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by: Carmela Kilback


Carmela Kilback
GPA 3.92

William Zoller

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About this Document

William Zoller
Class Notes
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This 2 page Class Notes was uploaded by Carmela Kilback on Wednesday September 9, 2015. The Class Notes belongs to CHEM 142 at University of Washington taught by William Zoller in Fall. Since its upload, it has received 17 views. For similar materials see /class/192554/chem-142-university-of-washington in Chemistry at University of Washington.




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Date Created: 09/09/15
Chapter 1 1 75 Solution aNote Distance Speed gtlt Time 0 2642 gal 1L 701L 701LX 185gal 185gal gtlt 254mz39 gal 470mz39 So you can drive 470 miles on a tankful b 05ldollarL gtlt 701L 36dollars The trip costs 36 dollars cNote Time Distance Speed 470mz39 470migtlt1k m 756km 06214mz 1h 866km and 756km 866km h 756km X 873h So that trip takes 873 hours 1 79 Solution The volume of the dorm is 1m3 1000L 3 331gtlt103L 3531ft 1m 11 gtlt12ftgtlt85ft11gtlt103ft3 11gtlt103 3 gtlt 1 31gtlt103Lgtlt1mm lm1n 1200L So it would take the air comditioner 26 minutes to change the air in the dorm once then 31x103L1200 26min 181 Solution Note mass density gtlt volume aVolume water in the pool 500m X250m gtlt 55 xw 2lgtlt103m3 1000L lgal X X 1m3 3785L So 55 X105gal water is needed to ll the pool to the average depth of 55 ft 5 lggtlt 10 ml X 1kg lml 1m3 lOOOg Mass 10gtlt103kgm3 gtlt21gtlt103m3 22X106kg and2lgtlt103m3 21gtlt103m3 55gtlt105ga1 b Densitywater 10gml 10 x 10 x103kg m3 So there is 22 X106kg water in the pool 191 Solution 1m3 3292m3 3531ft Volumeroom 100ftgtlt825ftgtlt125ft 103gtlt103ft3 103gtlt103ft3 gtlt Massparticles in the room 292m3 gtlt 50ng m3 15 X103Iug and Mass of each particle 75 gym X 1m 3 2 10 um 3 6 gtlt25gcm3 xii 20x10 5yg 8 So the number of particles is 15 X103Iug 20 X 10 5 ug 75 gtlt107 1m3 Lug 2 In each breath you take 0500L Xlo X 50 3 25 X10 ug particles wh1ch means you take 00L 1m 25 X 10 2 ug 20 X 10 5 ug 12 gtlt103 particles in each breath Chapter 2 222 Solution Mass of copper 6543 X 631g 413g Sulfer remain 631g 413g 218g 255 Solution Table for the elements with atomic numbers 25 7 Solution a Rn and 86 b Y and 3B c Po and 84 d K and 19


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