Week 6 Notes
Week 6 Notes PHY 2460 - 02
Popular in Concepts in Physics for Middle Childhood Education
Popular in Education, Physics
This 3 page Class Notes was uploaded by Kristianna Notetaker on Sunday October 9, 2016. The Class Notes belongs to PHY 2460 - 02 at Wright State University taught by Joseph Childers in Fall 2016. Since its upload, it has received 5 views. For similar materials see Concepts in Physics for Middle Childhood Education in Education, Physics at Wright State University.
Reviews for Week 6 Notes
Report this Material
What is Karma?
Karma is the currency of StudySoup.
You can buy or earn more Karma at anytime and redeem it for class notes, study guides, flashcards, and more!
Date Created: 10/09/16
• Speeding Up Index o Something per something else = index o something/something else = speed/time = acceleration • To find acceleration… (two ways) 1. Data Table Way Example: t v Δt (t 2t 1) Δv (v 2v )1 a (Δv/Δt) 0s 5mph -- -- -- 2s 25mph 2 20 10 4s 45mph 2 20 10 2. Acceleration Equation: (a) = Δv/Δt (0s, 5mph) (4s, 45mph) a = Δv/Δt = (45mph-5mph)/(4s-0s) = 40mph/4s = 10mph/s v = v 0+ at v 0= v – at a = v – v /0 t = v – v /0 Example #1: If at 0 seconds, a truck is moving at 10mph and is at 30mph 10 seconds later, what is the acceleration of the car? a = v 1– v /0 v 0= 10mph v 1= 30mph a = 30mph – 10mph/10s-0s t0 = 0s t1 = 10s a = 20mph/10s a = 2mph/s Example #2: A car starts at 5mph and accelerates at a rate of 3mph/s. How long does it take to get at 30mph? t = v – v 0a à t = (30mph - 5mph)/(3mph/s) = 25/3 = 8.33 seconds • “Falling” o velocity: speed is increasing; direction o acceleration: constant o position: downward; if up positive, decreasing if up negative, increasing Graph A: Graph B: Graph C: Graph D: ACCELERATION positive negative Graph C Graph A t Speeding Up Slowing Down p E Graph B Graph D V n Slowing Down Speeding Up • Velocity is… o Speed (value) o Direction ( + or – ) a = Δv/Δt = v –2v /t 1– 2 1 absolute speed = velocity value bars! • Displacement o Area between V. curve and t axis o Displacement (Δx) = (v)(Δt) area (square) = base(b)height(h) area = 1/2bh (triangle) area (trapezoid) = 1/2bh (b +1b ) 2 Example: What is the displacement over 3 seconds? Δx = (v)(Δt) 10m/s =(10m/s)(3s) =30m or A = bh = (3s)(10m/s) = 30m 1 2 3
Are you sure you want to buy this material for
You're already Subscribed!
Looks like you've already subscribed to StudySoup, you won't need to purchase another subscription to get this material. To access this material simply click 'View Full Document'