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CHEM 1500 Week 3

by: D Holley

CHEM 1500 Week 3 CHEM 1500

Marketplace > Ohio University > Chemistry > CHEM 1500 > CHEM 1500 Week 3
D Holley

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Concepts in Chemistry
Corey Beck
Class Notes
General Chemistry
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This 2 page Class Notes was uploaded by D Holley on Friday September 9, 2016. The Class Notes belongs to CHEM 1500 at Ohio University taught by Corey Beck in Fall 2016. Since its upload, it has received 18 views. For similar materials see Concepts in Chemistry in Chemistry at Ohio University.


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Date Created: 09/09/16
Week 3 CHEM 1500 9/6 & 9/8 Week three, whoo hoo! This week we got into the mathematically difficult solving; Dimensional Analysis and  Temperature. Dimensional analysis is used in all countries, but every country uses different units and this is  why it’s so handy. We will always be multiplying by a conversion factor. Some of the  conversions you will know by heart and others are provided to you on that handy two chart you  should’ve printed out or downloaded onto your phone. Again, don’t forget the significant figures, they are leaving any time soon.  Usually when solving with dimensional analysis you will feel the need to cross multiply. This  works great for one step conversions, but you should never get into the habit of doing it. We  know that the units in the original problem will have to be canceled out with units on the bottom  of the conversion factor, so you could think of that as cross multiplying.  Then, we began talking temperature. Dr. Beck gave us three equations that are related to  temperature, but he is only going to provide two of them on our quizzes and exams, that is why it is important that you play around with these equations and know how to reverse them.  The first equation relates degrees Fahrenheit (˚F) to degrees Celsius (˚C): T(˚F)=9/5T(˚C)+32. The second equation relates degrees Celsius (˚C) to Kelvin (K): T(K)=T(˚C)+273.15 Those two equations will be provided on the quizzes and exams, if needed. ˄ ˄ The third equations, which is derived from the first equation I listed, is  T(˚C)=5/9(T(˚F)­32). You can obtain this equation by using algebra.  We have two significant temperatures that come in handy: freezing and boiling. We know that  the freezing point of water is 32˚F and 0˚C. We also know that the boiling point of water is  212˚F and 100˚C. You do not have to memorize these, but they could help you give yourself a  few extra minutes on an exam.  There is something special about the Kelvin scale. We call the Kelvin scale the absolute scale  because when Kelvin is 0 we have predicted that all molecular movement has completely  stopped. Therefore, 0K is the coldest temperature that can be recorded.  Don’t forget to be keeping up with the weekly videos/quizzes, homework and make sure you’re  working through practice problems throughout each week!


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