Calculus II HONORS
Calculus II HONORS MTH 1322
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This 2 page Class Notes was uploaded by Dejon Bednar on Saturday October 3, 2015. The Class Notes belongs to MTH 1322 at Baylor University taught by Qin Sheng in Fall. Since its upload, it has received 53 views. For similar materials see /class/217914/mth-1322-baylor-university in Mathematics (M) at Baylor University.
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Date Created: 10/03/15
Note on August 28 2006 Several folks including Gregory if I am correct asked the question how to solve Problem 33 in Section 71 today Surely this problem is bit tricky to solve Now let us take a close look at a solution procedure Let w Then w2 m or From the above we acquire that dx dw2 2wdw Therefore via a substitution sin dx sinw2wdw Qwsin wdw 11 Now we may use the integral by parts formula For this let u w d1 sin wdw It follows that du dw 1 icosw Thus wsinwdw iwcoswcoswdw iwcoswsinwc 7 xcos sin o 12 Substituting 12 into 11 we obtain the solution of the original integral sin dx 72 cos 2sin C where C 20 You may have better methods for solving the integral may not you MTH 1322Q SHENG Note on August 24 2006 Let us consider the following integral I tan d How can we solve it in an easiest way Here is an example tan dz wdz cosx 7 cos s Ch cos c dcos s cos c du u ilnu C 7 lncosx 0 Obviously two well known properties icosx7sinx and d lnu0 dx u together with a substitution rule are used in the above procedure Needless to say the strategy can be used for solving sirnilar integrals such as cot d MTH 1322Q Same
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