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# General Physics II PHY 212

Syracuse

GPA 3.64

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This 38 page Class Notes was uploaded by Clement Bernier on Wednesday October 21, 2015. The Class Notes belongs to PHY 212 at Syracuse University taught by Xiangjun Xing in Fall. Since its upload, it has received 13 views. For similar materials see /class/225625/phy-212-syracuse-university in Physics 2 at Syracuse University.

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Date Created: 10/21/15

Lecture 102 Copyright 2008 Pearson Education Inc publishing as Pearson AddisonWesley D Which of these diagrams represent the same circuit r l 39 W i L ltgt gt T TT a b c d A a and b B b and c C a and c D a b and d E a b and c Copyright 2008 Pearson Education Inc publishing as Pearson AddisonWesley Review of last lecture Resistors in series RCq 2 R1 R2 RN series resistors Resistors in parallel l R parallel resistors N Copyright 2008 Pearson Education lnc publishing as Pearson AddisonWesley EXAMPLE 3210 A combination of resistors EXAMPLE 3210 A combination of resistors What is the equivalent resistance of the group of resistors shown in FIGURE 32267 FIGURE 3226 A combination of resistors AAAA gt 250 gt Copyright 2008 Pearson Education Inc publishing as Pearson AddisonWesley EXAMPLE 3210 A combination of resistors FIGURE 3227 The combination is reduced to a single equivalent resistor OQ AAAA VVVV 400 lt lt gt gt 25 2 AA vvvv ltgt 25 Q 1 154 1 ltgt OQ AAAA VVVV w qu ahm Tn Mi eresley A n Rank in order V9 from brightest to C dimmest the 1 3amp9 identical bulbs A D to D ACDgtBgtA BAgtCDgtB CABCD DAgtBgtCD EAgtCgtBgtD Copyright 2008 Pearson Education Inc publishing as Pearson AddisonWesley How should Ammeters be Connected Ammeter measures the current ow through it Ammeter must be connected in series with circuit elements Whose current needs to be measured Ammeter also has resistance very small Copyright 2008 Pearson Education Inc publishing as Pearson AddisonWesley How should Voltmeter be Connected Voltmeter measures the potential difference between two points on the circuit where it is connected Voltmeter must be connected in parallel with the circuit element whose voltage needs to be measured Voltmeter has very large resistance so that the current owing through it can be neglected Copyright 2008 Pearson Education Inc publishing as Pearson AddisonWesley ProblemSolving Strategy Resistor circuits H Assign current to each branch 2 Use Kirchhoff s Junction law to nd relation between currents 3 Using Kirchhoff 5 loop law and Ohm s Law to set up one equations for each loop 4 Solve these equations Copyright 2008 Pearson Education Inc publishing as Pearson AddisonWesley Example two loop circuit Find the current through and voltage across the lOOOhm resistor 300 I 100 I 200 I 19V 12V i T Copyright 2008 Pearson Education Inc publishing as Pearson AddisonWesley RC Circuit Charging a Capacitor 3 Switch closes at I I 0 s u R 4i INAI A 5 L C Copyright 2008 Pearson Education Inc publishing as Pearson AddisonWesley FIGURE 3235Krgecgltlr ults DISCharglng a capaCItor utt a Before the switch closes The switch willu close at r 0 lt gt lt ltAVR 0 Charge Q0 AVC QOC b After the switch closes C e 71R Charge Q The cun39cnt is reducing the AVC QC charge on the capacitor Copyright 2008 Pearson Education Inc publishing as Pearson AddisonWesley 39239 The time constant for the discharge of 2 0 2 9 this capacitor is 11 A 5 s 1 B 1 s C 2 s D 4 s E The capacitor doesn t discharge because the resistors cancel each other Copyright 2008 Pearson Education Inc publishing as Pearson AddisonWesley 3147 Solve a Current is de ned as I QAt so the charge delivered in time At is Q 142 150 A080 s 120 c b The drift speed is J IA 1 150 A Vdi Z Z 5617x10quot ms me me 7rrne 7r00025m85X1028m 3160X10719C At this speed the electrons drift a distance d 5617 x1074 ms080 s 449 x1074 rn 045 mm 3148 Solve The total charge in the battery is Q 1A 90 A3600 s 32 x105 c 3153 Solve a mi N 1 I 1 b since 1 AQAt for in nitesimal changes IdiQ 4tr2472 d d C a The value ofIat t 20 s is zero This is because the charge having reached its maximum value has stopped w Sc a UL 3163 Model Assurne the battery is ideal Visualize The current supplied by the battery and passing through the wire is 1 AVLMR A graph of current versus tirne has exactly the sarne shape as the graph ofAVtm with an initial value ofIn mphR 15 V30 g2 050 A The horizontal axis has been ehangedto seconds Ilr ms 1 rm ll 72m Solve