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## GENERAL PHYSICS

by: Kendrick Wilderman

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# GENERAL PHYSICS PHYS 2114

Kendrick Wilderman
OK State
GPA 3.82

Staff

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## Popular in Physics 2

This 0 page Class Notes was uploaded by Kendrick Wilderman on Sunday November 1, 2015. The Class Notes belongs to PHYS 2114 at Oklahoma State University taught by Staff in Fall. Since its upload, it has received 13 views. For similar materials see /class/232924/phys-2114-oklahoma-state-university in Physics 2 at Oklahoma State University.

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Date Created: 11/01/15
Chapter 26 Capacitance oEach capacitor is made of two conductors that carry equal amount charges but with opposite signs 0 0 01 o go Ad o 47rgoabba where C QV Concept question The capacitance of a parallel plate capacitor is proportional to the plate area proportional to the charge stored independent of the plate separation proportional to the potential difference between the plates proportional to the plate separation mcopw Concept question The capacitance of a parallel plate capacitor can be increased by A increasing the charge B decreasing the charge C increasing the plate separation D decreasing the plate separation E decreasing the plate area Concept question If the charge on a parallelplate capacitor is doubled A the capacitance is halved B the capacitance is doubled C the electric field is halved D the electric field is doubled E none of the above Applied question Why is it dangerous to touch the terminals of a high voltage capacitor even after the voltage source has been removed What can be done to make the capacitor safe to handle after the voltage source has been removed Electrostatic energy stored in a charged capacitor U CAV2 or 2 U29 2C The work done to charge a capac on dW V39dq39z qu39 Q Q2 W dW d39 I 61 q 2C 1 C Concept question Let Q denote charge V denote potential difference and U denote stored energy Of these quantities two different capacitors of C1 and 02 in parallel must have the same A Q only B Vonly C U only D Q and U only E Vand U only Concept question Let Q denote charge V denote potential difference and U denote stored energy Of these quantities two different capacitors of C1 and Cg in series must have the same A Q only B Vonly C U only D Q and U only E Vand U only Capacitors with Dielectrics oDieIectric material A dielectric material is an insulating material such as air oil paper porcelain and silicon oDieIectric constant K Material Constant K Vacuum 10 Air 100054 Oil 45 Silicon 12 A parallelplate capacitor of plate area A is filled with two dielectrics as shown What is the capacitance of this capacitor A Electrostatic Force The electrostatic force between two point charges obeys Coulomb39s Law lfqu1q2f r2 where k L 899 x109Nm2 IC2 471380 and 80 885 X1O1ZCZ Nm2 Problem Solving If two persons 50 kg each stood at arm39s length 05 m from one another and each person lost 1 of his electrons is what is the repulsive electrostatic force between them A 21 N B 21000N c 21x1016N D 21x1025N Q001x25000moXNAe 2 4x1 076 F21x1025N Problem solving A 2 MC charge is placed aT The origin An idenTicaI charge is placed 2 m from The origin on The xaxis and a Third idenTicaI charge is placed 2 m from The origin on The y axis The magniTude of The force on The charge aT The origin is A 90x 103 N B 64 x10393 N c 13 x10quot2 N D 18 x10quot2 N E 36 x10quot2 N Electrostatic Field Definition of an electric field A FqEF 0 Hr is a vector field oThe unit of Er39 is NC Concept Question An electron e and a pr39o ron p are on The x axis The directions of The elec rr39ic field If poin rs 1 2 and 3 respec rively are 1 2 x X 3 x V O I p gtlt gt lt gtlt gt lt lt gt gt gt lt lt lt mcowgt Problem solving Calculate the electric field due to the nucleus of a hydrogen atom at ro529xi Magnitude of E39 E kqr39z k 8 99x109 NmZc2 q e 16X103919639 r0529x1010m E kqrzz 51x10 1NC Direction of E E E ElecTric Fields The magnifudes of some eecrric fields FIELD LOCATION