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# INTRO ELTRCL SCIENCE ENSC 2613

OK State

GPA 3.78

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This 0 page Class Notes was uploaded by Ms. Abe Bernier on Sunday November 1, 2015. The Class Notes belongs to ENSC 2613 at Oklahoma State University taught by Staff in Fall. Since its upload, it has received 26 views. For similar materials see /class/232956/ensc-2613-oklahoma-state-university in Engineering & Applied Science at Oklahoma State University.

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Date Created: 11/01/15

314 Chapter 6 Electrical Theory Practice Problems If you attempt only a few select those with a star DC Cil CUitS 61 For the circuit below with voltages polarities as shown KVL in equation form is a v1vz 223 v4 215 0 b vl 222 223 v4 225 O c v1vgv3 v 050 d Ul 3902 23 124 vs0 62 Find 11 in amps a 12 b 15 c 18 d 21 63 Find the magnitude and sign of the power in watts absorbed by the circuit element in the box a 20 2 A 3 Q b 8 8 2m I 64 For the circuit shown the voltage across the 4 ohm resistor is with v 1 V a 1X4 b 1 2 c23 v 4 1 d2 SQ 65 The total conductance in mhos in the circuit shown below is a 1 5 b 1 2 C 2 1 Q 2 Q d5 239 252 Electrical TheoryPractice Problems 315 The voltage across the 5 ohm resistor in the circuit shown is I39 a 10 15 V 6 V 3 b 25 c 30 d 583 will quotquot7quot The power delivered to the 5 ohm resistor is a 15 b 215 c 285 d 32 The power in watts absorbed by the 6 mho conductance in the circuit be low is a 024 b 02 c 024 2 A 6 mho 4 mho d 048 The equivalent resistance in ohms between points a and b in the circuit be low is a 3 4 2 b 5 c 7 d 8 The voltage V 2 is a 64 b 40 2 A 1 A 020 0 o d 56 Find 1 in amperes a 40 b 20 c 411 0 0 M d 211 316 Chapter 6 Electrica1 Theory AC Circuits Single Phase 612 613 614 615 616 617 2j2 3 j4 is most nearly a 605 218 3 b 141 218 C 141 810 d 280 81 The following sinusoid is displayed on an oscillo scope The RMS voltage and the radian frequency are most nearly a 1 833 b 07071 5236 c 14142 5236 1 2 833 1 1 20 ms Find I in amperes a O29j068 b O12j069 c O82 j037 d 1 j2 5018 105 V 102 j20 502 7 20 Calculate the magnitude of the node voltage V148 a 851 b 772 c 688 d 922 2015 0 A The DC average current through the j 40 ohm inductor is 309 7209 j40 2 501 volts a 03 A b 05 A C 08 A d 12 A The rms current through the j 40 ohm inductor of Problem 61613 2 05 A b 093 A c 158 A d 211 A 80 90 V 401i Electrical Theory Practice Problems 317 618 The current through the capacitor is a 021 A 1030 amps 7100 b 057 A q 5 a c 10 A j 200 d 485 A 619 The voltage across the 5 ohm resistor of Problem 618 is a 050 V b 161 V c 206 V d 485 V 620 The peak value of Vt in the circuit shown is approximately a 20 Xi 10 c s 100 b 368 O c 259 d 500 Vft 8 5 Q 3300 in 621 The power factor of the circuit shown is most nearly a 05 b 06 4 Q c 07 d 08 3 622 What value of a will make the ms of Isl a minimum in the circuit shown L 8 x 1010 Hemies T 50 Q L 6 a 1414sinwt 15 i C 2 x 1039 Farad a 2 x106 b 8 x106 2 25 x106 d50 x106 623 What is the rms magnitude of the minimum source current in the circuit of Problem 622 a 10 b 15 c 20 d 25 624 For the circuit shown the value of capacitance C that will give a power fac tor of 10 is most nearly a 00173 139 10 cos 50 b 00519 C 00938 7 001 H 10 Q d 00393 C 318 Chapter 6 Electrical Theory 625 For maximum power dissipation in the load of the circuit shown R in ohms and L in Halli henna should be chosen as a 26 50 lt b 20 100 100m c 20 50 209 if R 125 100 12 K m 100 rads 100W L 39 LOAD AC Circuits 626 Calculate the total average power in watts dissipated in the balanced three Three Phase phase load a 2507 A b 5276 39 03456 a 6 Z10j5 d 978 VAC z 120 v c B 627 The value of the line current 1M in the balanced Y connected system shown is most nearly a 20613 b 353443 c 353145 d 151143 628 For a balanced Y connected system identify the incorrect statement a VPH g VL b IL 1m c Ptoml 3PPH d All phase impedances are equal 629 A 100 JP capacitor has ICU The capacitor voltage VCR at t 25 seconds 170 10 V is most nearly a 24 C 25 10 20 t d 26 la Electrical TheoryPractice Problems 319 630 The voltage across a 10 HF capacitor is 50t2 V The time in seconds it will take to store 200 I of energy is most nearly a 015 b 021 c 138 d 1125 our 139 631 The value of the voltage across