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## General Physics II

by: Cayla Kilback

22

0

4

# General Physics II PHYS 408

Cayla Kilback
UNH
GPA 3.64

Staff

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COURSE
PROF.
Staff
TYPE
Class Notes
PAGES
4
WORDS
KARMA
25 ?

## Popular in Physics 2

This 4 page Class Notes was uploaded by Cayla Kilback on Thursday October 29, 2015. The Class Notes belongs to PHYS 408 at University of New Hampshire taught by Staff in Fall. Since its upload, it has received 22 views. For similar materials see /class/231704/phys-408-university-of-new-hampshire in Physics 2 at University of New Hampshire.

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Date Created: 10/29/15
l p p2 v P1 7 V2 V1 V One mole of gas in the picture rst undergoes an isothermal compression at T293K green from 24 liters V1 to 6 liters V2 then a constant volume cooling blue and then a constant pressure expansion 1 What is the approximate pressure at pl a 10E3 Pa b 10E4 Pa c 10E5 Pa d 10E6 Pa e Not enough info We use pvnRT then you can calculate it However a quick thing to remember is that at standard Temp room temperature and standard Pressure 1 Atmosphere the volume of 1 mole of gas is 24 liters Thus the pressure is 1 atmosphere 10110quot5 Pa 2 What is the pressure at p2 a 05 pl b pl c 2pl d 4pl e Not enough info The green curve is an isotherm thus the temperature is constant That means that pV nRT is also constant If the volume is divided by a factor of 4 the pressure must go by a factor of 4 3 How much work is done by the gas during the constant volume cooling blue a0 b V2p2p1 c V2p1p2 d p2V2T e Not enough info When the volume remains constant no work can be done 4 How much work is done by the gas during the constant pressure red a 0 b pl VlV2 c p2V2Vl d nRTlnVlV 2 e nRTlnV2Vl The work done is WpAVpV V 5 How much work is done by the gas during the isothermal green a 0 b gt0 cl lt0 1 1 e Not enough info The area under the curve is negative because we go to the left so the WltO 6 a pl VlV2 b p2V2Vl c nRTlnVlV 2 d nRTlngV2Vl 1 e NI Integrate W pdV pn RTN so Wn RTnVfNi RL Circuit R Ve0 After one 5 the current is at 63 le391and the voltage at 37 e39l of the maximum value RL Circui rs VS RC Circui rs RC Circuit is V1 e0 After one 5 the current is at 37 e391and the voltage at 63 le39l of the maximum value RL Circui rs After one 5 the current is at 37 e39l of the maximum value VS RC Cir39cui rs it i Ioe CJJCRC After one 5 the current is at 37 e391 of the maximum value Mu rual Induction If two coils are close together the ux due to one will affect the other and Visa versa We call this mutual induction We denote it withM instead of L M N2q321 N1q312 l1 12 A change in the current of one coil thus sets up an Emf in the other coil These Emfs are give by di di M 1 a M 2 dl dl This is the basis of transformers More on transformers is in Chapter 33 Secll Which charge exerts the largest force on the test charge q AA ch D NE1 What is the direction of the force on the test charge q A Left B Right up D Down E None of above slyly l Which of the pictures V F correctly represents the 1 electric field of the 4 quot charges 393 ABQDE xi A has field lines crossing 39 7 so it is incorrect f B has disconnected field quot lines and field lines right next to each other that are in the opposite direction C looks normal D is not symmetric and has field lines right next to each other that are int e opposite direction

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