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General Physics (PHYS 111) Week 1

by: snufkin

General Physics (PHYS 111) Week 1 PHYS 111

Marketplace > San Francisco State University > Physics > PHYS 111 > General Physics PHYS 111 Week 1
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About this Document

Week 1 lecture notes from PHYS 111 (General Physics 1 course) going over vectors vs. scalar, distance, position, displacement, velocity, and speed.
General Physics 1
Elaine Tennant
Class Notes
Physics, General Physics, velocity, displacement/speed/velocity/acceleration/projective motion, kinematics




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This 4 page Class Notes was uploaded by snufkin on Monday September 5, 2016. The Class Notes belongs to PHYS 111 at San Francisco State University taught by Elaine Tennant in Fall 2016. Since its upload, it has received 163 views. For similar materials see General Physics 1 in Physics at San Francisco State University.


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Date Created: 09/05/16
Physics Notes: Week 1     Classical Mechanics:    Physical Quantities­ time (seconds), length (meters), mass (kilo)  SI Units (international system of units):  kilo​= ​10​  or 1,000   centi​= 1​ 0​  or  1   100 μ (micro)​= 10​ or 6 ​ 1   1,000,000   Ex​. ​ m→m  2.5cm 10⁻²  −2 ​ 1 × 1cm = 2.5× 10​ m or 0.025m    Dimensional Analysis:  Distance (m)= speed (rate in  m ​ ×  time (s)  s → d = v × t  (d= distance, v= velocity, t= time)    Ex.​ distance (m) = acceleration ( m ) ×  time​ power  s² m=  m ×  s²   s² 1 m=  m ×s​ p  s² 1= s​ ×s​ = s​​ (­2+ ) Set exponent equal to zero: ­2 + p = 0 → p = 2    Ex. Time and Length can be solved for separately  1 −   s​ = ( s² )​                 m​ = ​ m​  ×  m   ​ 2 1 s​ = (s​ )​ q                 m​ = ​ m​    2      ​ 1 ​ ­2q                                         ​ s​ = s​ o= p ­ 2   1 1= ­2q                          p=2   1 q= ­ 2     Problem Solving:  1. Draw a picture  2. Write down everything you know and want to know (* ​ **include units) ​   3. Draw a diagram  4. Write down relevant equations  5. Solve for what you want  6. Plug in numbers and calculate  7. Units and direction    Ex. Nerve fibers in humans can conduct nerve impulses a speeds up  ­­­­­­­­­­­­​ o ​ 40  m . How far can an impulse travel in 5 s ​ ec?  s m  v= 140  s  →   time= 5 s   distance (m) = ?  Equation: d= vt  m d= (140  s ​ ×  (5 s)   d= 700 m    1 Dimensional Kinematics:   **   denotes a vector (direction)      f ​is final     x​ is x​    i​ initial     ∆= “change in” or x​ ­ f​  i Position: x    ­ 0  ­position is the the new location from where an object was  Distance:​ x​ ­f​​  i ­distance is the total amount an object traveled  Displacement:​    xf​­  xi​= ∆ x    ­displacement is the amount traveled from the initial position    Ex. A person walks 20 m north, then 10 m south.  What is the distance?  distance: 20m + 10m= 30m  What is the displacement?  Displacement: +20m ­ 10m = 10m N    Vectors:                                         Scalars:  ­magnitude         ­magnitude  ­units                                             ­units  ­direction    displacement                                distance  velocity                                         mass         time         speed    ⃗v   =   ⃗Δx   average​ Δt speed =  distance   time   Ex. A person walks 20 m north, then 10 m south.Δt = 10 s ​ ec.  What is the speed?  speed =  ditimece = ​310s ​ 3 ms   What is the velocity?  ⃗Δx 10m N m ⃗v =   Δt =​  10s = 1 s ​    ​ Ex. A dog walks 10m north, 2m south, then 8m north. It takes 10 s ​ ec.  16m m     Slope =  10s = 1.6  s   Slope = velocity for position vs. time graphs    distance​= 10m + 2m + 8m= 20m    displacement​= 10m ­ 2m + 8m= 10m N    distance 20m m speed​=  time ​   10s = 2 s     ⃗Δx ⃗xf − ⃗xi 16m −8m 8 m average velocity​=  Δt =   tf − ti​  10s − 7s =  3 s N    instantaneous velocity= ​   lim ⃗ x   Δt→0 Δt           = 6m −11m =   5 m ​ 5 m N  10s − 9s 1 s s    


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