VALUE NC Inside a household Cu wire 10392 Near The charged drum of a phoTocopier 105 EIecTric breakdown in air 3x106 AT The 0529 K radius of a 5X10 Surface of a uranium nucleus 3x1021 Problem solving There is a uniformly charged ring wiTh line charge densiTy A and a radius of R a CalcuIaTe The elecTric field along iTs cenTraI axis aT 2 above The ring b DeTermine The posiTion 20 where The elecTric field reaches The maximum along iTs cenTraI axis Distributions of Electric Charges 1 Poin r charge 4 Si Q 2 Line charge densi ry 7L 3 Surface charge densi ry c5 4 Volume charge densi ry p R L a 2LQL 0QA pQV Cm Cm2 Cm3 For a charge distribution with q at ri The net electrostatic force on 40 at F is m Fzk L Hi The net electrostatic field at F is EFnhzmqlq FFZ i The Principle of Superposition Electric Field Lines Electric Field Lines help you to visualize electric field in space 1 The Density of Electric Field Lines illustrates the magnitude of electric field The Direction of Electric Field Lines indicates the direction of electric field Electric Field Lines start from positive charges source and terminate at negative charges sink Electric Field Lines never originate at no charges nor terminate at no charges Electric Field Lines Draw elec rric field lines for The following charge dis rribu rion 1 A single poin r charge 2 A pair of posi rive charges 3 A pair of opposi re charges 4 A s rraigh r line wi rh uniform charge dis rribu rion Chapter 36 Geometric Optics 0 Images formed by flat mirrors 0 Images formed by spherical mirrors 0 Images formed by refraction 0 Thin Ienses Quiz 6 Extra credit HW on the web Images formed by flat mirrors See figures 361 and 362 Basic elements 0 Object 0 Flat mirror geometric optics 0 Image Major conclusions 0 Image distance q object distance p 0 Image height h object height h 0 Lateral magnification M h h 1 See Figure 36 2 for the de nitions of object distance p and image distance q Images formed by spherical mirrors Basic elements 0 Object o Spherical mirror convex or concave 0 Image See figures 3611 and 3613 Important concepts 0 Object distance p is the distance between the object and the optical surface for refraction or reflection 0 Image distance q is the distance between the image and the optical surface for refraction or reflection 0 Focal length f is the image distance of an object that is far away from the mirror See Figure 36 12 for the de nition of focal length Concave Mirrors 0 Concave mirrors are spherical mirrors with light reflected from the inner concave surface oThe focal length f R2 where R is the radius of the spherical mirror 0 Relations among p q and f 1 1 1 2 p q f o Magnification h39 0 p Convex Mirrors 0 Convex mirrors are spherical mirrors with light reflected from the outer convex surface oThe focal length f R2 where R is the radius of the spherical mirror 0 Relations among p q and f 1 1 1 2 p q f o Magnification h39 0 p Sign Conventions for Mirrors 0 p is positive if object is in front of mirror real object oq is positive if the image is real in front of mirror oq is negative if the image is virtual in back of mirror of and R are positive if center of curvature is in front of mirror of and R are negative if center of curvature is in back of mirror 0 M is positive image is upright o M is negative image is inverted Thin Lenses The focal length of a thin lens 1 r 1 L L f R1 R2 Converging lens convex lens oThe focal length fis positive if the lens is converging Diverging lens concave lens oThe focal length fis negative if the lens is diverging See figure 3624 for definitions of the object focal point and image focal point Ray Diagrams for Thin Lenses To find the image of an object due to a lens one draws three rays see Fig 3627 Ray 1 parallel to the principle axis before the lens then refracted and passing the focal image point Ray 2 a straight line from the object through the center of the lens and continue to the image Ray 3 from the object passing the object focal point and then refracted to be parallel to the principle axis A Image Object Ray Ray 1 Ray 3

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