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# STRUCTURAL TECH I CM 3505

LSU

GPA 3.86

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This 12 page Class Notes was uploaded by Porter Kirlin on Tuesday October 13, 2015. The Class Notes belongs to CM 3505 at Louisiana State University taught by K. Hebert in Fall. Since its upload, it has received 44 views. For similar materials see /class/222672/cm-3505-louisiana-state-university in Construction Management at Louisiana State University.

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Date Created: 10/13/15

CM 3505 Final Exam Topics List 1 Horizontal Shear stress in Beams Variables1fv V Q I b t h Basic Horizontal Shearing Stress Equation fv VQIb Be able to find Q at a given level then findfV at that level Be able to determine the shearing Force on nails Find fv max 3V2A in rectangular beams fv max 3V2A Rectangles at NA only Estimate Horizontal shearing stress in steel beams fv Vth 2 Deflection Variables AX Amaxw L E I W Deflection Limits SUCh as AAllow ACode ALL Allow Typical values L180 L240 U360 Will be stated in problem Deflection limit may be based on Total Load or Live Load only Deflection formulas from beam tables EX For Uniform Distribution full length of simple beam Am 5wL4384E1 Know when to use Wfor Live Load or Wfor Total Load Know when to use AX or Amax Superposition of deflection formulas 3 Framing Load distribution arrow symbols Determine w from Area Loads Determine beam loading from area loading 4 Selecting Wood Beams 115 Fb for repetitive members 3 or more spaced 24 or less Procedure 1 Determine beam loading W andor Ps usuallyjust W 2 Find Mmax 3 Find Vmax A Select a trial section Determine Fb for selected trial beam Appendix H Use 115Fb when appropriate Find Sr Sr MFb Compare Sr to S for selected beam Appendix 1 ICDU I 8 If S OK Proceedto shearcheck If S not OK return to step 4 If S is much larger than Sr a smaller member may be adequate 9 Check Shear max 3V2A or Ar 3V2Fv 10 Compare to Fv Appendix H or A Appendix I 11 If shear O K then proceed to deflection check If shear not OK select member that satisfies Ar using Fv for new member 12 Determine allowable deflection as required by problem statement ALL Allow or ATL Allow 13 If allowable deflection is stated for Live Load determine WLL 14 Calculate Am Ex Am 5wL43 84EI For Uniform Distribution full length of simple beam Use appropriate W E from Appendix H I from Appendix I Remember unit conversions 15 If Amax exceeds AAHOW select member with greaterI value return to step 14 If AAHOW exceeds Amax deflection check OK 5 Selecting Steel Beams Procedure 1 2 Determine beam loading Wandor Ps usuallyjust W Find M max Determine Fb based on information in problem statement 0 4 5 Find Sr Sr MFb Compare Sr to S from appendix J Make initial selection 9 Adjust selection based on problem statement criteria 7 Determine allowable deflection as required by problem statement ALL Allow or ATL Allow 8 If allowable deflection is stated for Live Load determine WLL 9 Calculate Am Am 5wL43 84EI For Uniform Distribution full length of simple beam Use appropriate W E from Appendix H I from Appendix I Remember unit conversions 10 If Amax exceeds AAHOW select member with greaterI value return to step 14 If AAHOW exceeds Amax deflection check OK Check shear only if asked for in problem statement 6 Columns Terms Crushing Buckling Slenderness ratio Variablesfc F0 Ar Per K r Compressive crushing of Columns fPA AspFc Buckling Pcr TltzElL2 IDAcr TIZZELr2 For pinned ends Lr Slenderness ratio End Conditions K Pinned at both ends Fixed at one end pinned at the other Fixed at both ends Fixed at one end free at the other KL Effective length Pa TcZEIKL2 PAor TEEKM2 or PAor PerA Intermediate lateral bracing Weak Axis Strong Axis Effective length per Axis KLr per axis Larger value of KLr indicates the critical axis 7 Trusses First determine external reactions for either method of analysis Truss analysis by joints Analysis of concurrent forces on a joint or node using equations of equilibrium ZFX 0 ZFy 0 Truss analysis by method of sections Isolate whole sections ofthe truss by making a cut through the members of interest Then use equations of equilibrium to determine member forces required to maintain equilibrium of the whole section ZFxO 2Fy0 ZM0 Moment equation to be applied at a joint or node this includes at reaction joints Tip Select a joint that will reduce the number of forces to be considered particularly forces from diagonal members When using the moment equilibrium equation 8 Comprehensive component of final exam Any topic from Test 1 or 2 is possible Old topics that will almost certainly be on the Final Exam as separate questions Pinned Frame Truss by Joints Shear and Moment diagram Old topics that will be needed to solve problems from the current material Force components for loads at an angle for pinned frames Reactions Beam andor Cantilever for pinned frames VM diagrams Trusses Beams Equivalent point loads used when determining reactions