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KIN 300 Scott Week 2 Ch 1: Part II and Ch 2: Part I lecture notes

by: Natalie Wong

KIN 300 Scott Week 2 Ch 1: Part II and Ch 2: Part I lecture notes KIN 300

Marketplace > California State University Long Beach > Kinesiology > KIN 300 > KIN 300 Scott Week 2 Ch 1 Part II and Ch 2 Part I lecture notes
Natalie Wong
Long Beach State
GPA 4.0

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About this Document

We covered the rest of chapter 1: finding resultant and net forces and colinear and concurrent forces.
Kristen Scott
Class Notes
Kinesiology, Biomechanics, kin300, csulb, forces
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This 4 page Class Notes was uploaded by Natalie Wong on Monday September 5, 2016. The Class Notes belongs to KIN 300 at California State University Long Beach taught by Kristen Scott in Fall 2016. Since its upload, it has received 9 views. For similar materials see Biomechanics in Kinesiology at California State University Long Beach.

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Date Created: 09/05/16
KIN 300: Fall 2016 – Week 2 8/29/16 Natalie Wong Ch. 1 Part II – “Intro to Forces” ***Notes derived from Prof. Scott’s lecture PPT. I. Forces a. Definitions:  Resultant = result of addition of 2 or more forces on an object (difference between added  forces and existing forces)  Net = the sum of all external forces acting on an object  Colinear = forces that share the same line of action; paralleled forces (ex: both horizontal  forces, both vertical forces, etc.)  Concurrent = forces that do not share the same line of action, but do go through the same  point (ex: perpendicular forces, one acting horizontally and one acting vertically) b. Colinear Force Addition  When forces run on the same axis/line, they can be added. - Direction Values  Up & Right = (+)  Down & Left = (­)  Ex:         ­200N ­400N        100N 550N Net Force = ­200 ­400 +100 +550 = 50N c. Concurrent Forces  Cannot simply be added to find net force!  Organize forces into right angles/rectangle (if possible)  Then use right triangles and their respective properties to solve  Ex: ­70N ­400N ­400N 480N +10N ­70N  +480N 10N 2 2 2 (­60N)  + (80N)  2 C 3600 + 6400 = C 80N C=net force sqr rt (10,000) = C = 100N KIN 300: Fall 2016 – Week 2 8/29/16 Natalie Wong ­60N II. Types of Force Systems a. Force System = net force/all forces acting on an object b. Force Composition = Finding a resultant, or adding components of  a force system together  Ways in which to calculate force composition - Addition - Graphical technique - Pythagorean’s Theorem - Trigonometric technique c. Force Resolution = finding components of a force system III. Math a. Right triangles  Pythagoreans’s Theorem: if you know two sides of a right triangle, you can determine the  length of the third side - a  + b  = c 2  Trigonometry: if you know at least one side of a right triangle and at least one angle (other  than the 90 deg angle), you can solve for the other angle and side lengths - Trig Ratios   Sin = opposite/hypotenuse  Cos = adjacent/hypotenuse  Tan = opposite/adjacent hyp. - Inverse Trig Ratios (ex: arcsin or sin ) ­1       opp.  Ө = sin (opp/hyp) Ө ­1  Ө = cos (adj/hyp)  Ө = tan (opp/adj)        adj. IV. Static Equilibrium = when all forces acting on object make a net force of 0N ***Practice problems at the end of Ch 1 on Pg.46­50; Answers Pg.400  KIN 300: Fall 2016 – Week 2 8/31/16 Natalie Wong Ch. 2 Part I – “Intro to Linear Mechanics” ***Notes derived from Prof. Scott’s lecture PPT. I. Kinematics a. Need to know space and time i. Space = where an object starts and stops ii. Time = how long the object is in motion b. Quantities: i. Position – Distance and Displacement ii. Speed and Velocity iii. Acceleration c. Remember! Biomechanics is subdivided into Kinematics and Kinetics, each of which is  further subdivided into linear and angular motion. II. Linear vs Angular Motion a. Linear (Translational) Motion = all points of an object move the same distance, in the same direction, over the same amount of time. i. Rectilinear = all points of object move in a straight line  Ex: skiing, passively riding a bike, or any other activity or movement that requires the  body to stay in a stationary position while in locomotion in a straight line ii. Curvilinear = all points of object move in a curved path  Ex: hangliding, spread eagle in figure skating, or any other activity or movement that  requires the body to stay in a stationary position while in locomotion in a curved path b. Angular (Rotational) Motion = all point of object move through the same angle, in the  same direction, over the same amount of time. i. Movement occurs about a joint axis ii. Ex: Knee curl, biceps curl, etc III. General Motion a. Describes most complex movements because combo of linear and angular motion i. Angular motion at the joints  linear motion of the rest of the body  Ex: driving a wheelchair, running, jumping over an obstacle b. Position = an object’s location in space (x,y) i. Distance = length of true path an object has traveled  Unit = meters (m)  Scalar quantity = only has magnitude ii. Displacement = straight line from the object’s initial starting to position to its end  position  Unit = meters (m)  Vector quantity = direction (+ or ­) and magnitude c. Speed vs Velocity i. Speed = distance traveled over time  Units = meters (m)/second (s) or kilometers (km)/hour (h)  Scalar quantity = only magnitude KIN 300: Fall 2016 – Week 2 8/31/16 Natalie Wong  Can be calculated as average speed or instantaneous speed ii. Velocity = displacement over time  Units = m/s  Vector quantity = magnitude and direction (+ or ­)  Can be calculated as average or instantaneous velocity d. Acceleration = change in velocity over time i. Unit = m/s 2 ii. Can be calculated as average or instantaneous acceleration iii. Vector quantity = magnitude and direction (+ or ­) IV. Equations: a.  Displacement (d) = final position – initial position = P  ­ P f  i b. Speed (s) = distance (l) / time (t) = l/t c. Velocity (v) = displacement / time = d/t = (p  – p)/f i d. Acceleration (a) = ∆v/t = (v – v)ft i


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