C at t 30 X 1065 if the switch is closed at t 0 is 5 son a 351 l l quot V i 106 F b 451 10V C 7 i c 546 quot i d 632 632 How long in microseconds does it take for the current to reach half its fi nal value if the switch is closed at t O a 31 5 209 b 47 C 5 2 T 10 V 150 x 10396 H d 73 c 633 The electric flux passing out through a closed surface is equal to Electric Fied5 a the line integral of the current around the surface b zero c the flux density at the surface d the total charge enclosed by the surface 634 The direction of the force acting on a moving charge placed in a magnetic field is a perpendicular to the magnetic field 13 opposite to the direction of motion of the charge c along the direction of the magnetic eld d along the direction of motion of the charge 635 Two infinitely long lines of charge are parallel to the zaxis and located as shown The force on an electron at 100 will be in the direction a x b x c y d y 636 A point charge of 2 X 10 7 C is located at the origin of coordinates A spherical shell with center at the origin and radius of 20 cm has a surface charge density 1 X 10 7 Cmz The electric flux density at r c 50 cm in Cm2 is a 318x 10 8 c 955x 10 8 b 796X10quot8 a 1114x 10quot8 320 Chapter Electrical Theory 637 A uniform line charge of pl 30 nC m lies along the zaxis The flux den sity 3 at 345 is a 191 x 10quot10 c 11 94 x 10 1G b 9 55 x 10quotquot d 1592 x 10 10 638 An electric field in rectangular coordinates is given by E 43 4xy Vm The voltage drop from 111 to 511 is a 12 b 12 c 16 d 16 639 Static electric eld distributions refer to cases where a all time derivatives of field quantities are zero b the time derivatives of the displacement current are not zero c the electric fields vary with time d the electric scalar potential is twodimensional 640 A point charge of 50 X 10 9 C is placed 10 cm above a perfectly conducting infinitely large flat ground plane What is the voltage 5 cm above the ground with respect to zero volts on the ground a 3000 b 4000 c 5000 d 6000 641 Two long straight conductors located at 032 and 0 3z each carry 5 amperes in the same direction distances are in meters The magnitude of Magnetic Fields magnetic field intensity at 400 is a 12 13 253 C 3575 1 457 642 A solenoid has 1000 turns and carries a current of 5 amperes If L 50 cm and r6 25 cm what is the magnetic field intensity on the solenoid axis at the center of the solenoid a 10 b 2 x 105 c s x 10 d 105 643 The inductor shown has an inductance of 4 mII In order to increase the inductance to 40 mH a increase the current by 10 b increase the mean flux path length by 10 c increase the number of turns to 10 N 1 increase the cross sectional area of the iron by 10 UUL I gt c N r 644 An iron ring with a mean diameter of 20 cm is wound with a coil of 200 turns The permeability of the iron is 4739 x 10 4 Hm A current of 005 A is passed through the coil The magnetic flux density in the iron in Wf m is a 002 b 0012 c 1007 d 7r Electrical Theory Practice Problems 321 645 An iron core is shown The relative permeability of the iron is 4000 The re luctance in 114 of the magnetic circuit shown is a 17rx10 8 mm b 1422x10395 86m 2147rx10 8 8cm 10 d1167gtlt10 8 Average crosssection in 0009 m2 646 If the desired DC load voltage is 9 volts what is the rms value of Diodes the source a 41 b b 127 c 200 a v 1009 d 283 647 If the source voltage in the circuit of Prob 646 is v 100 sin 377t the peak reverse v01tage applied to the diode would be a 25 b 100 c 1414 d 318 648 If Rt 600 Q What must be the rms value of the sinusoidal voltage 22 if I 150 mA a 60 b 80 c 100 d 120 49 Calculate R in k9 so that Operational vovm 200 Ampli ers a 50 k 9 b 100 c 200 d 300 650 The gain of the following 1000 Q OP AMP circuit is a 02 b 12 c 4 d 5 322 Chapter 6 Electrical Theory 651 652 Given the voltages into the following OP AMP network the output voltage is 30 392 10000 b 4 C 7 4009 d 10 5002 2 v v 1 v 0 n g The OPAMP circuit below performs the function of a amplification b integration 3 differentiation d summing An OPAMP integrator is used to integrate the square wave shown What must be the C2x 1039613 value of R to make the peak R value of the triangular wave Um 00 equal 150 volts a 10 000 ohms 10 b 16 667 ohms t C 25 000 ohms vm 1 2 3 4 t d 33 333 ohms 10 vol 1 2 3 4 z

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