for asymmetrically placed distributed loads Concurrent Forces for truss byjoints Twoforce members for pinned frames Radius of gyration columns Axial Stress columns Bending Stress beams Section Modulus beams Moment of inertia beams CM 3505 Spring 07 Test 1 Sample Test This sample test discloses the types ofquestions and problems that can be expected on Test 1 This sample test is not intended to be representative of the quantity of problems or length oftime required to complete the test It is intended to be representative of the type of problems and questions that may be on the actual test but should not be seen as a limitation The separate topics list covers all areas of material that may be tested Part 1 is to be completed without notes or a calculator Part 2 is to be completed afterturning in part 1 A calculator and 1 sheet of notes front and back are allowed and must be turned in with part 2 Notes must be handwritten or typed and it is recommended that your notes show guidance for solving problems in the form of steps and procedures with notations ofthings to watch for how to handle a particular condition cautions etc No photocopies of solved problems from the HW solutions or textbook or any other published work will be allowed Part 1 To be completed without a calculator or notes 1 Short answer Stresses that tend to move layers in different directions are called stresses is the main stress typically associated with arches The is a vector that is equal in magnitude but opposite in sense to the resultant of all forces acting on a body How many supports does a cantilever have Describe a simple beam 2 True or False The equilibrant has twice the magnitude of the resultant Bending stress is the primary type of stress seen in a typical column Cables are always considered to be in tension The units of a moment are a force times a distance squared The cars in a parking garage are considered dead loads 3 Multiple choice Snow isa load a Live b Dead 0 Thermal d Weather The primary stress associated with arches is a Tensile b Masonry c Compressive d Shear A typical stable and determinate cantilever will have a three supports and 1 reaction b A pin and a roller 0 1 degree of indeterminacy d One support and three reactions 4 Draw the reactions associated with these symbols for supports 249 gram l J 5 Indicate the sense and magnitude of the other forces on the FBD of the twoforce members shown below 80K 50K 40 my qt 1 6 Indicate the stability and determinacy of the structures or members shown below 4 M TBL w 39 S7 945 FETEKNM 75 39 l 39 D39T A MIA Ms MNWMJLL 2 1 iv g Altat 39 7k 7 Draw the symbols for supports that create the conditions indicated Maximum of 2 supports per beam M Unstable 2 reactions 5 M n 7 Stable determinate r r Stable indeterminate 1 degree 8 Write an equation for summing the moments around point A for the cantilever and the simple beam below I M L l M12 1 14V rm VFXMA0 UV01 573 0 T A 9 H 1339 law A j i Ill 1 7 M kwL v l I Wigti FM letWU 539 7 9 I ZMASFif Jri 5y0 t0 Turn in this part of your test to get part 2 Part 2 is to be completed afterturning in part 1 A calculator and 1 sheet of notes front and back are allowed and must be turned in with part 2 Notes must be handwritten or typed and it is recommended that your notes show guidance for solving problems in the form of steps and procedures with notations ofthings to watch for how to handle a particular condition cautions etc No photocopies of solved problems from the HW solutions or textbook or any other published work will be allowed 1 Determine FX and Fy forthe Vectors shown F30K 142 2 Determine the magnitude sense and direction of the resultant of the group of vectors 40K 3 3 Determine the magnitude and sense of the forces in members A and B ma lbs I v 8 2 3 l go 7 3i 2 00 H s 4 Determine the magnitude and sense of the moment ofthe force with respect to point 0 and point A In other words find Mo and Ma I 001 3 x I quot 3 0k 4 X39 i 5 Indicate the equivalent point loads and locations on a FBD forthe distributed loads shown below 0 K ft 9 Kfe Ale 6 gtl l gtl8 6 Determine the support reactions for the cantilevered beam shown below 4K InkFr k l l gt I L N A 1 III 7 Determine all support reaction components for the simple beam shown below 300 lb 100 WE 50 lbR 1 4 l Lr l 2 l 8 Determine the horizontal projected load in lbsft then place an equivalent point load on a FBD of roof segment AB Show all reaction directions You do not need to show reaction values just label the arrow with the component names Dead load is 20 lbft of sloped length Snow load is 15 lbft of horizontal projection 9 Determine all support reaction components the distance y and the tension in segment AC for the cable structure shown below k o39603960 gtl 10 Determine all the force components and reactions acting on both members of the pinjointed structure shown below and label FBD s with the results Zoob If 25 Va i 8i ll Turn in your notes sheet with this part ofthe test

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