New User Special Price Expires in

Let's log you in.

Sign in with Facebook


Don't have a StudySoup account? Create one here!


Create a StudySoup account

Be part of our community, it's free to join!

Sign up with Facebook


Create your account
By creating an account you agree to StudySoup's terms and conditions and privacy policy

Already have a StudySoup account? Login here


by: Hailey Halvorson


Hailey Halvorson
GPA 3.8

J. Martinis

Almost Ready


These notes were just uploaded, and will be ready to view shortly.

Purchase these notes here, or revisit this page.

Either way, we'll remind you when they're ready :)

Preview These Notes for FREE

Get a free preview of these Notes, just enter your email below.

Unlock Preview
Unlock Preview

Preview these materials now for free

Why put in your email? Get access to more of this material and other relevant free materials for your school

View Preview

About this Document

J. Martinis
Class Notes
25 ?




Popular in Course

Popular in Physics 2

This 1 page Class Notes was uploaded by Hailey Halvorson on Thursday October 22, 2015. The Class Notes belongs to PHYS 105B at University of California Santa Barbara taught by J. Martinis in Fall. Since its upload, it has received 12 views. For similar materials see /class/227125/phys-105b-university-of-california-santa-barbara in Physics 2 at University of California Santa Barbara.




Report this Material


What is Karma?


Karma is the currency of StudySoup.

You can buy or earn more Karma at anytime and redeem it for class notes, study guides, flashcards, and more!

Date Created: 10/22/15
01 92 A wheel rolling at speed 1 will have angular velocity 0 vT If we consider this problem by using the CoM the KB is the sum of the COM translational motion plus the rotation around the COM So 7 2 l 2 2 2 27 2 KEing 2140 72Mv 22MR vT 74Mv Now we can also consider the point of the wheel touching the ground The special feature of this point is that it is momentarily at rest Therefore all the kinetic energy is due to the rotational motion around that point If we remember the parallel axis theorem 1 10M Mh2 where h is the distance from the CoM to the translated axis we get that 1 around this point is 32MR2 So 7127 2 KEiglw 74Mv This is identical to what we found above 02 99 Well do this integral in cylindrical coordinates in which the volume element is dV pdp d9 d2 So L 27r R I d2 d9 dpp p2 0 0 0 R M 27f L d 3 7 M lt m 1 7MP 2 The products of inertia are zero due to the re ective symmetry of a cylinder across the z 7 2 and y 7 2 planes When we integrate over a mass distribution that is even in z and y multiplied by a single factor of z or y which will be odd we get an integral over an odd function which is necessarily zero 03 910 031 a L M271 2 Adzfz igML


Buy Material

Are you sure you want to buy this material for

25 Karma

Buy Material

BOOM! Enjoy Your Free Notes!

We've added these Notes to your profile, click here to view them now.


You're already Subscribed!

Looks like you've already subscribed to StudySoup, you won't need to purchase another subscription to get this material. To access this material simply click 'View Full Document'

Why people love StudySoup

Steve Martinelli UC Los Angeles

"There's no way I would have passed my Organic Chemistry class this semester without the notes and study guides I got from StudySoup."

Amaris Trozzo George Washington University

"I made $350 in just two days after posting my first study guide."

Bentley McCaw University of Florida

"I was shooting for a perfect 4.0 GPA this semester. Having StudySoup as a study aid was critical to helping me achieve my goal...and I nailed it!"


"Their 'Elite Notetakers' are making over $1,200/month in sales by creating high quality content that helps their classmates in a time of need."

Become an Elite Notetaker and start selling your notes online!

Refund Policy


All subscriptions to StudySoup are paid in full at the time of subscribing. To change your credit card information or to cancel your subscription, go to "Edit Settings". All credit card information will be available there. If you should decide to cancel your subscription, it will continue to be valid until the next payment period, as all payments for the current period were made in advance. For special circumstances, please email


StudySoup has more than 1 million course-specific study resources to help students study smarter. If you’re having trouble finding what you’re looking for, our customer support team can help you find what you need! Feel free to contact them here:

Recurring Subscriptions: If you have canceled your recurring subscription on the day of renewal and have not downloaded any documents, you may request a refund by submitting an email to

Satisfaction Guarantee: If you’re not satisfied with your subscription, you can contact us for further help. Contact must be made within 3 business days of your subscription purchase and your refund request will be subject for review.

Please Note: Refunds can never be provided more than 30 days after the initial purchase date regardless of your activity on the site.