eunent is 1 dQdt Thus the total charge supplied by the battery is Q 1 Id area under the currentversustinie graph u 57200 s050 A 180x103 c 3168 Solve a The charge delivered is 50x103 A50x1039 s 25 c b The current in the lightning rod and the potential drop across it are related by Equation 3122 Using 0 for iron from Table 312 97x10 8 Qm 50 m 50x10 A ALLI7 243x10 4mz AV 100 V This is the area required for a maximum voltage drop of 100 V The corresponding diameter of the lightning rod 74 z r If wggxlomggm 7r 7quot him pL Qm Law WQRK3H 6 9 911 Ema M W we pm A EA 339 Nb 4935 2444 Noe13 EV E13 E15 m v clamV gt mwvf J LP VA I QEWVBLMLQQ v w M 23Lquotl E A MW 9 7 s opbbwlgl v mV l V3 Lalx o ms 103 a m Marga WM 3 4 chi 34 Gut 0 waxE Em at W O 4n 9 SD quot 5Vgt I L Ioquot c 9 Dumb GHW J 016g 6 th 0 1 mix v at 9W9 11 46 gz u t 7 L a 3 3 4793 g39g 4w 0 3 ga qua 383 351 111126 31 S 32quot Wk 14 N Llrr 62 V9 1 Q worm M w P oa o39wc39m 3quot a as ch V M thjsxuS 1 moan guo L 64411 I eol 3 J z 39 Eu um M a oL 3T use 205 Vole M Q Rad r 6 EMMZQ a km Map w P amp omidhgrrdw who My VL AC2 39 M 4 Mat ML W 2 W Vma 4 ne39oW ML Aa n4AWamphm amok Knot Q O Lhrab frf39 hedkiietb r1 1 Q 2M m x39F FN V 2 Z 1 L l W MWQW if 4 w 4 mo m M JreTv i gt t a L V M20 r C FQ 2 V a okib th 7c 14 Wok AW Law 4quot Mau 39h EKQ TJgL Lecture 102 Copyright 2008 Pearson Education Inc publishing as Pearson AddisonWesley D Which of these diagrams represent the same circuit r l 39 W i L ltgt gt T TT a b c d A a and b B b and c C a and c D a b and d E a b and c Copyright 2008 Pearson Education Inc publishing as Pearson AddisonWesley Review of last lecture Q t I 22 239 Resistors in series W Copyright 2008 Pearson Education Inc publishing as Pearson AddisonWesley EXAMPLE 3 210 A combination of resistors EXAMPLmwi mminainofresistrs 2 goflfq39f go qon 4371 I Pearson AddisonWesley wi J 1 l f syn Re t 4m Mm EXAMPLE 3210 A combination of resistors FIGURE 3227 The combination is reduced to a single equivalent resistor OQ AAAA VVVV 400 lt lt gt gt 25 2 AA vvvv ltgt 25 Q 1 154 1 ltgt OQ AAAA VVVV w qu ahm Tn Mi eresley Rank in order from brightest to dimmest the em identical bulbs A to D kCDgtBgtA M ngk 4 ABCD 7 L r P 3 V3 F V0 VpL E I C quot W 3922 K It R Copyright 2008 Pearson Education Inc publishing as Pearson AddisonWesley V g gt C F7P ll How should Ammeters be Connected 39 Ammeter measures the current ow through it Ammeter must be connected in series with circuit elements whose current needs to be measured Ammeter also has resistance very small m U Copyright 2008 Pearson Education Inc publishing as Pearson AddisonWesley How should Voltmeter be Connected 39 Voltmeter measures the potential difference between two points on the circuit where it is connected Voltmeter must be connected in parallel with the circuit element whose voltage needs to be measured Voltmeter has very large resistance so that the current owing through it can be neglected V R I a l b i 39 Copyright 2008 Pearson Education Inc publishing as Pearson AddisonWesley ProblemSolving Strategy Resistor circuits H Assign current to each branch 2 Use Kirchhoff s Junction law to nd relation between currents 3 Using Kirchhoff 5 loop law and Ohm s Law to set up one equations for each loop 4 Solve these equations Copyright 2008 Pearson Education Inc publishing as Pearson AddisonWesley Example two loop circuit Find the current through and voltage across the IOOOhrn resistor 1 Juwmi oy LCM quotI 2 Sit t1 quot 2000 12 3 11 WP 2 11V 1100an 10 Copyright 2008 Pearson Education Inc publishing as Pearson AddisonWesley 96011 XL WOJIXI va f g C Wk r Son quot 3 I a A412 leaLXI goo x j D V x3 Q qwa kloa ij 339 21VtLVgt 33V 1 33 K Moon quot O O3A 1quot ILI 1quot O o I 0014 3 aquot C 091er 0003A i 200A 90 A 1519 41 U 01 2V LWJ39L A r 0 03 A qu 1W amp RC Circuit Charging a Capacitor a S39Wi ih Closaas at m 0 S i GMT 2 m 4 w t o w I Grk Copyright 2008 Pearson Education Inc publishing as Pearson AddisonWesley Voii39osgi OM LG 0 Law C90 C VC 2 c 392 O IACf 99 a C IR TCquot 99 0 tao G E quotEquot 0 Q 2 8 C CMacCw M Changt mph 8 lt 600 E KICJCHZ 95 c lt4 vamjr I 3 dQGZ Equot 2 quot39 96 gt0 C Ott ffacaw zz W i RC OCVOMS 1N5 chaung Wadin o 39b 00 Loop LCMJ 00f W CW An Ci fCUi t AVc quot39 Id K 0 a Befeire closes Mic Cf 7quot 33 I63 200 2 26 I quotEQC39Wi Ro fzg 20 v W 3 2 X s f gt13 2 W a t C quot i7 2 I I C90 006 9 39 40 t o t m 9 e 1 3c 6 4quot Gk Tb closes IL E i i N I Copyright 2008 Pearson Education Inc publishing as Pearson AddisonWesley

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