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## Week of October 5th lecture notes

by: Katlyn Burkitt

25

0

6

# Week of October 5th lecture notes MATH 115

Marketplace > Towson University > Mathematics (M) > MATH 115 > Week of October 5th lecture notes
Katlyn Burkitt
Towson
GPA 3.2
Basic Math for the sciences
Dr. David Buchoff

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Hey these are the notes for this weeks lecture in case you were late or missed one!
COURSE
Basic Math for the sciences
PROF.
Dr. David Buchoff
TYPE
Class Notes
PAGES
6
WORDS
KARMA
25 ?

## Popular in Mathematics (M)

This 6 page Class Notes was uploaded by Katlyn Burkitt on Friday October 9, 2015. The Class Notes belongs to MATH 115 at Towson University taught by Dr. David Buchoff in Summer 2015. Since its upload, it has received 25 views. For similar materials see Basic Math for the sciences in Mathematics (M) at Towson University.

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Date Created: 10/09/15
Math Notes Week of October 5 Drill October 5 2015 1 Find the inverse fx2x7alsowrittenasy2x7 x2y7 2yx 7 x 7 f1x 7 y 2 2 2 Find the inverse fx4x3 1alsowrittenasy4x3 1 x4y3 1 x14y3 x1 3 1 4 y 2 3x x f 1 1 3 a function fthat consists of two 2 1 1 0 ants one segment from 2 2 to second from 1 0 to 1 2 39aph its inverse O 1 21 i To do this switch riginal function a b to get the inverse of the line of the in b a Se tlo 31 Quadratic Function 2 Generalform flx 96 0 Standard fXax h2k agt0 the curve is up alto the curve is down h k To Graph 1 To determine if the curve is up or down 2 Determine the vertex h k 3 Find the x intercepts fx0 4 Find the y intercepts f0 Real world uses Radar TV dishes trajectory 2 Example le 2X 3 8 2 Find the x intercepts 02 2x 3 8 2M 3f28 x 322x 32 2 51 Find the y interc fx 2 3 8 fix 298 fixF2 188 Vertex 3 8 X intercepts 5 1 Y intercept 10 PositiveNegative Negative The line through the vertex is the axis of symmetry 2 To determine the vertex of a quadratic equation in general form fi zax bXC 2 2a b 1 27 Use the formula to nd the vertex The y value is the maximum if the equation is negative and the minimum if the equation is positive Miner 7th 2915 Graph the Function fx x 124 Find the vertex 14 2 Find the x Intercepts 02 x 1 4 x 1V24 ih 1V244 x lziZ Find the y intercept f0 0 124 124 Next step Graph 2 Given fx4x2 16x1000 a Determine with Minimum b Find the minimL 1 4 if fx has a minimum or maximum qr 3 mMaxi um b b X 2a f 1 261 V 100 f2984 So the minimum OCCURS at x2 but the minimum is 984 c Domain 0090 Range 0 Sec 41 Ex onential Functions fixi2x X y 4 116 3 18 2 14 1 12 0 1 1 2 2 4 3 8 4 16 1 1 To calculateanegative exponent rewrite 2 as ine the graph gradually gets closer to ybx isapositive up ardcurveifbgt1 gt m lt E 3 39C o V bx iv 0 npg ti1244wvnward curve if b lt 1 J fxbxc Cgt0 Shi s PClt0shift down fxbxccgtOShtZcltOshtZ xgt bx KH I xbx fxcbxcgt1 fxcbeclt1 Formula for compound interest m r 1 n 612p

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