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Week 10- S7 AND S8

by: Hayley Lecker

Week 10- S7 AND S8 CHEM 2325 - 001

Hayley Lecker
GPA 3.42

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About this Document

It goes over the homeworks for the week, all complete.
Organic Chemistry - 12551
James Salvador
Class Notes
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This 11 page Class Notes was uploaded by Hayley Lecker on Saturday March 26, 2016. The Class Notes belongs to CHEM 2325 - 001 at University of Texas at El Paso taught by James Salvador in Fall 2015. Since its upload, it has received 58 views.

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Date Created: 03/26/16
OrganicChemistry 2Week 10 Important Information: Professor’s Email: Class Website: Class Code (E-book): utep2325spring2016 Includes examples of the Homework! Posted the week before the homework’s are due to help everyone get 100’s! S7 The first step adds a methyl so the benzene ring and water is the by product. In the second step sulfuric acid is added para to the methyl group, this is sulfur with two doubled bonded oxygens and one OH group. In the third step, a nitrogen group is added ortho, like many of the other synthesis this will be removed. Before the nitrogen group is removed, the sulfur is removed first. If the sulfur wasn’t added, the nitrogen group would have gone para instead. Now the nitrogen group is converted to NH2. As in other synthesizes a diazonium is made, this is great for being able to put other groups on. This is converted to an alcohol in this step. Now look closely Cl likes to add ortho, para. Since the OH group is better than a methyl it goes para to that. In this step the alcohol is converted to O-Na. Finally the carboxylic acid can be added on. S8 In this step a t-butyl group is added to the benzene ring. The next progression a methanol group is added para to the t-butyl group. The alcohol is removed and replaced by Cl. Now this is where it gets messy, the Cl is removed and the HUGE group you see below is what replaces it. In this step, the long chain above loses four carbons at the ether positions, and those oxygens are in ionic state. Now, they are converted to alcohols. The second part of the carboxylic acid is removed. Now this seems backwards but the alcohol is reconverted to the ether. Now the double bonded oxygen is converted to an alcohol, and the oxygen above that was sandwich between two carbons was removed. This is where another ring is formed, as you can see below all the oxygens are removed. In the final step, a ketone is added.


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