General Chemistry Week 4
General Chemistry Week 4 CHEM 101 - 08
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This 5 page Class Notes was uploaded by Samantha Weller on Sunday September 27, 2015. The Class Notes belongs to CHEM 101 - 08 at Radford University taught by Timothy J Fuhrer in Fall 2015. Since its upload, it has received 41 views. For similar materials see General Chemistry in Chemistry at Radford University.
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Date Created: 09/27/15
General Chemistry Week 4 Notes Limiting Reactions the reactant that controls the amount of product by being in a limited amount ZMQ 102 gtZMTQO Egan 20101 S l x If you regR 155 gr s oli Mg with 20 Liters of 02 which is the limiting reactant and how much product can be made i 5 S 50 k 39739 TEMP 20 L o If the reactant that is leftover after all the product that can be formed is formed ll Example 1 a Identify the Limiting and Excess Reactaht 2H2 02 21120 80g 80g Step 1 Identify the Limiting Reaetant go to males Larger number 80g H2 X m2 X 2 11101 Hag 39 11101 H20 excess reactant Qingg H2 2 11101 H2 Smaller number 303 02 X M2 X Emil H39 05 101 H20 limiting reactant 3200g 02 1 11101 02 Conversion Keys 1 Inc1H2 202 H2 1 me 02 3200 02 2 mo H2 1 1 111011120 1 mo 02 2 mo H20 Empirical Formulas a list of elements present in a compound and the mass percent of each a formula that gives the ratio of atoms in a chemical compound a formula that tells the identity and numbers of atoms in a molecule Elemental analysis ef nicetine reparts 213 g earhenl IE43 g hytlregen antl L493 g nitregen Determine the simplest empirical fermula fer ninetine Selutien Since a fermula is a mel ratie ef the elements are must eenvert these ameunts te mels sis gt airs mel efC atems IE43 g H nssa mel ef H atems l mel N H493g H W LIIIESE mel ef mtregen atems The ratie far these three elements is III IT39S mel ef C atems IE4E mel ef H atems ELDESE mel ef N atems dividing threugh h the smallest number we can get whale numbers 5D6C599H1N the empirical fermula fer nieetine is CEHelJ Reactions in Aqueous Solutions moles of soluteLiters of solution Mm Dilution equation M1 V1 M2 V2 What is the molarity of a solution made by dissolving 25 g of NaCl in enough water to make 125 ml of solution moles of solute mOlanty liter of solution 1 mole NaCl 25 g NaCl x 585 g NaCl 00427 mole 00427 mole NaCl 0125 L 034 M NaCl molarity procedure for determining the concentration measured volume to react with a solution of another substance the standard solution whose concentration is known Sample Problem 1 I How many 1an of 045MHC1 must be added to 25 mL of 100M KOH to make a neutral solution 1 Wf lll balanced equation g 29 g LDBH aimL 13ml 2 Find mols ofknown solution i i a r 1 39 u L 2 DD l quotlquot DEL 3 Use moi ratio to nd mols of unl 39iownIt 1 Hal 1 V V i Defy 4 Solve for the unknown 5 R I a quotm r l u39 If 1 T 39 i quot I iquot quot 3 myquot 39 ii M J I t CL r dissolve in water to produce electricity containing ions dissociate in solution but only to a small extent dissociate nearly 100 in solution dissociate in solution but only to a small extent
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