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KIN 300 Fall 2016 Scott Week 4 9/7/16 Ch 2 Part Lecture

by: Natalie Wong

KIN 300 Fall 2016 Scott Week 4 9/7/16 Ch 2 Part Lecture KIN 300

Marketplace > California State University Long Beach > Kinesiology > KIN 300 > KIN 300 Fall 2016 Scott Week 4 9 7 16 Ch 2 Part Lecture
Natalie Wong
Long Beach State
GPA 4.0

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About this Document

Notes covered projectiles
Kristen Scott
Class Notes
Kinesiology, kin300, Biomechanics, projectiles
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This 4 page Class Notes was uploaded by Natalie Wong on Sunday September 18, 2016. The Class Notes belongs to KIN 300 at California State University Long Beach taught by Kristen Scott in Fall 2016. Since its upload, it has received 3 views. For similar materials see Biomechanics in Kinesiology at California State University Long Beach.


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Date Created: 09/18/16
KIN 300: Fall 2016 – Week 4 9/7/16 Natalie Wong ***Notes are derived from Prof. Scott’s lecture PPT Chapter 2: Part II I. Definition of Projectile a. Projectile = curvilinear motion in which an object is under the influence of gravity and air  resistance (negligible for this class), or vertical and horizontal forces b. How does gravity affect a projectile? i. Horizontal motion not affected by gravity, therefore, horizontal velocity (v ) and  x acceleration (a )xremain constant ii. Vertical motion IS affected by gravity! Since acceleration due to gravity is a constant,  vertical acceleration (a ) ys constant. However, vertical velocity (v ) will chynge –  decrease to apex (v  = y m/s) and increase back down in the direction of gravity c. Factors influencing projectile trajectory i. Projection angle – affects distance and time  Max projection angle = 45⁰ ii. Projection height  Difference between the start and end heights – three trajectories: - Same start and end heights *mostly what we’ll be dealing with in class - Start height > end height - Start height < end height iii. Projection velocity  How fast object is launched with vertical and horizontal velocity  Resultant trajectory dependent on velocity and projection angle Projection Velocity Projection Angle Projection Height II. Formulas a. Uniformly accelerated motion equations i. v f v + it {final velocity = initial velocity + (acceleration x time)} ii. v f= v  +i2ad {final velocity   = initial velocity  + (2 x acceleration x displacement)} iii. d = vt + ½ at  {displacement = (initial velocity x time) + (½ acceleration x time )} 2 i III. 7 steps to a projectile problem: 1) Find vertical and horizontal components of projection velocity 2) Find time it takes to reach the apex 3) Find the vertical height from release point to apex 4) If the projectile isn’t symmetrical, calculate total height to apex 5) Find time down from apex (if start height = end height, time up = time down) KIN 300: Fall 2016 – Week 4 9/7/16 Natalie Wong 6) Find total time the projectile was in the air (sum of time up and time down) 7) Find the range or horizontal distance traveled by the projectile.


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