and obtaining a head or a tail c Taking an exam and either passing or failing 12 At the beginning of the basketball season in a particular year the odds that the New York Yankees will win the American League pennant are 3 to 2 a What are the odds that the Yankees will lose the pennant First step the odds that they will win according to the information given it 3 to 2 This means they will win 3 times out of 5 3 plus 2 Second step if their probability of winning are 35 then the probability of them losing is 25 The odds become 2 to 3 b What is the probability that the Yankees will win the pennant See explanation above 35 060 c What is the probability that the Yankees will lose the pennant See explanation above 25 040 13 If you draw a single card once form a deck of ordinary playing cards what is the probability that it will be a The ace of diamonds First step an ordinary pack of paying cards contains 52 cards 4 of those will be ace and four of them will be diamonds Second step only 1 card will be an ace AND a diamond Third step 152 0019230769 b A 10 First step there are 4 ten39s in a 52 card deck Second step 452 0076923077 c A queen or a heart Frist step There are 4 queens and 13 hearts Second step add the probabilities and subtract 1 because one card will be both queen of hearts 452 1352 152 1652 Third step 1652 0307692308 d A 3 or a black card First step there are four 339s and 26 black cards half of the deck Second step Add the probabilities then take away 2 because two cards will be a 3 and black Since four cards are 339s and half are black half of the quot3quot cards will be black Third step 452 2652 152 2852 Fourth step 2852 0538461538 15 If you are randomly sampling one at a time with replacement from a bag that contains eight blue marbles seven red marbles and ve green marbles what is the probability of obtaining a A blue marble in one draw from the bag First step add to nd the total number of marbles 8 7 5 20 Second step There are 8 blue marbles 820 040 b Three blue marbles in three draws from the bag First step There is replacement so the probability of drawing a blue marble remains the same for each of the 3 draws Second step 820 x 820 x 820 5128000 0064 c A red a green and a blue marble in that order in three draws from the bag First step The denominator will stay the same because there will be replacement with each draw Second step red 720 Green 520 Blue 820 Third step multiply each probability 720 x 520 x 820 2808000 0035 d At least two red marbles in three draws from the bag First step There are three possibilities of drawings 2 red with 1 blue 2 red with 1 green or 3 red Second step Find the probability of each drawing 2 red and 1 blue 720 x 720 x 820 3928000 x3 11768000 because there are 3 possible orders of this drawing 2 red and 1 green 720 x 720 x 520 2458000 x3 7358000 same reasoning as above 3 red 720 x 720 x 720 3438000 Third step Add the probability of each possible drawing 11768000 7358000 3438000 22548000 028175 16 The same as questions in 15 but WITH REPLACEMENT A Blue marble in one draw from the bag remains 820 040 B 3 blue marbles in three draws from the bag First draw probability 820 Second draw probability 719 Third draw probability 618 Multiply 820 X 719 X 618 3366840 0049122807 C A red a green and a blue marbles in that order in three draws from the bag First draw for red 720 Second draw for green 519 Third draw for blue 818 Multiply 720 x 519 x 818 2806840 0040935673 D At least two red marbles in three draws from the bag First step There are three possibilities of drawings 2 red with 1 blue 2 red with 1 green or 3 red Second step Find the probability of each drawing 2 red and 1 blue 720 x 619 x 818 3366840 x3 because there are 3 order possibilities with this drawing 10086840 2 red and 1 green 720 x 619 x 518 2106840 x3 6306840 same reasoning as above 3 red 720 x 619 x 518 2106840 Third step Add the probability of each possible drawing 10086840 6306840 2106840 18486840 0270175439 17 You are playing the onearmed bandit slot machine that has a lemon a plum an apple an orange a pear some cherries and a banana Each slot is independent of each other a What is the probability of three oranges appearing First step total fruits are 7 different fruits for each slot Second step multiply 17 x 17 x 17 0002915452 b Two oranges and a banana will appear without regard to order First step The order could go as follows 1 Orange banana orange 2 Banana orange orange 3 Or Orange orange banana Second step nd the probability of each possible order First order 17 x 17 x 17 1343 Second order 17 x 17 x 17 1343 Third order 17 X 17 X 17 1343 Now add each order39s probability 3343 0087 c At least two oranges will appear First step there are 7 fruits total But 6 fruits if you exclude orange Second step without speci cation to the third fruit there are 3 order possibilities 1 Orange other fruit orange 2 Orange orange other fruit Or 3 Other fruit orange orange Third step multiply each possibility by 6 because there are 6 different fruits that could be the quotother fruitquot First order 17 x 67 x 17 6343 Second order 17 x 17 x 67 6343 Third order 67 x 17 x 17 6343 Probability of all three slots being orange 17 x 17 x 17 1343 Fourth step add each order probability together 6343 6343 6343 1343 19343 0055393586 18 You want to call a friend on the telephone You remember the rst three digits of her phone number but you have forgotten the last four digits What is the probability that you will get the correct number merely by guessing once For each of the last four digits there are 10 numbers to choose from The probability of guessing the correct number is 110 for each of the four last digits 110 X 110 X 110 X 110 00001 19 You are planning to win big at the race track In a particular race there are seven horses entered If the horses are all equally matched what is the probability of your correctly picking the winner and runnerup For choosing the winner there would be seven horses The probability of picking the correct horse is 17 For choosing the runnerup there would be 6 options after picking the winner 16 Multiply each 17 x 16 142 0023809524

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