Chemistry Chapter 5 Notes
Chemistry Chapter 5 Notes CH 104
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This 1 page Class Notes was uploaded by Meghan Skiba on Tuesday September 27, 2016. The Class Notes belongs to CH 104 at University of Alabama - Tuscaloosa taught by Stephen Woski in Fall 2016. Since its upload, it has received 22 views.
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Date Created: 09/27/16
Chemistry 104 Chapter 5 Chemical Reactions Chemical Reactions Reactant Product Balanced Equations Atoms in the reactants and products must equal eachother Oxidation/Reduction Oxidation reactions: electrons are lost Reduction reactions: electrons are gained Avogadro’s Number the number of a thing that makes up a mole of that thing 12 eggs is a dozen 6.022 x 10^23 eggs is a mole Conversion: 1 mol/6.02 x 10^23 OR 6.02 x 10^23/1 mol Atomic Weights and Moles Carbon’s atomic weight is 12.01 amu Carbon’s molar mass is 12.01 g/mol 1 mol of carbon weighs 12.01 g Formula Weight I. calculate formula weight by writing the formula and determining the number of atoms of each element from the subscripts II. multiply the number of atoms of each element by the atomic weight and add the results Mass to Moles Calculation mass (g) x mol/g = moles moles x g/mole = mass (g) i. identify the original and desired quantity ii. write out conversion factors iii. set up and solve the problem Percent Yield percent yield = (actual yield (g)/theoretical yield (g)) x 100%
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