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# AEM 264 Course Study Materials AEM 264

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This 18 page One Day of Notes was uploaded by Katie McCoy on Sunday January 18, 2015. The One Day of Notes belongs to AEM 264 at University of Alabama - Tuscaloosa taught by John Jackson in Fall. Since its upload, it has received 490 views. For similar materials see Dynamics in Engineering and Tech at University of Alabama - Tuscaloosa.

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Date Created: 01/18/15

Review for Test 27 D namics AEM264001 amp002 Spring 2015 Tuesday March 3 2015 700845 PM 127 Biology Bldg This test consists of multiple choice questions most of which appeared on previous Fundamentals of Engineering Examinations The inside front cover of your text will be attached as an equation sheet This is a closed book closed note test Circle the answer on the test paper that is closest to the correct answer For problems that require numerical computation show your work in detailin thespaceprovided in the examination booklet DO NOT WRITE ON THE PAGES RESERVED FOR CIRCLING YOUR ANSWERS If you do not follow these instructions you WILL receive a ZERO for each problem for which you have not done this This is regardless of whether or not you circled the correct answer This means your instructor must be able to find your solution and must be able to follow your computations Topics Covered Chapter 13 Application of Newton s 2 Law Xi mg YOU must draw good free body diagrams and kinetic diagrams You should be able to apply the 2139 Law using rectangular coordinates You should be able to apply the 2 Law using normaltangential coordinates Remember 3 is tangent to the path of the motion but a is not The acceleration a has two components We did not cover section 1236 You should know Newton s Law of Universal Gravitation but you do not need to know the constant G or the mass of the earth We did not cover section 137 Chapter 14 Work 8 Energy Conservation of Energy Be able to find work of a force work of a spring work of a weight Be careful with signs What are conservative forces Apply the principle of work amp energy to solve various applications Do you know the de nition of kinetic energy Remember that the two energy principles in this chapter are scalar equations not vectors Remember that forces perpendicular to the path of the motion do no work You must draw appropriate sketches Sometimes the energy principles must be supplemented by 13 mg and the kinematical relations What is the definition of mechanical efficiencyquot What is the conversion factor for hp in terms of ft Ib For watts N ms in terms of hp Apply the principle of conservation of energy to solve various applications When using the principle of conservation of energy you must define a datum on a sketch of your system Can you find the potential energy of a weight Of a spring Do you know when it is not possible to write an expression for potential energy 25 s cancellation on 2252015 oblique impact will be covered on teat 3 Chapter 15 Impulse and Momentum Use the principal of impulse and momentum to solve applications Draw appropriate sketches to show linear momentum my and impulse f Edi What are impulsive forces Do you understand when nonimpulsive forces may be neglected Can you recognize when linear momentum is conserved Can you use conservation of impulse and momentum to solve central and obligue collision applications We did not cover sections 155 159 Remember you may need to write constraint equations such as we learned to do for pulley problemsquot Remembers you may need to use the definition of relative motion T Eook News mam l 5 p6 1 m quot m 39 Newmm WW 0 wwwamonm R fgkg O FEE m MMh r WWEUO gtm ltc 35 g m W mem QM diaqm mg M w KWMC WWW 0 6 Momw 2 233 de T me 2sz max ZFJ may i rmz mmm My 6 153 39wzmgawamE N PWN 8me 4 OO G35OQw 3m 6091 Z F8 WM Na 4 10 6 400 SEW NQ ZWJ N 4OOCOS W5 33mm 5M m Sz FED i l Kmf c WGEN 4 N 4w M xiv ye 715 m 61mg m v VNmIS J W mammn 13 mt gamma 0W WW Equme 0 WWW w WWW Ta mm M momma Elia mm 222 mm 2900 SE w 3r iFnU in Mb mm mm W m 0140 a wow CWquot Foigcoga Pow 52 I WOW WNW WYCE Mw U14 5 Ff CL2 z NEW 0 3mm Wu Uquot1 a in K821 likgil T UP 3 TL lmyp1quot V2 mVfquot 12le t f39i39Zme Cihmvf WW 0 Wimon Camfd w midway lil WV M NK LMST IIZ 3 i3 dismmmmn P ig 01mm force 39 v v N quot 1 3 2 Nmfg VOW i E Waemg m LAWS 3 N IS PGWEY dUdt 39 Fquot V WP 6160 IQ bis E icimm w Paw 5 a r CUSJYCAHC wlt E w 6 qr 03 mm mm PU R BWGH WW 6 Wm m mm EMS UC 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