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by: Bethany B.

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# Chem1212K, Week 5 Notes CHEM 1212K

Marketplace > Georgia Gwinnett College > Chemistry > CHEM 1212K > Chem1212K Week 5 Notes
Bethany B.

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This week we discussed "rate expressions" and rate laws.
COURSE
Principles Chemistry II w/Lab
PROF.
Omar Villanueva
TYPE
Class Notes
PAGES
2
WORDS
CONCEPTS
General Chemistry, rate, expressions, ratelaw
KARMA
25 ?

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This 2 page Class Notes was uploaded by Bethany B. on Friday September 16, 2016. The Class Notes belongs to CHEM 1212K at Georgia Gwinnett College taught by Omar Villanueva in Fall 2016. Since its upload, it has received 4 views. For similar materials see Principles Chemistry II w/Lab in Chemistry at Georgia Gwinnett College.

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Date Created: 09/16/16
9.16.16 Chemistry 1212KNotes[Week 5] Chapter 13 Lecture Kinetics Reactants Products A B Rate “expression”:Rates are interms of changes in concentrations (M)over changesintime Rate = −∆ ????] +∆ ????] = ∆???? ∆???? −∆ ????] +4∆ ????] If itis: 2A1/4B Rate = 2∆???? = ∆???? Practice Problem: 4NO +2O  2N O R2te5of reaction)=0.024M/s a) At whatrate is N 2 5eingformed? −∆[???????? ] −∆ ???? ] +∆ ???? ???? ] ???????????????? = 2 = 2 = 2 5 4∆???? ∆???? 2∆???? ???? +∆ ???? 2 5 ] −∆ ???? 2] 0.024 ???? = 2∆???? = ∆???? ???? ???? Relationship:2 Rate N2O5= Rate O20.025 ????×2 = 0.048 ???? b) At whatrate is NO 2eacting/beingconsumed? The rate of reaction=the rate of O 2 ???? ???? 4 0.024 ???? ) = 0.096???? “Rate Laws” Rate laws expressarelationshipof the rate (M/time)of a reactionto the rate constant(k) and the concentrations [M] of reactants raisedto some powers(x,y, z) aA + bB cC [A]—concentrationof “A” Rate =k[A] [B] y  Reactionis X order inA [B]—concentrationof “B”  Reactionis Y order inB  Reactionis (X + Y) order overall Example: A + B AB Trial Initial [A] Initial [B] Rate (M/s) 1 0.720 M 0.180 M 0.470 2 0.720 M 0.720 M 1.880 3 0.360 M 0.180 M 0.117 Rate =k[A] [B] Y ???? ???? Trial 2 1.880 ????2 0.720 0.720 Trial 1 (0.470) = (????1)( 0.720) (0.180) ???? 4 = 4) ???? = 1 Rate =k[A] [B] 1 Trial 1 0.470 ????1 0.720 ???? 0.180 ???? = ( ) = ( )( ) ( ) Trial 3 0.117 ????3 0.360 0.180 4 = 2???? ???? = 2 Rate =k[A] [B] 1 Now findk. 0.470 = ???? 0.720 (0.180) 1 2

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