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by: D'angelo Will


D'angelo Will
GPA 3.95


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About this Document

Class Notes
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This 2 page Class Notes was uploaded by D'angelo Will on Thursday October 22, 2015. The Class Notes belongs to PORT 1 at University of California Santa Barbara taught by Staff in Fall. Since its upload, it has received 29 views. For similar materials see /class/226878/port-1-university-of-california-santa-barbara in Portuguese at University of California Santa Barbara.




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Date Created: 10/22/15
ECE137B High Frequency Amplifier Crib Sheet Page 1 Basics Transistor small si nal hi h fre uenc models K pi model CD B H C C Che Innka Cmdt C g 1 lt ltgt mm m f RE CD V IgtR f gm2 C CM gV gmareIcVT m be R E R0 VAIC E R C quotTquot model AVA39A Makes common base analysis much easier gt Both these models are only approximate quot2 CDquotVeb 2 CD being quotgoodquot up to ft Additionally Rb is often an important parasitic not discussed g V much in 137B m 2b Bl Qimnlification of Emitter l quot approximate only check notes for bounds on validity fr C rere RE RE mgmn4REa4RE fit CM If R re REre 5 1re RE Common Emitter Stage C 1 311m B VatV39 VmVM C Ri CVbe EERLeq E 1 RiCn CM1 ngleq RleqCu CL D a2 RRleqCMCL CMC C CL Jg gmvbe Tun CMgm V 0 MB 1 als 1232 ECE137B High Frequency Amplifier Crib Sheet Page 2 Emitter Follower Stage C 1 srzm D E VMVgen VmVgenMBW I B TEAquot C given that Am rere Rm I C REE C Vbe EERLeq E 1 CnRn re Rleq Avmb D J CM Rilltransistor input resistance gmvbe CLRLeqtransistor output resistance a2 Rtransistor input resistancevaq re AQQQQQQ Ta gmC General Solutions of Problems Nodal analysis Know how to do this 1 1Write the nodal equations sum of the 2 Use Cramer39s rule to solve currents0 at each circuit node and put Y le YB the resulting equations in matrix form the m Y s being various combinations of gm39s 21 Y22 Y23 0 lR39s and sC s Y31 YSZ Y33 0 Y Y Y Y V V I 11 12 13 14 1 m m Y41 Y42 Y43 0 V Y21 Y22 Y3 Y2 V2 0 Y11 Y12 Y13 Y14 m Y31 Y32 Y33 Y34 V3 0 Y21 Y22 Y23 Y24 Y41 Y42 Y43 Y44 V4 Vm 0 Y31 Y32 Y33 Y34 Y41 Y42 Y43 Y44 3 This comes out as 4 ksm Coc1502522m VM VM m1b1sb2s2m It I doid1sd2s II 11 mb 1a1sa2s2m aWthh 15 lelded through to get and the poles and zeroes are found by factoring the numerator and denominator 1f Present m 15 the number 0f zeros The separated pole approximation if minus the number of poles in the transfer applicable makes this factoring easy function 5 To find the impulse response do a 6 To find the sinusiodal frequency partial fraction expansion and then take the response set s jw inverse LaPlace transform


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