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## General Physics

by: Bart Thiel Jr.

8

0

5

# General Physics PHYS 201

Bart Thiel Jr.
Christopher Newport University
GPA 3.81

Costa Gerousis

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COURSE
PROF.
Costa Gerousis
TYPE
Class Notes
PAGES
5
WORDS
KARMA
25 ?

## Popular in Physics 2

This 5 page Class Notes was uploaded by Bart Thiel Jr. on Monday October 5, 2015. The Class Notes belongs to PHYS 201 at Christopher Newport University taught by Costa Gerousis in Fall. Since its upload, it has received 8 views. For similar materials see /class/219494/phys-201-christopher-newport-university in Physics 2 at Christopher Newport University.

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Date Created: 10/05/15
Chapter 12 Static Equilibrium 3 Static Equilibrium o Static Equilibrium implies the object is at rest static o Static equilibrium is a common situation in engineering o Principles involved are of particular interest to civil engineers architects and mechanical engineers Conditions for Equilibrium o Theanet force equals zero 0 F o If the object is modeled as a particle then this is the only condition that must be satisfied 0 The net torque equals zero 2 0 o This is needed if the object cannot be modeled as a particle 0 These conditions describe the rigid objects in equilibrium analysis model Equilibrium Equations 0 We will restrict the applications to situations in which all the forces lie in the xy plane 0 These are called coplanar forces since they lie in the same plane 0 There are three resulting equations 0 ZFX 0 0 ER 0 0 2 0 Axis of Rotation for Torque 5555 Equation 55 o The net torque is about an axis through any point in the xy plane o The choice of an axis is arbitrary Horizontal Beam Example 3 o The beam is uniform 0 So the center of gravity is at the geometric center of the beam 0 The person is standing on the beam 0 What are the tension in the cable and the force exerted by the wall on the beam Horizontal Beam Example 2 o Analyze 0 Draw a free body diagram 0 Use the pivot in the problem at the wall as the pivot o This will generally be easiest 0 Note there are three unknowns T R 6 T 5 Ti K 200 N 600 N 0 O 0 Horizontal Beam Example 3 3 o The forces can be resolved into RsinO Tsm 5300 components in the free body diagram Rcos 9 Tcos 53 O 0 Apply the two mm conditions of 4200 m 200 N equilibrium to obtain three equations Solve for the unknowns 00 O 0 00 0 Ladder Example 0 The ladder is uniform So the weight of the ladder acts through its geometric center its center of gravity 1 0 There is static friction between the ladder and a the ground nnnnnnnnnnnnnnnnnnnnnn n n a 0 O 0 Ladder Example 2 0 Analyze 0 Draw a free body diagram for theladder o The frictional force is fS us n 0 Let 0 be the axis of rotation o Apply the equations for the two conditions of equilibrium o Solve the equations

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