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# mgmt 305 mgmt 305

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This 6 page Class Notes was uploaded by Claire on Tuesday March 10, 2015. The Class Notes belongs to mgmt 305 at Purdue University taught by in Spring2015. Since its upload, it has received 414 views.

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Date Created: 03/10/15

SAMPLE QUESTIONS FOR EXAM 1 Rows Size Columns Drive A F R All Compact 9 37 10 56 Large 6 5 13 24 Mi ols i z e 1 3 4 8 8 6 9 A1 1 2 8 9 O 3 1 1 4 9 1 The table above classifies 149 cars by their size and type of drivetrain A All wheel F Front wheel R Rear Wheel Suppose we choose one of these cars at random What is the probability that it is a Rear Wheel drive given that it is a Large car A 13149 B 1324 C 1331 D 31149 2 Refer again to the above table Suppose we choose one of these cars at random what is the probability that it is a Compact car with Allwheel drive A 928 B 956 C 9149 D None of the above 3 Refer again to the above table the variables Drive and Size are what types of variables A Both categorical B Both numerical C One is categorical one is numerical Frequency 50 40 30 20 10 9quot 009 POP Distribution Of Flaws m I l I l l 0 5 1O 15 20 No of Flaws Lasertech buys synthetic diamonds to use in the production of medical and industrial lasers A usable synthetic diamond is one that has 6 or fewer flaws In a recent batch of synthetic diamonds presented to them for purchase the flaws of each were counted and the histogram of the resulting variable is shown above Approximately what percentage of this batch of diamonds is usable 20 30 45 70 Refer again to the sample of synthetic diamonds in Question 4 The z score of the median of this sample will likely be Nega ve Postive Zero Cannot be determined 009 POP N W909 34 50 68 95 111909 Suppose that for all households of Lafayette and West Lafayette the average monthly amount spent on internet access is 2760 with a standard deviation of 12 If we randomly select 1 household what is the probability they spend more than S30month on internet access 0025 005 0395 Cannot be determined without knowing the shape of the population distribution Refer again to the population in Question 6 If 100 households are sampled at random what is the probability that their average internet access fee is greater than 30 0025 005 034 068 Cannot be determined without knowing the shape of the population distribution Suppose we use Minitab or some other software to simulate sampling 100 cattle from the Angus beef cattle population and recording their weights Recall that their weights are distributed N1152 84 By the empirical rule how many of these 100 do we expect to be between 1048 and 1236 Suppose it is known that 52 of the workers at It s A Living nc consider themselves happy with their jobs If a random sample of 25 employees is taken the probability that 60 or more are happy is approximately 0 24 60 80 Cannot be determined due to inadequate sample size 10 11 12 13 Refer again to the employees at It s a Living in Question 9 TRUE or FALSE If we randomly sample 100 of these employees the probability that 60 or more are happy will be greater than the probability in Question 9 A TRUE B FALSE C Cannot be determined Suppose it is unknown what proportion of employees at It s a Living are happy If we randomly sample 100 and 55 are happy what is a 95 confidence interval based on this sample for the proportion who are happy A 045 065 B 04 07 C 05 06 D 042 068 E Cannot be determined without knowing the population standard deviation Again suppose it is unknown what proportion of employees at It s a Living are happy TRUE or FALSE If we randomly sample 1000 and 550 are happy the 95 confidence interval based on this sample for the proportion who are happy will be narrower than the one in Question 11 A TRUE B FALSE C Cannot be determined Suppose that from a random sample of 200 customers of ESR nc Emergency Snow Removers we produce a 95 confidence interval of 064 076 for the proportion of customers who are satisfied with their service The point estimate of the proportion of satisfied customers obtained from this sample is A 50 B 64 C 70 D 76 E Cannot be determined based on the given information 14 PCP 15 PCP 009 17 Refer to the sample from ESR in Question 13 and assume its point estimate by a great stroke of luck is the actual population proportion If we want to have a confidence interval with a margin of error of 003 we need to take a new sample with sample size of at least 100 400 800 Cannot be determined Suppose we are growing soy beans We wish to estimate our yield for an upcoming harvest We do this by estimating podsplant with 40 or more indicating an excellent yield Suppose we sample 30 plants at random and they have an average of 41 podsplant Further suppose we know from experience that the true population standard deviation is 55 A 95 confidence interval for our yield in podsplant based on this sample is 3895 4305 3903 4297 3975 4225 4042 Consider the sample of soy bean plants from Question 15 A 90 confidence interval computed from this sample will Be wider than the interval in Question 15 Be identical to the interval in Question 15 Be narrower than the interval in Question 15 Not contain the true podplant value for the population Consider the sample of soy bean plants from Question 15 but this time assume that we do not know the population standard deviation We compute the sample standard deviation and find that it is 55 A 95 confidence interval for our yield in podsplant based on this sample s wider than the one from Question 15 Is Narrower than the one from Question 15 Is the same as the one from Question 15 Cannot be calculated based on the information given 009

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