Notes for Lecture on Moments of Forces (October 1st)
Notes for Lecture on Moments of Forces (October 1st) ENGR 1100
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This 1 page Class Notes was uploaded by Rene Cardona on Monday October 5, 2015. The Class Notes belongs to ENGR 1100 at Rensselaer Polytechnic Institute taught by Wei Zhou in Fall 2015. Since its upload, it has received 65 views. For similar materials see Introduction to Engineering Analysis in Engineering and Tech at Rensselaer Polytechnic Institute.
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Date Created: 10/05/15
Introduction to Engineering Analysis Lecture of October 1st Moments of a Force Scalar Formulation The moment of a force about a point is de ned as the force multiplied by the distance 0 Ex If a 20 N force is applied at the end of 2 meter stick with perpendicular orientation to the stick you have 40 Nm moment 0 When multiplying the distance components by the force components you must multiply the ones that are perpendicular to each other such as Fx and the distance in the yaxis Cross Product 0 The cross product between two vectors gives you a vector that is orthogonal to both vectors 0 Orthogonal means perpendicular in 3 dimensional space 0 One way to solve for the cross product is CABsin6uc where A is the magnitude of the vectors 6 is the angle between them and uc is the unit vector of the cross product 0 The actual formula for the cross product between vectors A and B is ltAszAsz AszAsz AxByAyBxgt Moments of a Force Vector Formulation M F x r the moment of a force is the cross product of the position vector r and the force vector F