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Chem 1127Q Lecture Notes 3 9/6/16

by: Aidan

Chem 1127Q Lecture Notes 3 9/6/16 Chem 1127Q

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Class notes from 3rd lecture
General Chemistry
Dr. Fatma Selampinar
Class Notes
Temperature Scales, significant figures
25 ?




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This 2 page Class Notes was uploaded by Aidan on Wednesday September 7, 2016. The Class Notes belongs to Chem 1127Q at University of Connecticut taught by Dr. Fatma Selampinar in Summer 2015. Since its upload, it has received 6 views. For similar materials see General Chemistry in Chemistry at University of Connecticut.


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Date Created: 09/07/16
C/F­32 = 5/9 Ex. 40..1/F­32   5(F­32) = 360.9                          5F­160 = 360.9                         5F = 200.9                         F = 40.18 Calculations in this class will use Kelvin scale K = C +273 Sig Figs way to indicate error Ex. 30.0 = 2 sig figs .0108 3g sig figs Precision refers to number of sig figs associated with measurement Accuracy refers to how close result is to actual value Every calculation must be rounded to correct number of sig figs For multiplication and division result is rounded to number of sig figs present in the least precise number For addition and subtraction result is rounded to contain number of decimal places in the least  precise number Multiplication and division look for fewest sig figs of any number in calculation Addition and subtraction look for fewest decimal places in numbers in calculation “Weak link” principle in calculations Subtraction can “lose” sig figs Ex. 8.7638­8.7560 = .0078 2 sig figs      33.5 ­ 25.74 = 8.1 2 sig figs Round only final answer  If number greater than 5 round up otherwise round down Ex. 6.78 x 5.903 x (5.489 ­ 5.01) = 6.78 x 5.903 x .479 = 19.1707 = 19 Problem Solving Method Dimensional Analysis – have x –––––– = want                                       Have x (want/have) = want                                        Ex.                                          9 yd x –––– = ? ft                                         9 yd x (ft/yd) = ? ft                                         9 yd x (3 ft/1 yd) = 27 ft = 30 ft                                         .030 g x (? mg/? g) = ? mg                                         .030 g x (1000 mg/1 g) = 30 mg  If told 1 cal = 4.184 J then could derive 1 cal/4.184 J and 4.184 J/1 ca Plugging values and units into formulas results in combinations of units (derived units) Combinations of units often assigned definition of a new unit New unit is often useless for dimensional analysisl


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